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A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls involve fax messages, and consider a sample of 25 incoming calls. What is the probability that

a. At most 6 of the calls involve a fax message?

b. Exactly 6 of the calls involve a fax message?

c. At least 6 of the calls involve a fax message?

d. More than 6 of the calls involve a fax message?

Short Answer

Expert verified

a) The probability of given condition is \(B(6;25,0.25) = P(X \le 6)\mathop = \limits^{(1)} 0.5611\).

b) The probability of given condition is \({0.25^6}{(1 - 0.25)^{25 - 6}} = 0.1828\)

c) The probability of given condition is \(0.6217.\)

d) The probability of given condition is \(\{ X > 6\} \) is event \(\{ X \le 6\} \).

Step by step solution

01

Definition of probability

Probability denotes the possibility of something happening. It's a field of mathematics that studies the probability of a random event occurring.

02

Step 2: What is the probability that most 6 of the calls involve a fax message

a)

Let

\(X = \)number of incoming calls that involve fax messages.

Since \(25\% \) of the incoming calls involve fax messages, \(p = 0.25\) and there are \(n = 25\) incoming calls. Therefore, \(X\sim Bin(25,0,25\)) (Binomial Distribution).

(a):

Cumulative Density Function cdf of binomial random variable X with parameters n and p is

\(\begin{array}{c}B(x;n,p) = P(X \le x)\\ = \sum\limits_{y = 0}^x b (y;n,p),\;\;\;\\x = 0,1, \ldots ,n.\end{array}\)

Therefore, the following is true

\(\begin{array}{c}B(6;25,0.25) = P(X \le 6)\\\mathop = \limits^{(1)} 0.5611.\end{array}\)

Therefore, the value can be found in Appendix Table A.l. (column " \(0.25\)鈥 and row " 6".

03

Step 3: What is the probability that 6 of the calls involve a fax message

b)

Theorem:

\(b(x;n,p) = \left\{ {\begin{array}{*{20}{l}}{\left( {\begin{array}{*{20}{l}}n\\x\end{array}} \right){p^x}{{(1 - p)}^{n - x}}}&{,x = 0,1,2, \ldots ,n}\\0&{\rm{ }}\end{array}} \right.\)

The following is correct

\(\begin{array}{c}P(X = 6)\\ = b(6;25,0.25)\\ = 256\end{array}\)

Therefore, \({0.25^6}{(1 - 0.25)^{25 - 6}} = 0.1828.\)

04

Step 4: What is the probability that at least 6 of the calls involve a fax message

c)

The following holds

\(\begin{array}{c}P(X \ge 6)\mathop = \limits^{(1)} 1\\ - P(X < 6)\mathop = \limits^{(2)} 1\\ - P(X \le 5) = 1\\ - B(5;25,0.25)\mathop = \limits^{(3)} 1\\ - 0.3783 = 0.6217.\end{array}\)

Complement of event\(\{ X \ge 6\} \)is event\(\{ X < 6\} \);

X takes only non-negative values;

As a result, the value is in Appendix Table A.l. (column " \({0.25^\circ }\)and row "5").

05

Step 5: What is the probability that More than 6 of the calls involve a fax message

d)

The following is true

\(\begin{array}{c}P(X > 6)\mathop = \limits^{(1)} 1 - P\\(X \le 6) = 1 - 0.5611\\ = 0.4389\end{array}\)

Therefore, complement of event \(\{ X > 6\} \)is event \(\{ X \le 6\} \).

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