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A manufacturer of integrated circuit chips wishes to control the quality of its product by rejecting any batch in which the proportion of defective chips is too high. To this end, out of each batch (10,000 chips), 25 will be selected and tested. If at least 5 of these 25 are defective, the entire batch will be rejected.

a. What is the probability that a batch will be rejected if 5% of the chips in the batch are in fact defective?

b. Answer the question posed in (a) if the percentage of defective chips in the batch is \({\bf{10}}\% \).

c. Answer the question posed in (a) if the percentage of defective chips in the batch is \({\bf{20}}\% \).

d. What happens to the probabilities in (a)鈥(c) if the critical rejection number is increased from 5 to \({\bf{6}}\)?

Short Answer

Expert verified

(a) The probability is \(P(X \ge 5) = 0.007\).

(b) The percentage of defective chips in the batch is \(10\% \)is \(P(X \ge 5) = 0.098\).

(c) The percentage of defective chips in the batch is \(20\% \)is \(P(X \ge 5) = 0.579\).

(d) If the critical rejection number is increased from 5 to \(6\), So The probabilities would decrease.

Step by step solution

01

Concept Introduction

Probability is the likelihood that an event will occur and is calculated by dividing the number of favourable outcomes by the total number of possible outcomes. The simplest example is a coin flip. When you flip a coin there are only two possible outcomes, the result is either heads or tails.

02

Determine the probability

(a)

The second parameter of the specified Binomial Distribution is \({\bf{p}}\)in this example

\(p = 0.05\)

If at least \(5\) out of \(25\) chips are damaged, the entire batch will be rejected; thus, the requested probability is

\(P(X \ge 5) = 1 - B(4;25,0.05) = 1 - 0.993\)

\({\rm{ = 0}}{\rm{.007}}\)

Hence, the probability is \(P(X \ge 5) = 0.007\).

03

Determine the percentage of defective chips

(b)

The second parameter of the specified Binomial Distribution is \(p\)in this example.

\(p = 0.1\)

If at least 5 out of 25 chips are damaged, the entire batch will be rejected; thus, the requested probability is

\(P(X \ge 5) = {\rm{ }}1 - B(4;25,0.1) = 1 - 0.902\)

=0.098

Therefore, the percentage of defective chips in the batch is \(10\% \)is \(P(X \ge 5) = 0.098\).

04

Determine the percentage of defective chips

(c)

The second parameter of the specified Binomial Distribution is \({\bf{p}}\)in this example.

\(p = 0.2\)

If at least \(5\) out of \(25\) chips are damaged, the entire batch will be rejected; thus, the requested probability is

\(P(X \ge 5) = 1 - B(4;25,0.2) = 1 - 0.421\)

\({\rm{ = 0}}{\rm{.579}}\)

Thus, the percentage of defective chips in the batch is \(20\% \)is \(P(X \ge 5) = 0.579\).

05

Determine the probability

(d)

The possibilities would dwindle (look at the Cumulative Density Function - sum of positive numbers).

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