Chapter 6: Q5E (page 358)
How large a random sample must be taken from a given distribution in order for the probability to be at least 0.99 that the sample mean will be within 2 standard deviations of the mean of the distribution?
Short Answer
25
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 6: Q5E (page 358)
How large a random sample must be taken from a given distribution in order for the probability to be at least 0.99 that the sample mean will be within 2 standard deviations of the mean of the distribution?
25
All the tools & learning materials you need for study success - in one app.
Get started for free
Suppose that \({{\bf{X}}_{\bf{1}}}{\bf{,}}...{\bf{,}}{{\bf{X}}_{\bf{n}}}\) form a random sample from a normal distribution with unknown mean θ and variance \({{\bf{\sigma }}^{\bf{2}}}\). Assuming that \({\bf{\theta }} \ne {\bf{0}}\) , determine the asymptotic distribution of \({{\bf{\bar X}}_{\bf{n}}}^{\bf{3}}\)
Let \({\overline X _n}\)be the sample mean of a random sample of size n from a distribution for which the mean is μand the variance is \({\sigma ^2}\), where \({\sigma ^2} < \infty \).
Show that \({\overline X _n}\)converges to μ in quadratic mean as \(n \to \infty \).
Prove that the sequence of random variables Zn in Exercise 22 converges in quadratic mean (definition in Exercise 10) to 0.
Let X be a random variable for which \({\bf{E}}\left( {\bf{X}} \right){\bf{ = \mu }}\)and\({\bf{Var}}\left( {\bf{X}} \right){\bf{ = }}{{\bf{\sigma }}^{\bf{2}}}\).Construct a probability distribution for X such that \({\bf{P}}\left( {\left| {{\bf{X - \mu }}} \right| \ge {\bf{3\sigma }}} \right){\bf{ = }}\frac{{\bf{1}}}{{\bf{9}}}\)
Let\({{\bf{X}}_{\bf{n}}}\)be a random variable having the binomial distribution with parameters n and\({{\bf{p}}_{\bf{n}}}\). Assume that\(\mathop {{\bf{lim}}}\limits_{{\bf{n}} \to \infty } \,\,{\bf{n}}{{\bf{p}}_{\bf{n}}}{\bf{ = \lambda }}\). Prove that the m.g.f. of\({{\bf{X}}_{\bf{n}}}\)converges to the m.g.f. of the Poisson distribution with mean λ.
What do you think about this solution?
We value your feedback to improve our textbook solutions.