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Suppose that \({{\bf{X}}_{\bf{1}}}{\bf{,}}...{\bf{,}}{{\bf{X}}_{\bf{n}}}\) form a random sample from a normal distribution with unknown mean θ and variance \({{\bf{\sigma }}^{\bf{2}}}\). Assuming that \({\bf{\theta }} \ne {\bf{0}}\) , determine the asymptotic distribution of \({{\bf{\bar X}}_{\bf{n}}}^{\bf{3}}\)

Short Answer

Expert verified

The asymptotic distribution of \({\bar X_n}^3\) is follows a normal distribution with mean \({\theta ^3}\) and variance \(\frac{{9{\theta ^4}{\sigma ^2}}}{n}\)

Step by step solution

01

Given information

\({X_1},...,{X_n}\) a random sample from a normal distribution with unknown mean \(\theta \) and variance \({\sigma ^2}\)

02

Finding the asymptotic distribution

The asymptotic distribution of\(g\left( {{{\bar X}_n}} \right)\)

Where,

\(g\left( x \right) = {x^3}\)

The distribution\({\bar X_n}\)is normally distributed with mean\(\theta \)and variance\(\frac{{{\sigma ^2}}}{n}\)

According to the delta method,

The asymptotic distribution of\(g\left( {{{\bar X}_n}} \right)\)should be the normal distribution with the mean,

\(g\left( \theta \right) = {\theta ^3}\)

The variance is,

\(\begin{array}{c}Variance = \left( {\frac{{{\sigma ^2}}}{n}} \right){\left[ {g'\left( \theta \right)} \right]^2}\\ = \frac{{9{\theta ^4}{\sigma ^2}}}{n}\end{array}\)

Therefore, the asymptotic distribution of\({\bar X_n}^3\)is follows a normal distribution with mean\({\theta ^3}\)and variance\(\frac{{9{\theta ^4}{\sigma ^2}}}{n}\)

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Most popular questions from this chapter

Suppose that X is a random variable for which E(X) = μ and \({\bf{E}}\left[ {{{\left( {{\bf{X - \mu }}} \right)}^{\bf{4}}}} \right]{\bf{ = }}{{\bf{\beta }}^{\bf{4}}}\) Prove that

\({\bf{P}}\left( {\left| {{\bf{X - \mu }}} \right| \ge {\bf{t}}} \right) \le \frac{{{{\bf{\beta }}_{\bf{4}}}}}{{{{\bf{t}}^{\bf{4}}}}}\)

A random sample of n items is to be taken from a distribution with mean μ and standard deviation σ.

a. Use the Chebyshev inequality to determine the smallest number of items n that must be taken to satisfy the following relation:

\({\bf{Pr}}\left( {\left| {{{{\bf{\bar X}}}_{\bf{n}}}{\bf{ - \mu }}} \right| \le \frac{{\bf{\sigma }}}{{\bf{4}}}} \right) \ge {\bf{0}}{\bf{.99}}\)

b. Use the central limit theorem to determine the smallest number of items n that must be taken to satisfy the relation in part (a) approximately

Suppose that the proportion of defective items in a large manufactured lot is 0.1. What is the smallest random sample of items that must be taken from the lot in order for the probability to be at least 0.99 that the proportion of defective items in the sample will be less than 0.13?

Suppose that the number of minutes required to serve a customer at the checkout counter of a supermarket has an exponential distribution for which the mean is 3. Using the central limit theorem, approximate the probability that the total time required to serve a random sample of 16 customers will exceed one hour.

Suppose that \({X_1},...,{X_n}\)form a random sample of size n from a distribution for which the mean is 6.5 and the variance is 4. Determine how large the value of n must be in order for the following relation to be satisfied:

\({\bf{P}}\left( {{\bf{6}} \le {{{\bf{\bar X}}}_{\bf{n}}} \le {\bf{7}}} \right) \ge {\bf{0}}{\bf{.8}}\)

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