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Let\({{\bf{X}}_{\bf{n}}}\)be a random variable having the binomial distribution with parameters n and\({{\bf{p}}_{\bf{n}}}\). Assume that\(\mathop {{\bf{lim}}}\limits_{{\bf{n}} \to \infty } \,\,{\bf{n}}{{\bf{p}}_{\bf{n}}}{\bf{ = \lambda }}\). Prove that the m.g.f. of\({{\bf{X}}_{\bf{n}}}\)converges to the m.g.f. of the Poisson distribution with mean λ.

Short Answer

Expert verified

Proved. the m.g.f. of \({X_n}\) converges to the m.g.f. of the Poisson distribution with mean \(\lambda \)

Step by step solution

01

Given information

Let \({X_n}\)be a random variable having a binomial distribution with parameters n and \({p_n}\)

02

Proved part

The m.g.f. of the binomial distribution with parameters n and\({p_n}\)is,

\({\psi _n}\left( t \right) = {\left( {{p_n}\exp \left( t \right) + 1 - {p_n}} \right)^n}\)

If,\(n{p_n} \to \lambda \)

\(\mathop {\lim }\limits_{n \to \infty } \,{\psi _n}\left( t \right) = \mathop {\lim }\limits_{n \to \infty } \,\,{\left( {1 + \frac{{n{p_n}}}{n}\left[ {\exp \left( t \right) - 1} \right]} \right)^n}\)

This converges to\(\exp \left( {\lambda \left[ {{e^t} - 1} \right]} \right)\), which is the m.g.f of the Poisson distribution with mean\(\lambda \)

Hence, the m.g.f. of \({X_n}\) converges to the m.g.f. of the Poisson distribution with mean \(\lambda \)……[Proved]

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Most popular questions from this chapter

It is said that a sequence of random variables\({Z_1},{Z_2},...\)converges to a constant b in quadratic mean if

\(\mathop {\lim }\limits_{n \to \infty } E\left[ {{{\left( {{Z_n} - b} \right)}^2}} \right] = 0\). (6.2.17)

Show that Eq. (6.2.17) is satisfied if and only if\(\mathop {\lim }\limits_{n \to \infty } E\left( {{Z_n}} \right) = b\)and\(\mathop {\lim }\limits_{x \to \infty } V\left( {{Z_n}} \right) = 0\).

Let f be a p.f. for a discrete distribution. Suppose that\(f\left( x \right) = 0\)for \(x \notin \left[ {0,1} \right]\). Prove that the variance of this distribution is at most\(\frac{1}{4}\). Hint: Prove that there is a distribution supported on just the two points\(\left\{ {0,1} \right\}\)with variance at least as large as f, and then prove that the variance of distribution supported on\(\left\{ {0,1} \right\}\)is at most\(\frac{1}{4}\).

How large a random sample must be taken from a given distribution in order for the probability to be at least 0.99 that the sample mean will be within 2 standard deviations of the mean of the distribution?

Using the correction for continuity, determine the probability required in Exercise 7 of Sec. 6.3.

Let \({X_1},{X_2},...\)be a sequence of i.i.d. random variables having the exponential distribution with parameter 1. Let \({Y_n} = \sum\limits_{i = 1}^n {{X_i}} \)for each \(n = 1,2,...\)

a. For each\(u > 1\), compute the Chernoff bound on \(\Pr \left( {{Y_n} > nu} \right)\).

b. What goes wrong if we try to compute the Chernoff bound when\(u < 1\).

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