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Write the exponential equation in logarithmic form. For example, the logarithmic form of \(2^{3}=8\) is log \(_{2} 8=3\) \(24^{0}=1\)

Short Answer

Expert verified
The logarithmic form of \(24^{0}=1\) is log \(_{24} 1 = 0\)

Step by step solution

01

Identify the variables

We identify the base, exponent and value in \(24^{0}=1\). The base \(b\) is 24, the exponent \(x\) is 0 and the output \(y\) equals 1.
02

Apply the Logarithmic form

We apply the logarithmic form which is log \(_{b} y = x\). Considering the identified variables, we apply this to our equation and get log \(_{24} 1 = 0\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Equations
Exponential equations are mathematical expressions where a constant base is raised to a variable exponent. For example, in the equation \(2^3 = 8\), the number 2 is raised to the power of 3, resulting in 8. Exponential equations are key in representing growth processes, such as populations or interest rates, where amounts double over fixed intervals.
In math, the general form of an exponential equation is:\[ b^x = y \]
where:
  • \(b\) is the base
  • \(x\) is the exponent
  • \(y\) is the result of the base raised to the power of the exponent
Understanding exponential equations allows us to see how changes in the exponent can rapidly impact the outcome. When the exponent is zero, as in the case of \(24^0 = 1\), the rule that any non-zero number raised to the power of zero is 1, is demonstrated.
Logarithm Conversion
Logarithmic conversion is a vital mathematical process that allows us to express exponential equations in terms of logarithms. Remember that a logarithm is the inverse of an exponential function. So, if you have an exponential equation like \(b^x = y\), the equivalent logarithmic form would be \( \log_{b} y = x \).
This conversion reverses the operations of the original equation, allowing us to solve for encumbered values or verify results more conveniently. Converting exponential equations to logarithms is especially useful in solving problems where you need to find out the exponent, like in our exercise with \(24^0 = 1\). When rewritten in logarithmic form, it becomes \( \log_{24} 1 = 0 \), making it clear and straightforward that the exponent must be 0 to get a result of 1.
Base and Exponent Identification
In any exponential equation, the first step is to clearly identify the different components: the base and the exponent. These form the backbone of both exponential and logarithmic equations.
For instance, in \(24^0 = 1\):
  • Base \(b\): This is the number that is being repeatedly multiplied. In our example, the base is 24.
  • Exponent \(x\): This shows how many times the base is used in multiplication. In this instance, it’s 0, leading to a special case where any number (except 0) raised to the power of 0 equals 1.
  • Result \(y\): This is the quantity resulting from raising the base to the exponent. Here, it is 1.
Accurate identification of these components helps in both forming and solving exponential equations, and it's crucial when changing the equation to logarithmic form. This will enable seamless translation between the two forms, enhancing understanding and problem-solving capabilities.

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Most popular questions from this chapter

True or False? In Exercises \(97-102,\) determine whether the statement is true or false given that \(f(x)=\ln x .\) Justify your answer. $$f(a x)=f(a)+f(x), \quad a>0, \quad x>0$$

Graphical Analysis Use a graphing utility to graph the functions \(y_{1}=\ln x-\ln (x-3)\) and \(y_{2}=\ln \frac{x}{x-3}\) in the same viewing window. Does the graphing utility show the functions with the same domain? If so, should it? Explain your reasoning.

Comparing Models A cup of water at an initial temperature of \(78^{\circ} \mathrm{C}\) is placed in a room at a constant temperature of \(21^{\circ} \mathrm{C} .\) The temperature of the water is measured every 5 minutes during a half-hour period. The results are recorded as ordered pairs of the form \((t, T),\) where \(t\) is the time (in minutes) and \(T\) is the temperature (in degrees Celsius). $$ \begin{array}{l}{\left(0,78.0^{\circ}\right),\left(5,66.0^{\circ}\right),\left(10,57.5^{\circ}\right),\left(15,51.2^{\circ}\right)} \\\ {\left(20,46.3^{\circ}\right),\left(25,42.4^{\circ}\right),\left(30,39.6^{\circ}\right)}\end{array} $$ (a) The graph of the model for the data should be asymptotic with the graph of the temperature of the room. Subtract the room temperature from each of the temperatures in the ordered pairs. Use a graphing utility to plot the data points \((t, T)\) and \((t, T-21)\) . (b) An exponential model for the data \((t, T-21)\) is given by \(T-21=54.4(0.964)^{t} .\) Solve for \(T\) and graph the model. Compare the result with the plot of the original data. (c) Take the natural logarithms of the revised temperatures. Use the graphing utility to plot the points \((t, \ln (T-21))\) and observe that the points appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. This rasulting line has the form \(\ln (T-21)=a t+b\) . Solve for \(T,\) and verify that the result is equivalent to the model in part (b). (d) Fit a rational model to the data. Take the reciprocals of the \(y\) -coordinates of the revised data points to generate the points $$ \left(t, \frac{1}{T-21}\right) $$ Use the graphing utility to graph these points and observe that they appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. The resulting line has the form $$ \frac{1}{T-21}=a t+b $$ Solve for \(T,\) and use the graphing utility to graph the rational function and the original data points. (e) Why did taking the logarithms of the temperatures lead to a linear scatter plot? Why did taking the reciprocals of the temperatures lead to a linear scatter plot?

Condensing a Logarithmic Expression In Exercises \(67-82\) , condense the expression to the logarithm of a single quantity. $$\frac{1}{2}\left[\log _{4}(x+1)+2 \log _{4}(x-1)\right]+6 \log _{4} x$$

Expanding a Logarithmic Expression In Exercises \(37-58\) , use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\ln x y z^{2}$$

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