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Using the Change-of-Base Formula In Exercises \(11-14,\) evaluate the logarithm using the change-of-base formula. Round your result to three decimal places. $$\log _{3} 0.015$$

Short Answer

Expert verified
-3.820

Step by step solution

01

Apply the Change-of-Base Formula

We start by transforming the expression using the change-of-base formula. \(\log_{b} a = \frac{\log a}{\log b}\). Here, we have a base of 3 (\(b=3\)) and a = 0.015. Thus, applying the formula we get: \( = \frac{\log 0.015}{\log 3} \)
02

Compute the Logs

Next, we calculate the log of 0.015 and the log of 3 using a calculator, making sure that we are calculating the logs to base 10: \(= \frac{-1.82390874094}{0.47712125472}\)
03

Divide and Round to Three Decimal Places

Finally, we divide the two log values and round the result to three decimal places: \(-3.820\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Logarithmic Functions
Logarithms are an essential concept in mathematics, particularly in algebra and calculus. A logarithmic function is the inverse of an exponential function. In simpler terms, if you have an equation such as y = b^x, where b is the base and x is the exponent, the logarithmic form would be x = log_b(y). This equation literally means 'what power must we raise b to, in order to get y?'.

For example, the logarithm base 2 of 8 is 3, since 2^3 = 8. Hence, log_2(8) = 3. Logarithms are particularly useful for solving equations where the unknown is an exponent, and they also play an important role in areas such as scientific notation, musical scales, and information theory.

When dealing with logarithms, remember these key properties:
  • The base b must always be greater than 0 and not equal to 1.
  • The argument (the number you are taking the log of) must always be positive.
  • Logarithms can be added, subtracted, and even converted to different bases using various logarithmic identities.
Understanding these properties helps in effectively evaluating and manipulating logarithmic expressions.
Exponential Functions
An exponential function takes the form f(x) = b^x, where b is the base and is a constant. Exponential functions show how quantities grow exponentially – that is, by a constant factor over equal successive intervals. One quintessential example of an exponential function is compound interest in finance, where money grows at a certain rate over time.

These functions are characterized by their rapid increase or decrease at an accelerating rate, indicating that the growth or decay rate is proportional to the current value. This concept is opposite in some ways to logarithms because while logarithms give us the exponent, the exponential function gives us the value of the quantity when it's been subjected to exponential growth.

For anything you are working on which involves growth, decay, or rapid change, understanding exponential functions is key. They allow us to model real-world situations like population growth, radioactive decay, and even how pandemics spread, which makes them incredibly useful and widely applicable.
Logarithm Evaluation Using Change-of-Base Formula
Evaluating logarithms directly can be challenging if the base is not a standard value such as 10 or e (the natural logarithm base). That's where the change-of-base formula comes in handy. The formula states that for any logarithm log_b(a), you can change the base to one that is more amenable to computation, such as base 10 or base e, using this identity: log_b(a) = log_c(a) / log_c(b), where c is the new base you're converting to.

In our exercise, we evaluated log_3(0.015) by changing the base to 10, making it easier to compute with a calculator. It's important to remember that you can use any base for c as long as it is positive and not equal to 1. However, it's most practical to use base 10 or base e because they are commonly supported on calculators. This formula essentially breaks the problem down into a division of two simpler logarithms, which can be directly solved using standard calculator functions.

Another tip is to be attentive to the precision required in the answer. In many cases, such as in our exercise, it's important to round to a certain number of decimal places. Precision matters in scientific and academic work, so make sure you follow directions carefully for rounding.

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Most popular questions from this chapter

Expanding a Logarithmic Expression In Exercises \(37-58,\) use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\ln \sqrt{z}$$

Comparing Models A cup of water at an initial temperature of \(78^{\circ} \mathrm{C}\) is placed in a room at a constant temperature of \(21^{\circ} \mathrm{C} .\) The temperature of the water is measured every 5 minutes during a half-hour period. The results are recorded as ordered pairs of the form \((t, T),\) where \(t\) is the time (in minutes) and \(T\) is the temperature (in degrees Celsius). $$ \begin{array}{l}{\left(0,78.0^{\circ}\right),\left(5,66.0^{\circ}\right),\left(10,57.5^{\circ}\right),\left(15,51.2^{\circ}\right)} \\\ {\left(20,46.3^{\circ}\right),\left(25,42.4^{\circ}\right),\left(30,39.6^{\circ}\right)}\end{array} $$ (a) The graph of the model for the data should be asymptotic with the graph of the temperature of the room. Subtract the room temperature from each of the temperatures in the ordered pairs. Use a graphing utility to plot the data points \((t, T)\) and \((t, T-21)\) . (b) An exponential model for the data \((t, T-21)\) is given by \(T-21=54.4(0.964)^{t} .\) Solve for \(T\) and graph the model. Compare the result with the plot of the original data. (c) Take the natural logarithms of the revised temperatures. Use the graphing utility to plot the points \((t, \ln (T-21))\) and observe that the points appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. This rasulting line has the form \(\ln (T-21)=a t+b\) . Solve for \(T,\) and verify that the result is equivalent to the model in part (b). (d) Fit a rational model to the data. Take the reciprocals of the \(y\) -coordinates of the revised data points to generate the points $$ \left(t, \frac{1}{T-21}\right) $$ Use the graphing utility to graph these points and observe that they appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. The resulting line has the form $$ \frac{1}{T-21}=a t+b $$ Solve for \(T,\) and use the graphing utility to graph the rational function and the original data points. (e) Why did taking the logarithms of the temperatures lead to a linear scatter plot? Why did taking the reciprocals of the temperatures lead to a linear scatter plot?

Using the Change-of-Base Formula In Exercises \(11-14\) , evaluate the logarithm using the change-of-base formula. Round your result to three decimal places. $$\log _{1 / 2} 4$$

Compound Interest Use the formula \(A=P\left(1+\frac{r}{n}\right)^{n t}\) to calculate the balance of an investment when \(P=\$ 3000\) , \(r=6 \%,\) and \(t=10\) years, and compounding is done (a) by the day, (b) by the hour, (c) by the minute, and (d) by the second. Does increasing the number of compoundings per year result in unlimited growth of the balance? Explain.

Condensing a Logarithmic Expression In Exercises \(67-82\) , condense the expression to the logarithm of a single quantity. $$\ln x-[\ln (x+1)+\ln (x-1)]$$

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