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True or False? In Exercises \(97-102,\) determine whether the statement is true or false given that \(f(x)=\ln x .\) Justify your answer. $$f(a x)=f(a)+f(x), \quad a>0, \quad x>0$$

Short Answer

Expert verified
True. The statement \(f(ax)=f(a)+f(x)\) is true for the function \(f(x)=\ln x\).

Step by step solution

01

Consider the given function

The given function is \(f(x)=\ln x\). We are required to determine whether the statement \(f(ax)=f(a)+f(x)\) is true or false.
02

Evaluate f(ax)

From the given function, \(f(ax)=\ln(ax)\).
03

Use logarithmic identity

Applying the properties of logarithms, specifically the product rule, which states that the log of a product is equivalent to the sum of the logs, the expression can be rewritten as \(\ln(a) + \ln(x)\).
04

Comparing the two sides of the equation

Comparing this with the given equation, it aligns with \(f(a) + f(x)\) because \(f(a)=\ln a\) and \(f(x)=\ln x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Understanding the properties of logarithms is crucial when dealing with logarithmic functions. These properties are the backbone that allows algebraic manipulation and simplification of logarithmic expressions. One fundamental property is that the logarithm of a product of two positive numbers is the same as the sum of the logarithms of those numbers individually. This ties directly into the question from our exercise in which we compare whether the natural logarithm of a product, \(\ln(ax)\), can be represented as \(\ln(a) + \ln(x)\). The product rule for logarithms emerges as a convenient tool for proving this statement to be true. In understanding the properties, there are a few others that are quite useful:

  • The logarithm of a quotient is the difference of the logarithms: \( \ln(\frac{a}{b}) = \ln(a) - \ln(b) \).
  • The logarithm of a power is the product of the exponent and the logarithm: \( \ln(a^x) = x \cdot \ln(a) \).
  • The logarithm of the base itself is always 1: \( \ln(e) = 1 \), where \( e \) is the base of the natural logarithm.
  • The natural logarithm of 1 is zero: \( \ln(1) = 0 \).
These properties allow for flexibility in rewriting expressions and finding solutions to equations involving logarithms, making it easier to understand and solve logarithmic equations.
Natural Logarithm
The natural logarithm, represented as \(\ln(x)\), is a logarithm to the base \(e\), where \(e\) is an irrational and transcendental constant approximately equal to 2.71828. The natural logarithm arises in many areas of mathematics and is especially important in calculus due to its relationship with rates of growth and decay.

Its properties are reflected in the integral of reciprocal functions and it has a unique inverse relationship with the exponential function, which means that \(e^{\ln(x)} = x\) and \(\ln(e^x) = x\). Grasping this concept of the natural logarithm is crucial because it explains why the statement from our exercise \(f(ax) = f(a) + f(x)\) is true when \(f(x)\) is defined as the natural logarithm of \(x\). This underlines the connectivity between different mathematical functions and constants, showcasing the importance of the natural logarithm as a building block for more complex mathematical concepts.
Logarithm Product Rule
The logarithm product rule is a fundamental property that states the logarithm of a product is the sum of the logarithms of the factors. Formally, for any positive real numbers \(a\) and \(x\), the rule can be expressed as \(\ln(ax) = \ln(a) + \ln(x)\). This is the rule that is used in Step 3 of our exercise solution, enabling us to break down \(\ln(ax)\) into a more manageable form.

Applying this property can simplify complicated logarithmic expressions and is particularly useful for solving equations that involve the products of variables. In our exercise, we apply the product rule to prove that the natural logarithm of a product \(ax\) behaves in a way that it can be separated into the sum of the individual logarithms of \(a\) and \(x\), justified by the identity \(f(ax) = f(a) + f(x)\) for the given function \(f(x) = \ln(x)\). This rule, along with other properties of logarithms, is essential for students to understand as it forms the basis for working effectively with logarithmic equations in higher mathematics.

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Most popular questions from this chapter

Condensing a Logarithmic Expression In Exercises \(67-82\) , condense the expression to the logarithm of a single quantity. $$-4 \log _{6} 2 x$$

Expanding a Logarithmic Expression In Exercises \(37-58,\) use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\log 4 x^{2} y$$

Condensing a Logarithmic Expression In Exercises \(67-82\) , condense the expression to the logarithm of a single quantity. $$\frac{1}{2}\left[\log _{4}(x+1)+2 \log _{4}(x-1)\right]+6 \log _{4} x$$

Comparing Models A cup of water at an initial temperature of \(78^{\circ} \mathrm{C}\) is placed in a room at a constant temperature of \(21^{\circ} \mathrm{C} .\) The temperature of the water is measured every 5 minutes during a half-hour period. The results are recorded as ordered pairs of the form \((t, T),\) where \(t\) is the time (in minutes) and \(T\) is the temperature (in degrees Celsius). $$ \begin{array}{l}{\left(0,78.0^{\circ}\right),\left(5,66.0^{\circ}\right),\left(10,57.5^{\circ}\right),\left(15,51.2^{\circ}\right)} \\\ {\left(20,46.3^{\circ}\right),\left(25,42.4^{\circ}\right),\left(30,39.6^{\circ}\right)}\end{array} $$ (a) The graph of the model for the data should be asymptotic with the graph of the temperature of the room. Subtract the room temperature from each of the temperatures in the ordered pairs. Use a graphing utility to plot the data points \((t, T)\) and \((t, T-21)\) . (b) An exponential model for the data \((t, T-21)\) is given by \(T-21=54.4(0.964)^{t} .\) Solve for \(T\) and graph the model. Compare the result with the plot of the original data. (c) Take the natural logarithms of the revised temperatures. Use the graphing utility to plot the points \((t, \ln (T-21))\) and observe that the points appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. This rasulting line has the form \(\ln (T-21)=a t+b\) . Solve for \(T,\) and verify that the result is equivalent to the model in part (b). (d) Fit a rational model to the data. Take the reciprocals of the \(y\) -coordinates of the revised data points to generate the points $$ \left(t, \frac{1}{T-21}\right) $$ Use the graphing utility to graph these points and observe that they appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. The resulting line has the form $$ \frac{1}{T-21}=a t+b $$ Solve for \(T,\) and use the graphing utility to graph the rational function and the original data points. (e) Why did taking the logarithms of the temperatures lead to a linear scatter plot? Why did taking the reciprocals of the temperatures lead to a linear scatter plot?

Think About It Which functions are exponential? (a) 3\(x\) (b) 3\(x^{2}\) (c) \(3^{x}\) (d) \(2^{-x}\)

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