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Expanding a Logarithmic Expression In Exercises \(37-58\) , use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\ln x y z^{2}$$

Short Answer

Expert verified
The expanded form of \(\ln x y z^{2}\) is \(\ln(x) + \ln(y) + 2*\ln(z)\).

Step by step solution

01

Application of Product Rule

Firstly, apply the product rule, which states that the logarithm of a product is equal to the sum of the logarithms of its factors. The expression \(\ln x y z^{2}\) can be written as \(\ln(x) + \ln(y z^{2})\).
02

Application of Product Rule again

Now apply the product rule again to the term \(\ln(y z^{2})\), which again seems to be the logarithm of a product. This rule allows to split the term into two logarithms: \(\ln(y) + \ln(z^{2})\). This leads to a rewritten expression: \(\ln(x) + \ln(y) + \ln(z^{2})\).
03

Utilization of Power Rule

Finally, apply the power rule to the term \(\ln(z^{2})\). The power rule states that the logarithm of a number to a certain power is equal to the product of that power and the logarithm of the number. Thus \(\ln(z^{2})\) can be written as \(2*\ln(z)\). So the final expanded form of the given logarithm is \(\ln(x) + \ln(y) + 2*\ln(z)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Understanding the properties of logarithms is essential for expanding logarithmic expressions. Like a Swiss Army knife for algebra, these properties help us transform complex logarithmic expressions into simpler components that are easier to work with.

A logarithm basically tells us the power to which we must raise a base number to get another number. For instance, if we have a logarithm in the form of \(\log_b(x) = y\), this means that \(b^y = x\). This fundamental understanding opens up a pathway to delve into the various properties that operate within the realm of logarithms.

Three critical properties are the product rule, quotient rule, and power rule. The product rule guides us to break down logs of products into sums of logs. The quotient rule does the opposite for division, turning logs of quotients into differences of logs. The power rule allows for the exponent within a log to be pulled out as a multiplier. These rules not only make computations more manageable but also pave the way for solving more complex equations involving logarithms.

We apply these properties because logarithmic functions occur naturally across many disciplines. For instance, they're used to measure the intensity of earthquakes (Richter scale) and sound (decibels), to understand exponential growth and decay in populations and radioactive substances, and even in financial models to calculate compounding interest.
Product Rule of Logarithms
The product rule of logarithms is a gateway to simplifying expressions that consist of multiple terms multiplied together inside a logarithm. In essence, this rule states that the log of a product is the sum of the logs of its factors.

Let's take the logarithmic expression \(\ln(ab)\). Applying the product rule, we can express this as \(\ln(a) + \ln(b)\), effectively decomposing the log of a product into a sum. The logarithm of each separate term is easier to deal with, whether for further expansion, simplification, or even solving equations.

Real-World Implications

It’s not just about making math ‘easier’—this property has real-world implications. Scientists who work with phenomena that multiply, such as growing bacteria cultures or unchecked fires, can use the product rule to understand how variables interact over time, measuring changes logarithmically and providing valuable insights into their rates of growth.

The product rule is a workhorse in the field of mathematics but also serves as a bridge to understanding dynamic changes in many scientific fields.
Power Rule of Logarithms
When we encounter a logarithmic expression where the argument (the number or expression inside the log) is raised to a power, the power rule of logarithms comes into play. This rule allows us to take that exponent and bring it out in front of the log, formally stated as \(\log_b(x^n) = n * \log_b(x)\).

This is incredibly useful because it essentially simplifies the complexity of the argument down to its base component, making the expression more manageable. For example, applying the power rule to \(\ln(z^2)\) transforms it into \(2*\ln(z)\), just as we saw in the textbook's step-by-step solution.

Practical Applications

The power rule also has practical applications beyond textbook problems. It’s used in fields such as acoustics, where the intensity of sound depends on the power of its source, and in photography, where the exposure is related to the power of light. Understanding and applying the power rule can help professionals in these areas evaluate situations more accurately and efficiently.

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Most popular questions from this chapter

Think About It For how many integers between 1 and 20 can you approximate natural logarithms, given the values \(\ln 2 \approx 0.6931,\) ln \(3 \approx 1.0986,\) and ln 5\(\approx 1.6094 ?\) Approximate these logarithms (do not use a calculator).

Using Properties of Logarithms In Exercises \(15-20\) , use the properties of logarithms to rewrite and simplify the logarithmic expression. $$\ln \frac{6}{e^{2}}$$

Forensics At 8: 30 A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At 9: 00 A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at 11: 00 A.M. the temperature was \(82.8^{\circ} \mathrm{F} .\) From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula \(t=-10 \ln \frac{T-70}{98.6-70}\) where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling. It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F}\).) Use the formula to estimate the time of death of the person.

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