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Jodi and Jeff borrowed \(120,000 at 6.5% per annum compounded monthly for 30 years to purchase a home. Their monthly payment is determined to be \)758.48.

(a) Find a recursive formula for their balance after each monthly payment has been made.

(b) Determine Jodi and Jeff’s balance after the first payment.

(c) Using a graphing utility, create a table showing Jodi and Jeff’s balance after each monthly payment.

(d) Using a graphing utility, determine when Jodi and Jeff’s balance will be below \(100,000.

(e) Using a graphing utility, determine when Jodi and Jeff will pay off the balance.

(f) Determine Jodi and Jeff’s interest expense when the loan is paid

(h) Is it worthwhile for Jodi and Jeff to pay the additional \)100? Explain.

Short Answer

Expert verified

(a) The recursive formula for their balance after each monthly payment has been made is pn=1.0054pn-1-758.48

(b) Jodi and Jeff’s balance after the first payment is $119889.52

(c) A table showing Jodi and Jeff’s balance after each monthly payment can be created by evaluating the recursive formula for different values of n

(d) The balance will be less than $100,000 after 127 months

(e) The balance will be paid off after 358 months.

(f) Jodi and Jeff’s interest expense when the loan is paid is $151322.54

(h) It is worthwhile for Jodi and Jeff to pay the additional $100

Step by step solution

01

Step 1. Given Information

Jodi and Jeff borrowed $120,000 at 6.5% per annum compounded monthly for 30 years to purchase a home. Their monthly payment is determined to be $758.48.

02

Part (a) of Step 1. Recursive formula 

Given that A=758.48,r=0.065,n=12,p0=120,000

The recursive formula can be found by substituting the values in the equation role="math" localid="1648522221518" pn=1+rnpn-1-758.48

role="math" localid="1648522347330" pn=1+rnpn-1-758.48pn=1+0.06512pn11-758.48pn=1.0054pn-1-758.48

03

Part (b) of Step 1. Jodi and Jeff’s balance 

To calculate Jodi and Jeff’s balance after the first payment we have to evaluate the recursive formula for n=1

p1=1.0054p1-1-758.48p1=1.0054p0-758.48p1=1.0054×120,000-758.48p1=119889.52

04

Part (c) of Step 1. Table showing Jodi and Jeff’s balance 

The table showing Jodi and Jeff’s balance after each monthly payment can be created by evaluating the recursive formula for different values of n.

npn
1119889.52
2119778.433
3119666.767
4119554.488
5119441.602
6119328.106
7119213.998
05

Part (d) of Step 1. Jodi and Jeff’s balance will be below $100,000. 

The table showing Jodi and Jeff’s balance is

npn
116102247
117102041
118101833
119101625
120101415
121101204
122100992
123100779
124100565
125100350
126100133
12799915.1
12899696.2

From the above table, we can conclude that, pnis less than $100,000 for n=127

Therefore the balance will be less than $100,000 after 127 months.

06

Part (e) of Step 1. Jodi and Jeff will pay off the balance. 

The table showing Jodi and Jeff’s balance is

npn
3496442.4
3505718.7
3514991.1
3524259.6
3533524.1
3542784.7
3552041.2
3561293.8
357542.3
358-213.3

From the table, we can conclude that pnis less than 0for n=358

Therefore the balance will be paid off after 358 months.

07

Part (f) of Step 1. Jodi and Jeff’s interest expense 

Jodi and Jeff’s interest expenses can be calculated by subtracting the borrowed amount from the total of all payments.

From the table of the previous part, we can say that the balance falls $0 after the 358th payment

The payment of $758.48 was made 357 times

The last payment paid by Jodi and Jeff can be calculated by subtracting $-213.3 from $758.48

758.48-213.3=545.18

The total of all payments is the sum of $758.48 payments made for 358 months and the sum of the last payment

358×758.48+545.18=271322.54

The interest expense is

271322.54-120,000=151322.54

08

Part (h) of Step 1. Explanation

If Jodi and Jeff pay an extra $100 then the interest expense will be significantly lower, therefore it is worthwhile for Jodi and Jeff to pay the additional $100

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