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Cooling Air As a parcel of air rises (for example, as it is pushed over a mountain), it cools at the dry adiabatic lapse rate of 5.5°F per 1000 feet until it reaches its dew point. If the ground temperature is 67°F, write a formula for the sequence of temperatures, {Tn}, of a parcel of air that has risen n thousand feet. What is

the temperature of a parcel ofair if it has risen 5000 feet?

Short Answer

Expert verified

Formula for the sequence of temperatures

Tn=-5.5n+67

the temperature of a parcel of air if it has risen 5000 feet

T5=39.5°F

Step by step solution

01

Given Information 

The ground temperature is 67°F. The difference in temperature per 1000 feet is -5.5°F .

02

Formula for temperature 

The ground temperature is 67°F. The difference in temperature per 1000 feet is -5.5°F .

The temperature of parcel of air at 1000 feet is T1= 67-5.5=62.5

The temperature of parcel of air at 2000 feet isT2=67-2(5.5)

The temperature of parcel of air at n thousand feet

Tn=67-5.5nTn=-5.5n+67

03

Step 3:  Temperature at 5000 feet

Now we find the temperature of a parcel of air if it has risen 5000 feet

n=5

Tn=-5.5n+67n=5T5=-5.5(5)+67=39.5°F

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