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Eye color, Part I. A husband and wife both have brown eyes but carry genes that make it possible for their children to have brown eyes (probability 0.75 ), blue eyes (0.125) , or green eyes (0.125) . (a) What is the probability the first blue-eyed child they have is their third child? Assume that the eye colors of the children are independent of each other. (b) On average, how many children would such a pair of parents have before having a blue-eyed child? What is the standard deviation of the number of children they would expect to have until the first blue-eyed child?

Short Answer

Expert verified
(a) The probability is approximately 0.096. (b) On average, they would have 8 children before a blue-eyed child; the standard deviation is approximately 7.48.

Step by step solution

01

Identify Probability Model

The problem involves finding when the first blue-eyed child (event with probability \( p = 0.125 \)) occurs, which fits a geometric probability model. In this model, the probability of the first success (blue-eyed child) on the \( k \)-th trial is given by \( P(X = k) = (1-p)^{k-1}p \).
02

Calculate Probability for Part (a)

We need to find the probability that the first blue-eyed child is the third child. Using the geometric distribution formula, \( P(X=3) = (1-0.125)^{3-1}\times0.125 = 0.875^2\times0.125 \).
03

Compute P(X=3)

Calculate \( (0.875)^2 = 0.765625 \) and then \( 0.765625 \times 0.125 = 0.095703125 \). Therefore, the probability is approximately \( 0.096 \).
04

Determine Expected Value for Part (b)

For a geometric distribution, the expected value \( E(X) \) is given by \( \frac{1}{p} \). Here, \( p = 0.125 \), so \( E(X) = \frac{1}{0.125} = 8 \).
05

Calculate Standard Deviation for Part (b)

The standard deviation for a geometric distribution is given by \( \sqrt{\frac{1-p}{p^2}} \). Therefore, use \( \sqrt{\frac{0.875}{0.125^2}} = \sqrt{56} \approx 7.48 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Model
In the world of statistics, a probability model gives us a mathematical way to predict outcomes of random events. A common type is the geometric probability model, which focuses on finding the first success in a sequence of trials. This model is perfect for scenarios where you're waiting for an event, such as the first blue-eyed child in this exercise.

The geometric distribution applies when each trial (or child, in this case) is independent, and the event of interest has a constant probability of occurring in each trial. Here, the probability of a child having blue eyes is 0.125 (or 12.5%).

To find the probability that the first successful event (first blue-eyed child) happens at trial number \( k \), the probability model uses the formula:
  • \( P(X=k) = (1-p)^{k-1}p \)
Where \( p \) is the probability of success on each trial. This formula is crucial in calculating probabilities in a sequence of independent events.
Expected Value
The expected value in a geometric distribution tells you how many trials you can expect, on average, before achieving the first success. It's like the average number of children a couple would have before having one with blue eyes.

For geometric distributions, the formula for expected value \( E(X) \) is quite simple:
  • \( E(X) = \frac{1}{p} \)
In this case, since the probability \( p \) of having a blue-eyed child is 0.125, the expected number of children until seeing a blue-eyed child is \( \frac{1}{0.125} = 8 \). This means on average, they might expect their first blue-eyed child by the 8th child.

Expected value is a powerful concept because it provides a single summary statistic that encapsulates the expected outcome over the long run.
Standard Deviation
Standard deviation is a metric that helps us understand the variability or spread of a probability distribution. In a geometric distribution, it tells us how much the number of trials needed to achieve the first success might differ from the expected value.

The formula for standard deviation \( \sigma \) in a geometric distribution is given by:
  • \( \sigma = \sqrt{\frac{1-p}{p^2}} \)
Using the probability \( p = 0.125 \), we find the standard deviation to be \( \sqrt{\frac{0.875}{0.125^2}} = \sqrt{56} \approx 7.48 \). This means the number of children needed to have a blue-eyed child can vary by about 7.5 children around the average of 8.

A larger standard deviation indicates more variability and less predictability in the outcome. In this way, standard deviation complements the expected value by providing a measure of uncertainty.
Independent Events
Independent events are fundamental to understanding probability models like the geometric distribution. Two events are independent if the occurrence of one does not affect the probability of the other happening.

In the context of this exercise, each child's eye color is an independent event. This means the eye color of one child doesn't influence the eye color of the next. The probability of each event (in this case, having a blue-eyed child) remains constant at 0.125.

This concept is crucial because it allows us to use the geometric distribution formula. If the events weren't independent, the probability of each subsequent child being blue-eyed could change based on previous outcomes.

Understanding independent events helps simplify complex probability problems and is a cornerstone in the study of probability and statistics.

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