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Pew Research reported that the typical response rate to their surveys is only \(9 \%\). If for a particular survey 15,000 households are contacted, what is the probability that at least 1,500 will agree to respond? \(^{42}\)

Short Answer

Expert verified
The probability is approximately 0.

Step by step solution

01

Identify the Problem

We are given a survey with a response rate of 9% and want to know the probability that 1,500 or more households out of 15,000 will agree to respond.
02

Define the Binomial Distribution

We recognize this problem as a binomial distribution problem where the number of trials is 15,000, and the success probability (household responds) is 0.09.
03

Calculate the Mean and Standard Deviation

For a binomial distribution, the mean \( \mu \) is given by \( n \cdot p \) and the standard deviation \( \sigma \) is given by \( \sqrt{n \cdot p \cdot (1 - p)} \). Here, \( \mu = 15,000 \cdot 0.09 = 1,350 \) and \( \sigma = \sqrt{15,000 \cdot 0.09 \cdot 0.91} \approx 35.95 \).
04

Use Normal Approximation

Since the number of trials is large, we can use the normal approximation for the binomial distribution. The normal distribution has a mean of 1,350 and a standard deviation of approximately 35.95.
05

Calculate the Z-score

Calculate the z-score for \( x = 1,500 \) using the formula \( z = \frac{x - \mu}{\sigma} \). Here, \( z = \frac{1,500 - 1,350}{35.95} \approx 4.17 \).
06

Determine the Probability

Using a standard normal distribution table, find the probability corresponding to a z-score of 4.17. The probability of having a z-score greater than 4.17 is extremely small (almost 0). This means the probability of having at least 1,500 responses is close to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a fundamental concept in statistics. It's used when we are interested in the number of successes in a fixed number of independent trials. Each trial has two possible outcomes: success or failure. In our case, each household either responds (success) or doesn't respond (failure) to a survey.

Key characteristics of a binomial distribution include:
  • Number of trials (n): This is the total number of attempts or tests conducted. In this scenario, 15,000 households were surveyed.
  • Probability of success (p): The probability that one trial results in a success. Here, it's given that a response is likely 9% of the time, or 0.09 probabilistically.
  • Determination of mean and standard deviation: The mean (expected value) is calculated using the formula \( n \cdot p \), and the standard deviation is found using \( \sqrt{n \cdot p \cdot (1-p)} \).
The binomial distribution helps us to determine the expected and the variability of responses from surveyed households.
Normal Approximation
When dealing with large sample sizes, the binomial distribution can be difficult to compute directly. Instead, we use normal approximation, which simplifies the process.

This technique involves approximating the binomial distribution with a normal distribution, which is more manageable computationally. For the normal approximation to be valid, sample sizes should be large, generally considered as \( n \cdot p > 5 \) and \( n \cdot (1 - p) > 5 \). In our case, 1,350 expected responses meet this requirement.

With this approximation, we find that the mean (\( \mu \)) and standard deviation (\( \sigma \)) derived from the binomial distribution are applied to the normal distribution as well. This provides a smooth, continuous curve which helps calculate probabilities, such as the chance of getting at least a certain number of responses.
Z-score
The z-score is a crucial part of the normal approximation process, providing a way to standardize the results. In statistics, a z-score tells us how many standard deviations an element is from the mean.

For instance, to calculate the z-score for getting 1,500 or more responses, we use the formula:
\[z = \frac{x - \mu}{\sigma}\]
where \( x \) is the value in question (1,500 responses), \( \mu \) is the expected mean (1,350 responses), and \( \sigma \) is the standard deviation (approximately 35.95).

This calculation yields a z-score of about 4.17, which indicates that 1,500 responses are substantially higher than what would typically be expected, given the calculated mean and standard deviation. This standardized score leads us to further analysis in the context of the normal distribution table.
Response Rate
The response rate is the ratio of the number of respondents to the total number of surveyed entities. In our example, Pew Research highlights a response rate of 9%. The response rate is a critical metric as it directly influences the reliability and validity of survey results.

A low response rate often prompts analysts to consider whether the collected data truly represents the intended population, whereas a higher response rate increases confidence in the survey findings. Here are some points to consider about response rates in surveys:
  • Determining Sample Size: Knowing the expected response rate helps in calculating how many individuals you should contact to achieve a desired number of responses.
  • Impact on Data Quality: A low response rate may imply non-response bias, where the views of the non-respondents could differ from those who responded.
  • Strategies to Increase Rates: Using follow-up calls, incentives, or simplifying the survey can help improve response rates.
Understanding and working with response rates are essential for conducting effective and reliable surveys.

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Most popular questions from this chapter

Suppose a university announced that it admitted 2,500 students for the following year's freshman class. However, the university has dorm room spots for only 1,786 freshman students. If there is a \(70 \%\) chance that an admitted student will decide to accept the offer and attend this university, what is the approximate probability that the university will not have enough dormitory room spots for the freshman class?

Playing darts. Calculate the following probabilities and indicate which probability distribution model is appropriate in each case. A very good darts player can hit the bull's eye (red circle in the center of the dart board) \(65 \%\) of the time. What is the probability that he (a) hits the bullseye for the \(10^{\text {th }}\) time on the \(15^{\text {th }}\) try? (b) hits the bullseye 10 times in 15 tries? (c) hits the first bullseye on the third try?

Customers at a coffee shop. A coffee shop serves an average of 75 customers per hour during the morning rush. (a) Which distribution have we studied that is most appropriate for calculating the probability of a given number of customers arriving within one hour during this time of day? (b) What are the mean and the standard deviation of the number of customers this coffee shop serves in one hour during this time of day? (c) Would it be considered unusually low if only 60 customers showed up to this coffee shop in one hour during this time of day? (d) Calculate the probability that this coffee shop serves 70 customers in one hour during this time of day.

Multiple choice quiz. In a multiple choice quiz there are 5 questions and 4 choices for each question \((\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}) .\) Robin has not studied for the quiz at all, and decides to randomly guess the answers. What is the probability that (a) the first question she gets right is the \(3^{r d}\) question? (b) she gets exactly 3 or exactly 4 questions right? (c) she gets the majority of the questions right?

Sickle cell anemia. Sickle cell anemia is a genetic blood disorder where red blood cells lose their flexibility and assume an abnormal, rigid, "sickle" shape, which results in a risk of various complications. If both parents are carriers of the disease, then a child has a \(25 \%\) chance of having the disease, \(50 \%\) chance of being a carrier, and \(25 \%\) chance of neither having the disease nor being a carrier. If two parents who are carriers of the disease have 3 children, what is the probability that (a) two will have the disease? (b) none will have the disease? (c) at least one will neither have the disease nor be a carrier? (d) the first child with the disease will the be \(3^{r d}\) child?

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