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Multiple choice quiz. In a multiple choice quiz there are 5 questions and 4 choices for each question \((\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}) .\) Robin has not studied for the quiz at all, and decides to randomly guess the answers. What is the probability that (a) the first question she gets right is the \(3^{r d}\) question? (b) she gets exactly 3 or exactly 4 questions right? (c) she gets the majority of the questions right?

Short Answer

Expert verified
(a) \(\frac{9}{64}\), (b) \(\frac{75}{512}\), (c) \(\frac{151}{1024}\).

Step by step solution

01

Understanding the Probability of Correct Answers for One Question

Each question has 4 possible choices, and only one is correct. Therefore, the probability that Robin guesses an answer correctly is \( \frac{1}{4} \). The probability of guessing incorrectly is \( \frac{3}{4} \).
02

Calculating Probability for Part (a)

For Robin to get the first correct answer on the 3rd question, she must get the first two questions wrong, followed by a correct answer on the 3rd question.This is calculated using: \( P = \left( \frac{3}{4} \right)^2 \times \frac{1}{4} \). Calculating gives: \[ P = \left( \frac{3}{4} \right)^2 \times \frac{1}{4} = \frac{9}{64} \].
03

Calculating Probability for Part (b)

To find the probability that Robin gets exactly 3 or 4 questions right, we use the binomial probability formula: \( P(X = k) = \binom{n}{k} (p^k) (1-p)^{n-k} \), where \( n = 5 \), \( p = \frac{1}{4} \), and \( k \) is the number of correct answers.1. For exactly 3 correct: \( P(X = 3) = \binom{5}{3} \left(\frac{1}{4}\right)^3 \left(\frac{3}{4}\right)^2 \). - Calculate: \( \binom{5}{3} = 10 \), so \( P = 10 \cdot \left(\frac{1}{4}\right)^3 \cdot \left(\frac{3}{4}\right)^2 = \frac{135}{1024} \).2. For exactly 4 correct: \( P(X = 4) = \binom{5}{4} \left(\frac{1}{4}\right)^4 \left(\frac{3}{4}\right)^1 \). - Calculate: \( \binom{5}{4} = 5 \), so \( P = 5 \cdot \left(\frac{1}{4}\right)^4 \cdot \frac{3}{4} = \frac{15}{1024} \).3. Total probability for exactly 3 or 4 correct answers: \( P = \frac{135}{1024} + \frac{15}{1024} = \frac{150}{1024} = \frac{75}{512} \).
04

Calculating Probability for Part (c)

To get the majority of right answers, Robin must get at least 3 correct answers.Using the previous calculations:- Probability of exactly 3 correct answers is \( \frac{135}{1024} \).- Probability of exactly 4 correct answers is \( \frac{15}{1024} \).- Probability of all 5 correct is \( P(X = 5) = \binom{5}{5} \left(\frac{1}{4}\right)^5 = \frac{1}{1024} \).Sum all probabilities: \( P = \frac{135}{1024} + \frac{15}{1024} + \frac{1}{1024} = \frac{151}{1024} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Binomial Probability
When tackling problems that involve multiple-choice guessing, binomial probability is a key concept. It helps calculate the chances of getting a specific number of successful outcomes (in this case, correct answers) when each outcome is independent of the others.

Binomial probability works on the assumption that:
  • The number of trials or questions (n) is fixed, here it's 5.
  • Each trial has only two possible outcomes - success (right answer) or failure (wrong answer).
  • The probability of success (p) is the same for each trial, given by \( p = \frac{1}{4} \) for Robin’s guessing.
  • The probability of failure is \( 1-p \), which equates to \( \frac{3}{4} \).
For Robin to guess exactly 'k' correct answers, we use the formula:\[P(X = k) = \binom{n}{k} (p^k) (1-p)^{n-k}\] This formula combines the binomial coefficient \( \binom{n}{k} \), which determines how many ways Robin might get 'k' correct answers from 'n' questions, with the probability of these successes occurring. Binomial probability is invaluable in settings where repeated independent trials occur, such as quizzes or tests.
Exploring Conditional Probability
Conditional probability is another important concept, which comes into play when determining the likelihood of an event given that another event has occurred.

For instance, question part (a) asks us to find the probability that Robin's first correct answer is on the 3rd question. In conditional terms, this is the probability that she gets two wrong answers followed by a correct one. We use the rule for conditional probability to determine this:

  • First, calculate the probability of independent events (two wrong answers followed by a right one).
  • The probability of each wrong answer is \( \frac{3}{4} \), while the probability of a correct answer is \( \frac{1}{4} \).
So, the probability for Robin to guess wrong twice and then right would be \( \left( \frac{3}{4} \right)^2 \times \frac{1}{4} \), which simplifies to \( \frac{9}{64} \). Conditional probability allows us to approach problems like this logically and precisely.
Delving into Statistical Analysis
Statistical analysis involves the collection, examination, and interpretation of data in order to understand probabilities more thoroughly. In our scenario with Robin and her guesses, understanding statistical analysis means looking deeper into the probabilities of various outcomes.

This exercise employs statistical analysis by:
  • Calculating exact probabilities for different numbers of correct answers using a well-defined probability framework such as the binomial distribution.
  • Determining the odds of achieving a majority of correct answers by summing relevant probabilities.
For example, statistical analysis is used to find the total probability of Robin getting at least 3 right answers. This involves adding the probabilities for exact scenarios: 3 correct, 4 correct, and all 5 correct. Such analysis helps in making informed predictions about outcomes and can guide decision-making in uncertain situations.

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Most popular questions from this chapter

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