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College smokers. We are interested in estimating the proportion of students at a university who smoke. Out of a random sample of 200 students from this university, 40 students smolse. (a) Calculate a \(95 \%\) confidence interval for the proportion of students at this university who smoke, and interpret this interval in context. (Reminder: check conditions) (b) If we wanted the margin of error to be no larger than \(2 \%\) at a \(95 \%\) confidence level for the proportion of students who smoke, how big of a sample would we need?

Short Answer

Expert verified
(a) CI: [14.5%, 25.5%]. (b) Sample size: 1537.

Step by step solution

01

Find Sample Proportion

First, calculate the sample proportion \(\hat{p}\).Given: 40 students smoke out of a sample of 200 students.\[\hat{p} = \frac{40}{200} = 0.20\]
02

Check Conditions for Confidence Interval

To calculate the confidence interval, we need to check if the sample size is large enough for our estimate to be valid.The conditions are:1. The sample is random.2. The sample should be large enough such that both \(n\hat{p} \) and \(n(1-\hat{p})\) are at least 10. For our sample:\[n\hat{p} = 200 \times 0.20 = 40\]\[n(1-\hat{p}) = 200 \times 0.80 = 160\]These are both greater than 10, so the conditions are satisfied.
03

Calculate Confidence Interval

Use the formula for a confidence interval for a proportion:\[ CI = \hat{p} \pm Z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]For a 95% confidence level, \( Z^* \approx 1.96 \).\[CI = 0.20 \pm 1.96 \times \sqrt{\frac{0.20 \times 0.80}{200}} = 0.20 \pm 0.055\]Thus, the confidence interval is \([0.145, 0.255]\).
04

Interpretation of Confidence Interval

We are 95% confident that the proportion of students who smoke at this university is between 14.5% and 25.5%.
05

Calculate Required Sample Size for Desired Margin of Error

We want a margin of error (ME) no larger than 2% (or 0.02).The formula for margin of error is:\[ME = Z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]Rearranging for \(n\):\[n = \left(\frac{Z^*}{ME}\right)^2 \hat{p}(1-\hat{p})\]Using \(Z^* = 1.96\), \(\hat{p} = 0.20\), and \(ME = 0.02\):\[n = \left(\frac{1.96}{0.02}\right)^2 \times 0.20 \times 0.80 = 1536.64\]We round up to the nearest whole number, so the required sample size is 1537.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Proportion
The sample proportion, denoted as \( \hat{p} \), represents the fraction of individuals in a sample who possess a particular attribute. In our example, the attribute in question is smoking among university students. Out of the 200 students sampled, 40 are smokers. To find the sample proportion, you divide the number of smokers by the total number of sampled students: \[ \hat{p} = \frac{40}{200} = 0.20 \] This calculation indicates that 20% of the sampled students are smokers. The sample proportion is crucial as it acts as an estimate for the true proportion in the entire population. When conducting statistical analyses, always ensure that your sample is random and representative to yield trustworthy results.
Explaining Margin of Error
The margin of error (ME) provides a measure of the extent of uncertainty or possible variation around a sample estimate. It indicates how far the sample proportion might be from the true population proportion. A smaller margin of error indicates higher confidence in the estimate's accuracy. Typically, the margin of error is computed using a statistical formula that involves the standard error of the sample proportion and a Z-score linked to the desired confidence level. For a 95% confidence level, the Z-score is approximately 1.96. This number is chosen based on standard statistical tables. To keep the margin of error below 0.02 or 2%, adjustments in sample size, representative data, or confidence level must be considered. For instance, decreasing the margin of error often necessitates a larger sample size.
Delving into Statistical Conditions
Before calculating confidence intervals, it's essential to check specific statistical conditions to ensure that your analysis is valid. These conditions are:
  • Random sampling: The sample must be collected randomly to avoid bias and accurately represent the broader population.
  • Minimum size condition: Both \( n\hat{p} \) and \( n(1-\hat{p}) \) should be at least 10 to use the normal approximation method for confidence intervals. This is known as the large sample condition. In our example, \( n\hat{p} = 40 \) and \( n(1-\hat{p}) = 160 \), satisfying this requirement.
By adhering to these conditions, the analysis will be statistically sound, providing robust and reliable estimates for the population parameter. It's a critical step ensuring that conclusions drawn from the data hold true in a general setting.
Decoding Confidence Level
The confidence level is an interval estimate's statistical reliability, indicating how sure we are that the true parameter lies within the specified range. Often expressed as a percentage, a common choice is 95%. In practical terms, a 95% confidence level means if the same population is sampled multiple times, approximately 95% of the derived confidence intervals will overarch the true population parameter. In our university smoking example, we are 95% confident that the true proportion of students who smoke falls within 14.5% and 25.5%. The confidence level reflects the probability of the sample accurately representing the population, with a higher percentage denoting more assuredness. However, increasing the confidence level typically broadens the confidence interval, requiring more data for precise estimates.

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Most popular questions from this chapter

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