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Public option, Part 1. A Washington Post article from 2009 reported that "support for a government-run health-care plan to compete with private insurers has rebounded from its summertime lows and wins clear majority support from the public." More specifically, the article says "seven in 10 Democrats back the plan, while almost nine in 10 Republicans oppose it. Independents divide 52 percent against, 42 percent in favor of the legislation." \((6 \%\) responded with "other".) There were were 819 Democrats, 566 Republicans and 783 Independents surveyed. (a) A political pundit on TV claims that a majority of Independents oppose the health care public option plan. Do these data provide strong evidence to support this statement? (b) Would you expect a confidence interval for the proportion of Independents who oppose the public option plan to include \(0.5 ?\) Explain.

Short Answer

Expert verified
Yes, a majority of Independents oppose; confidence interval likely includes 0.5.

Step by step solution

01

Calculate Independent Opposers

To find out how many Independents oppose the plan, calculate the proportion: - Independent Opposers: 52% of 783. Calculate this: \( 0.52 \times 783 = 407.16 \approx 407 \). This means approximately 407 Independents oppose the plan.
02

Majority Test for Opposing Independents

To determine if a majority of Independents oppose the plan, check if this is more than half of all Independents surveyed. - Half of 783 Independents: \( \frac{783}{2} = 391.5 \). Since 407 is greater than 391.5, this confirms that a majority of Independents oppose the plan.
03

Explain Confidence Interval Expectation

A confidence interval captures the proportion of the population who exhibits a trait. Since 52% opposed in the sample, the sample proportion is \( p = 0.52 \). Calculated via a confidence interval formula, accounting for sample size 783 and standard deviation, it's expected to include 0.5. This is because 52% is close to 50%, historically expected due to margin of error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
Understanding proportion is crucial in data analysis, especially when assessing public opinion or survey results. A proportion represents the fraction of a total population that exhibits a certain trait or behavior. For example, in the survey about the public option plan, we are interested in the proportion of Independents who oppose the plan, which is calculated as 52%.
To calculate this proportion, you use the formula:
  • Proportion (\( p \)) = Number with trait / Total number surveyed
In this case, it was 407 Independents out of 783 surveyed who opposed the plan, resulting in a 52% opposition. Proportions are foundational in understanding how data represents real-world scenarios, providing insight into trends and opinions.
Confidence Interval
A confidence interval gives us a range of values, derived from a dataset, that is likely to contain the true population proportion. This is particularly useful when you need to infer the proportion for a larger population based on a sample.
When calculating a confidence interval for the proportion of Independents who oppose the health care plan, we start with the sample proportion (\( \hat{p} = 0.52 \)) and consider the sample size (\( n = 783 \)). The calculation involves finding the standard error, which measures how much our sample proportion is likely to fluctuate:
  • Standard Error (\( ext{SE} \)) = \( \sqrt{\frac{p(1-p)}{n}} \)
Then you use the standard error to calculate the confidence interval. Typically, a 95% confidence interval is used in social sciences, providing a broad understanding of where the true population parameter might lie. Given that 52% is very close to the midpoint of 50%, the confidence interval is expected to include 0.5 with the usual margins of error.
Sample Size
Sample size is a key component when conducting surveys or experiments, as it impacts the reliability and accuracy of the results. A larger sample size generally provides more reliable and precise estimates of the population parameter due to reduced standard error.
In the context of the exercise, the sample size of 783 Independents gives a decent representation, which helps in forming a fairly accurate confidence interval. The larger your sample size, the more confident you can be that your sample proportion is close to the true population proportion.
However, it's always critical to ensure that the sample is not only large but also randomly selected, to avoid bias and ensure representativeness. This maximizes the likelihood that the sample accurately reflects the overall population.
Majority Test
A majority test is a simple but powerful tool used to determine if more than half of a population or sample exhibit a particular characteristic. To find out if a majority of Independents oppose the health care plan, you compare the number of those opposing to half of the total sample.
In this case:
  • Calculate the number that would represent half of the population: \( \frac{783}{2} = 391.5 \)
  • Compare it to the number opposing the plan (407)
Since 407 is greater than 391.5, it confirms a majority. Majority tests provide a straightforward interpretation of data, especially when making decisions or claims based on survey results. It's a direct application of proportions to a practical judgment on whether a particular stance is supported by the majority in a sample.

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Most popular questions from this chapter

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