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91Ó°ÊÓ

Consider the null hypothesis \(H_{0}: \mu=625 .\) Suppose that a random sample of 29 observations is taken from a normally distributed population with \(\sigma=32\). Using a significance level of \(.01\), show the rejection and nonrejection regions on the sampling distribution curve of the sample mean and find the critical value(s) of \(z\), when the alternative hypothesis is as follows. a. \(H_{1}: \mu \neq 625\) b. \(H_{1}: \mu>625\) c. \(H_{1}: \mu<625\)

Short Answer

Expert verified
For the alternative hypothesis \(H_{1}:\mu \neq 625\), the critical value of z is \(\pm 2.58\), meaning anything outside this range will fall in the rejection region. For \(H_{1}:\mu > 625\), the critical value of z is \(2.33\), anything greater than this falls in the rejection region. For \(H_{1}:\mu < 625\), the critical value of z is \(-2.33\), meaning anything less than this falls in the rejection region.

Step by step solution

01

Identify Hypotheses and Significance Level

The null hypothesis \(H_{0}:\mu = 625\) and the alternative hypotheses are \(H_{1}:\mu \neq 625\), \(H_{1}:\mu > 625\), and \(H_{1}:\mu < 625\). Also, the significance level is \(0.01\).
02

Calculate Z-critical Values for \(H_{1}:\mu \neq 625\)

For a two-sided test, the rejection regions are both sides of the curve because we are testing for inequality (\(\mu \neq 625\)). The cumulative probability for this test is \(1 - \frac{0.01}{2} = 0.995\). Checking a standard z-table, the z-value that corresponds to 0.995 is approximately \(\pm 2.58\). So, the critical values of z are \(\pm 2.58\).
03

Calculate Z-critical Values for \(H_{1}:\mu > 625\)

For this one-sided test, the rejection region is in the right tail of the curve (testing for \(\mu > 625\)). So, with a total area of \(0.99\) to the left (since \(1-0.01=0.99\)), the z-critical value from the Z-table is approximately \(2.33\). So, the critical value of z is \(2.33\).
04

Calculate Z-critical Values for \(H_{1}:\mu < 625\)

For this one-sided test, the rejection region is in the left tail of the curve (testing for \(\mu < 625\)). So, using a total of \(0.01\) to the left of the curve, the z-critical value from the Z-table is approximately \(-2.33\). So, the critical value of z is \(-2.33\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis represents a default or original statement about a population parameter that we aim to test. It is often a statement of no effect or no difference. In this exercise, the null hypothesis is denoted as \(H_{0}: \mu = 625\), suggesting that the population mean \(\mu\) is equal to 625.
The null hypothesis serves as the starting point for statistical testing and is tested against the alternative hypothesis. One common trait of the null hypothesis is that it assumes any observed effect is due to sample variation and not a true effect in the population. This means we assume the null hypothesis is true until proven otherwise.
It's primarily used to establish a position that can be contradicted through the collection of sample data. If the data provides significant evidence against \(H_0\), this may lead to its rejection in favor of an alternative hypothesis.
Alternative Hypothesis
Contrary to the null hypothesis, the alternative hypothesis posits that a population parameter differs from the value stated in the null hypothesis and represents the effect one expects to find. In our exercise, we have three alternative hypotheses:
  • \(H_{1}: \mu eq 625\): The mean is not equal to 625, indicating a two-tailed test.
  • \(H_{1}: \mu > 625\): The mean is greater than 625, implying a right-tailed test.
  • \(H_{1}: \mu < 625\): The mean is less than 625, suggesting a left-tailed test.
With the alternative hypothesis, we're looking for evidence to support this claim in the sample data. It often reflects the research hypothesis and is what the study aims to support.
When the sample data strongly supports the alternative hypothesis, it may lead to the rejection of the null hypothesis, indicating a significant result.
Significance Level
The significance level, denoted as \(\alpha\), represents the threshold probability for rejecting the null hypothesis. It's a crucial component in hypothesis testing, defining how strong the evidence must be against the null hypothesis to reject it. In this exercise, the significance level is set at \(0.01\), or 1%.
This implies that there's a 1% chance of rejecting the null hypothesis when it is actually true, known as a Type I error. A lower significance level, like 0.01, requires stronger evidence against the null hypothesis compared to a common level such as 0.05.
  • If the p-value from the test is less than \(\alpha\), the null hypothesis is rejected.
  • If the p-value is greater than \(\alpha\), we fail to reject the null hypothesis.
The significance level not only determines the rejection criteria but also impacts the width of the confidence intervals and the z-critical values used in the test.
Critical Value
The critical value is a point on the test statistic distribution used as a decision criterion for hypothesis testing. It's determined by the significance level and the nature of the test (one-tailed or two-tailed).
In this exercise, we calculated different critical values:
  • For \(H_{1}: \mu eq 625\), the two-tailed test critical values are approximately \(\pm 2.58\), derived from dividing \(\alpha\) by 2 for each tail.
  • For \(H_{1}: \mu > 625\), the right-tailed test critical value is approximately \(2.33\); here, it's the point where 99% of the data lies below.
  • For \(H_{1}: \mu < 625\), the left-tailed test critical value is approximately \(-2.33\), representing the point below which only 1% of the data lies.
These critical values are used to define the rejection region, determining whether the observed test statistic falls into a range that leads us to reject \(H_0\) or not.
Sampling Distribution
A sampling distribution is the probability distribution of a given statistic based on a random sample. In hypothesis testing, we often look at the sampling distribution of the sample mean. This distribution provides insight into how the sample mean would behave if we took many samples from the same population.
For normally distributed populations, which the exercise assumes, the sampling distribution of the sample mean will also be normal, especially when sample sizes are large due to the Central Limit Theorem.
With a mean equal to the population mean and a standard error of \(\sigma / \sqrt{n}\), where \(\sigma\) is the population standard deviation and \(n\) is the sample size, we attain a clearer picture of the variability expected in the sample data.
  • In this exercise, the sample size is 29 and \(\sigma = 32\), so the standard error is \(32/\sqrt{29}\). This helps in generating the z-critical values and defining rejection regions.
Understanding the sampling distribution is essential as it forms the basis for determining whether the sample provides sufficient evidence to reject the null hypothesis.

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Most popular questions from this chapter

The standard therapy used to treat a disorder cures \(60 \%\) of all patients in an average of 140 visits. A health care provider considers supporting a new therapy regime for the disorder if it is effective in reducing the number of visits while retaining the cure rate of the standard therapy. A study of 200 patients with the disorder who were treated by the new therapy regime reveals that 108 of them were cured in an average of 132 visits with a standard deviation of 38 visits. What decision should be made using a \(.01\) level of significance?

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