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Consider the null hypothesis \(H_{0}: \mu=5 .\) A random sample of 140 observations is taken from a population with \(\sigma=17\). Using \(\alpha=.05\), show the rejection and nonrejection regions on the sampling distribution curve of the sample mean and find the critical value(s) of \(\mathrm{z}\) for the following. a. a right-tailed test b. a left-tailed test \(\quad\) c. a two-tailed test

Short Answer

Expert verified
The critical z-values for different types of test are: a) Right-tailed test: 1.645, b) Left-tailed test: -1.645, c) Two-tailed test: \(\pm1.96\). These values essentially divide the acceptance and rejection zones on a testing curve.

Step by step solution

01

Calculate test statistic

First, calculate the test statistic for each type of test. Recall that: \(z = \frac{(\overline{X} - \mu)}{(\sigma / \sqrt{n})}\). With \(\mu = 5\), \(\sigma = 17\), and \(n = 140\), the calculated 'z' values will be the same, regardless of the type of test.
02

Determine the critical value of z for a right-tailed test

For a right tailed test at \(\alpha = 0.05\), equivalent to a confidence level of 95%, the critical z-score from the z table is usually 1.645. Hence, this z-score separates the acceptance region (to the left of 1.645) and the rejection region (to the right of 1.645). If the computed 'z' is in the rejection region, you reject the null hypothesis.
03

Determine the critical value of z for a left-tailed test

For a left-tailed test at \(\alpha = 0.05\), equivalent to a confidence level of 95%, the critical z-score from the z table is usually -1.645. Hence, this z-score separates the acceptance region (to the right of -1.645) and the rejection region (to the left of -1.645). If the computed 'z' is in the rejection region, you reject the null hypothesis.
04

Determine the critical value of z for a two-tailed test

For a two-tailed test at \(\alpha = 0.05\), equivalent to a confidence level of 90%, the critical z-scores are usually \(\pm1.96\). Hence, these z-scores separate the acceptance region (between -1.96 and 1.96) and the rejection region (to the left of -1.96 and to the right of 1.96). If the computed 'z' is in the rejection region, you reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Value
The critical value plays a significant role in hypothesis testing. It essentially acts as a threshold, marking the boundaries of the rejection region on a statistical distribution, often the normal distribution. The critical value is tied to the significance level, denoted by \( \alpha \), which is the probability of rejecting the null hypothesis when it is true. Common \( \alpha \) values are 0.05, 0.01, and 0.10 corresponding to confidence levels of 95%, 99%, and 90%, respectively.
  • For a right-tailed test, the critical value separates the far right portion of the distribution.
  • In a left-tailed test, it separates the far left portion.
  • For a two-tailed test, critical values are found at both ends of the distribution.
These critical regions are where, if our test statistic falls, we reject the null hypothesis in favor of the alternative hypothesis. Depending on whether it is a one-tailed or two-tailed test, the corresponding z-score (the critical z-value) can differ, as seen in the original solution with common cutoffs like 1.645 and 1.96.
Z-Score
The z-score is a standardized statistic used in hypothesis testing to determine how far away a sample mean is from the population mean in units of the standard deviation. The z-score is crucial because it helps identify whether the sample result is typical of what we'd expect if the null hypothesis were true.You calculate z-score using:\[ z = \frac{(\overline{X} - \mu)}{(\sigma / \sqrt{n})} \]where:
  • \( \overline{X} \) is the sample mean.
  • \( \mu \) is the population mean under the null hypothesis.
  • \( \sigma / \sqrt{n} \) is the standard error.
The higher the absolute value of the z-score, the further the sample mean is from the population mean, indicating it is less likely to occur by random chance. In hypothesis testing, we compare the computed z-score against the critical z-value to decide whether to reject or not reject the null hypothesis.
Null Hypothesis
The null hypothesis, often denoted as \( H_0 \), is a statement used in hypothesis testing representing a default position that there is no effect or no difference. In many tests, it's a statement asserting that any observed effect in the data is purely due to chance.In the context of the original exercise, our null hypothesis is \( H_{0}: \mu=5 \), which asserts that the population mean \( \mu \) is equal to 5. Hypothesis testing revolves around determining whether evidence from the sample data is strong enough to reject this null hypothesis in favor of an alternative hypothesis.Rejection of the null hypothesis implies that the data provides sufficient evidence that the population mean is different from 5, but if it falls within the critical value's range, we don't have enough evidence to reject \( H_0 \). The goal is to minimize errors, particularly Type I errors, which occur when we incorrectly reject a true null hypothesis.
Sample Mean
The sample mean, denoted by \( \overline{X} \), is the average value of a sample and serves as an estimator of the population mean. It is crucial in hypothesis testing as it forms the basis of our z-score calculations.When gathered from a random sample, the sample mean can provide insights into the population from which the sample is drawn. However, due to natural variability, it might not perfectly match the population mean (The reliability of \( \overline{X} \) as an estimate increases with sample size \( n \). Larger samples tend to approximate the true population mean more closely, ensuring the conclusions drawn from hypothesis testing are similarly more robust. The standard error \( \sigma / \sqrt{n} \), associated with \( \overline{X} \), diminishes as the sample size grows, tightening the estimate's precision.

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Most popular questions from this chapter

The Bath Heritage Days, which take place in Bath, Maine, have been popular for, among other things, an eating contest. In 2009, the contest switched from blueberry pie to a Whoopie Pie (www.timesrecord.com), which consists of two large, chocolate cake-like cookies filled with a large amount of vanilla cream. Sixty-five randomly selected adults are chosen to eat a 1 -pound Whoopie Pie, and the average time for 59 adults (out of these 65 ) is \(127.10\) seconds. Based on other Whoopie Pie-eating contests throughout the United States, suppose that the standard deviation of the times taken by all adults to consume 1-pound Whoopie pies are known to be \(23.80\) seconds. a. Find the \(p\) -value for the test of hypothesis with the alternative hypothesis that the mean time to eat a 1 -pound Whoopie Pie is more than 2 minutes. Will you reject the null hypothesis at \(\alpha=.01\) ? Explain. What if \(\alpha=.02\) ? b. Test the hypothesis of part a using the critical-value approach. Will you reject the null hypothesis at \(\alpha=.01\) ? What if \(\alpha=.02\) ?

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