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91Ó°ÊÓ

You read an article that states " 50 hypothesis tests of \(H_{0}: \mu=35\) versus \(H_{1}: \mu \neq 35\) were performed using \(\alpha=.05\) on 50 different samples taken from the same population with a mean of \(35 .\) Of these, 47 tests failed to reject the null hypothesis." Explain why this type of result is not surprising.

Short Answer

Expert verified
Having 47 out of 50 tests fail to reject the null hypothesis is not surprising because the true population mean is indeed 35. Given the significance level of 5%, we would expect around 95% of the tests (thus 47 or 48 out of 50) to fail to reject the null hypothesis, given no substantial difference between the tested value and the actual population parameter.

Step by step solution

01

Understand Hypothesis Testing

In statistical hypothesis testing, the null hypothesis \(H_{0}\) is an initial claim that is based on past scientific research or observations. The alternative hypothesis \(H_{1}\) proposes an alternative idea. In this exercise, the null hypothesis is that the population mean is 35, and the alternative is that the mean is not 35.
02

Understand the Significance Level (\(\alpha\))

The significance level (\(\alpha\)), also known as the 'Type I error', is the probability of rejecting the null hypothesis when it is true. In this exercise, \(\alpha\) is set as .05, which means there is a 5% risk of concluding that a difference exists when there is no actual difference.
03

Reflect on the Results

Given that the true population mean is 35, we would expect the majority of tests to fail to reject the null hypothesis. And indeed, 47 out of 50 tests fail to reject the null hypothesis, which is a percentage of 94%. Therefore, these results align well with our expectations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, often symbolized as \( H_0 \), is a foundational aspect of hypothesis testing. It is essentially the statement that there is no effect or no difference, and any observed variation is due to sampling or experimental error.
In many tests, the null hypothesis asserts that the population parameter, such as the mean, is equal to a specific value. In the exercise example, the null hypothesis claims that the population mean \( \mu \) is 35.
When conducting hypothesis tests, the initial assumption is typically that the null hypothesis is true until evidence strong enough to oppose this claim can be provided. This acts as a benchmark against which the alternative hypothesis is tested. Therefore, understanding the null hypothesis is crucial because it sets the stage for statistical experimentation.
When you do not have convincing evidence to support the claim of the alternative hypothesis (which we'll discuss next), you fail to reject the null hypothesis.
Alternative Hypothesis
The alternative hypothesis, represented as \( H_1 \), is a statement that contradicts the null hypothesis. It proposes that there is some effect or difference that warrants attention. In hypothesis testing, the alternative hypothesis offers a new perspective or theory to be tested statistically.
In our example, the alternative hypothesis suggests that the population mean \( \mu \) is not equal to 35. This hypothesis encompasses any scenario where the mean is either greater than or less than 35, making it a two-sided test.
Formulating the alternative hypothesis requires careful consideration of what you aim to prove or discover through your research. The goal is to provide enough statistical evidence to support this alternative claim, thereby rejecting the null hypothesis.
Remember, lending support to the alternative hypothesis requires not just data, but data that significantly deviates from what is expected under the null hypothesis.
Significance Level
The significance level, denoted by \( \alpha \), is an essential component in hypothesis testing. It defines the probability threshold for determining when to reject the null hypothesis. Commonly set at 0.05, this means there's a 5% chance of rejecting the null hypothesis when it is actually true, which corresponds to a 95% confidence level in the results.
Significance levels help control what is known as 'Type I error', which we'll explore in the next section. They are selected based on how much risk one is willing to take in mistakenly identifying an effect that does not exist.
In our exercise, the significance level of 0.05 indicates a conservative approach, as it allows only a 5% probability of making a mistake by rejecting the null hypothesis if the population mean truly is 35. This level of caution is often chosen when the consequences of a wrong decision are serious.
The choice of a significance level is subjective and can vary depending on the context of the study, but care must be taken to balance the risk of errors with the likelihood of discovering true effects.
Type I Error
Type I error occurs when the null hypothesis is rejected even though it is true. It's like a false alarm where the test incorrectly indicates an effect or difference when there isn't one. In statistical terms, this is represented by the significance level \( \alpha \).
When conducting multiple tests, as stated in the original exercise with 50 hypothesis tests, the chance of committing a Type I error increases. However, a proper significance level reduces the risk of this error. For the exercise's significance level of 0.05, this means we accept a 5% chance of making such an error in any single test.
In practical terms, if the null hypothesis for a fair coin being flipped is that it will land heads or tails equally often, a Type I error would be declaring it biased when it isn't.
Understanding Type I errors advances your comprehension of testing limitations and prevents overconfident conclusions based solely on statistical outcomes. It's critical to interpret results within the context of this risk, ensuring a more informed scientific inquiry.

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Most popular questions from this chapter

Perform the following tests of hypothesis. a. \(H_{0}: \mu=285, \quad H_{1}: \mu<285, \quad n=55, \bar{x}=267.80, \quad s=42.90, \quad \alpha=.05\) b. \(H_{0}: \mu=10.70, \quad H_{1}: \mu \neq 10.70, \quad n=47, \bar{x}=12.025, \quad s=4.90, \quad \alpha=.01\) c. \(H_{0}: \mu=147,500, \quad H_{1}: \mu<147,500, n=41, \bar{x}=141,812, s=22,972, \alpha=.10\)

Records in a three-county area show that in the last few years, Girl Scouts sell an average of \(47.93\) boxes of cookies per year, with a population standard deviation of \(8.45\) boxes per year. Fifty randomly selected Girl Scouts from the region sold an average of \(46.54\) boxes this year. Scout leaders are concerned that the demand for Girl Scout cookies may have decreased. a. Test at the \(10 \%\) significance level whether the average number of boxes of cookies sold by all Girl Scouts in the three-county area is lower than the historical average. b. What will your decision be in part a if the probability of a Type I error is zero? Explain.

Briefly explain the conditions that must hold true to use the \(t\) distribution to make a test of hypothesis about the population mean.

The president of a university claims that the mean time spent partying by all students at this university is not more than 7 hours per week. A random sample of 40 students taken from this university showed that they spent an average of \(9.50\) hours partying the previous week with a standard deviation of \(2.3\) hours. Test at the \(2.5 \%\) significance level whether the president's claim is true. Explain your conclusion in words.

Consider \(H_{0}: p=.45\) versus \(H_{1}: p<.45\). a. A random sample of 400 observations produced a sample proportion equal to .42. Using \(\alpha=.025\), would you reject the null hypothesis? b. Another random sample of 400 observations taken from the same population produced a sample proportion of .39. Using \(\alpha=.025\), would you reject the null hypothesis?

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