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A random sample of 18 observations produced a sample mean of \(9.24\). Find the critical and observed values of \(z\) for each of the following tests of hypothesis using \(\alpha=.05 .\) The population standard deviation is known to be \(5.40\) and the population distribution is normal. a. \(H_{0}: \mu=8.5\) versus \(H_{1}: \mu \neq 8.5\) b. \(H_{0}: \mu=8.5\) versus \(H_{1}: \mu>8.5\)

Short Answer

Expert verified
The observed and critical values for each scenario will depend on the calculated observed Z score. The critical values for the tests are generally \(\pm 1.96\) for two-tailed tests and 1.645 for one-tailed tests in the positive direction.

Step by step solution

01

Identify Given Values

Observations (\(n\)) = 18, Sample Mean (\(\overline{x}\)) = 9.24, Population Standard Deviation (\(\sigma\)) = 5.40, Significance Level (\(\alpha\)) = 0.05, Hypothesized Population Mean (\(\mu\)) = 8.5
02

Calculate Observed Value of Z

Use the formula:\(Z_{obs} = \frac {(\overline{x} - \mu)}{(\sigma/ \sqrt{n})}\)Substitute the known values to calculate \(Z_{obs}\) for both scenarios.
03

Determine the Critical value of Z for a. \(H_{0}: \mu=8.5\) versus \(H_{1}: \mu \neq 8.5\)

This is a two-tailed test as \(H_{1}: \mu \neq 8.5\) indicates that the population mean can either be less than or greater than 8.5. For a two-tailed test with \(\alpha=.05\), the critical value for \(z\) is generally \(\pm 1.96\).
04

Determine the Critical value of Z for b. \(H_{0}: \mu=8.5\) versus \(H_{1}: \mu > 8.5\)

This is a one-tailed test as \(H_{1}: \mu > 8.5\) only considers the possibility that the population mean is greater than 8.5. For a one-tailed test with \(\alpha=.05\), the critical value for \(z\) is generally 1.645 for the upper tail.
05

Compare observed and critical values

For both test scenarios, compare the observed \(Z_{obs}\) value with the critical Z values. If \(|Z_{obs}|\) for a. or \(Z_{obs}\) for b. are greater than their respective critical \(Z\), we reject \(H_{0}\). Else, we do not reject \(H_{0}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Test
The z-test is a statistical method used to determine if there's a significant difference between sample data and a known population mean. It is particularly useful when the population standard deviation is known, which is the case in our example. Here, we use the z-test to test hypotheses about the average of a specific set of observations.
In general, the steps for conducting a z-test are straightforward:
  • Compute the z-statistic using the formula: \[ Z_{obs} = \frac{(\overline{x} - \mu)}{(\sigma/ \sqrt{n})} \]
  • Compare this observed z-value against a critical value that corresponds to your chosen significance level (often denoted as \( \alpha \)).

The calculated z-value tells us how many standard deviations our sample mean is from the population mean under the null hypothesis. In hypothesis testing, the z-test helps us to either reject or fail to reject the null hypothesis based on this figure.
Significance Level Explained
The significance level, represented as \( \alpha \), indicates the probability of rejecting the null hypothesis when it is actually true. It is a crucial component that helps to define our acceptance criteria for the hypothesis test.
In most hypothesis tests, a typical \( \alpha \) level is 0.05, meaning we have a 5% risk of concluding that there is an effect or difference when there is none. This level is often known as the level of risk, and helps to handle the concept of Type I error.
Choosing a significance level is a balance between risk and reliability. A smaller \( \alpha \) suggests higher confidence, but decreases the sensitivity to detect an actual effect, while a larger \( \alpha \) does the opposite.
Critical Value in Hypothesis Testing
The critical value is a threshold which the test statistic must exceed in order to reject the null hypothesis. It is determined based on the chosen significance level and the nature of the test (e.g., two-tailed or one-tailed).

In our problem, the critical z-value for the two-tailed test is approximately ±1.96, and for the one-tailed test, it is 1.645. These values can be found in standard z-tables. The decision rule is simple:
  • If our observed z-value surpasses the critical threshold (in magnitude), we reject the null hypothesis.
  • If it does not, then we cannot reject the null hypothesis.

This logic helps understand whether the sample mean indicates a significant difference from the hypothesized population mean.
Two-Tailed Test
A two-tailed test is used when changes in either direction away from the hypothesized parameter are considered significant. This type of test will check for both positive and negative differences.

In our example with the hypothesis \( H_{1}: \mu eq 8.5 \), it implies that the population mean could be either less than or greater than 8.5.
The critical z-value for a significance level of 0.05 is ±1.96. If the absolute value of our observed z-value is greater than this, we reject the null hypothesis.
Two-tailed tests are common in scientific research where deviation in either direction is of interest.
One-Tailed Test
In a one-tailed test, the hypothesis specifically targets a deviation in a single direction. This is appropriate when the direction of the anticipated effect is known and confidently one-sided.

Considering our hypothesis test of \( H_{1}: \mu > 8.5 \), we exclusively investigate if the sample mean is significantly greater than the hypothesized mean. For such a test with a significance level of 0.05, the critical value of z translates to approximately 1.645.

If our observed z-value is greater than this critical value, we conclude by rejecting the null hypothesis. A one-tailed test thus is precise and direct, making it efficient when the direction of interest is clear and one-sided.

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Most popular questions from this chapter

In Las Vegas and Atlantic City, New Jersey, tests are performed often on the various gaming devices used in casinos. For example, dice are often tested to determine if they are balanced. Suppose you are assigned the task of testing a die, using a two-tailed test to make sure that the probability of a 2 -spot is \(1 / 6 .\) Using the \(5 \%\) significance level, determine how many 2 -spots you would have to obtain to reject the null hypothesis when your sample size is \(\begin{array}{lll}\text { a. } 120 & \text { b. } 1200 & \text { c. } 12,000\end{array}\) Calculate the value of \(\hat{p}\) for each of these three cases. What can you say about the relationship between (1) the difference between \(\hat{p}\) and \(1 / 6\) that is necessary to reject the null hypothesis and (2) the sample size as it gets larger?

A random sample of 14 observations taken from a population that is normally distributed produced a sample mean of \(212.37\) and a standard deviation of \(16.35 .\) Find the critical and observed values of \(t\) and the ranges for the \(p\) -value for each of the following tests of hypotheses, using \(\alpha=.10\). a. \(H_{0}: \mu=205\) versus \(H_{1}: \mu \neq 205\) b. \(H_{0}: \mu=205\) versus \(H_{1}: \mu>205\)

In an observational study at Turner Field in Atlanta, Georgia, \(43 \%\) of the men were observed not washing their hands after going to the bathroom (see Exercise \(7.80\) ). Suppose that in a random sample of 95 men who used the bathroom at Camden Yards in Baltimore, Maryland, 26 did not wash their hands. a. Using the critical-value approach and \(\alpha=.10\), test whether the percentage of all men at Camden Yards who use the bathroom and do not wash their hands is less than \(43 \%\). b. How do you explain the Type I error in part a? What is the probability of making this error in part a? c. Calculate the \(p\) -value for the test of part a. What is your conclusion if \(\alpha=.10 ?\)

The print on the packages of 100-watt General Electric soft-white lightbulbs states that these lightbulbs have an average life of 750 hours. Assume that the standard deviation of the lengths of lives of these lightbulbs is 50 hours. A skeptical consumer does not think these lightbulbs last as long as the manufacturer claims, and she decides to test 64 randomly selected lightbulbs. She has set up the decision rule that if the average life of these 64 lightbulbs is less than 735 hours, then she will conclude that GE has printed too high an average length of life on the packages and will write them a letter to that effect. Approximately what significance level is the consumer using? Approximately what significance level is she using if she decides that GE has printed too high an average length of life on the packages if the average life of the 64 lightbulbs is less than 700 hours? Interpret the values you get.

The mean balance of all checking accounts at a bank on December 31,2009, was \(\$ 850 .\) A random sample of 55 checking accounts taken recently from this bank gave a mean balance of \(\$ 780\) with a standard deviation of \(\$ 230 .\) Using the \(1 \%\) significance level, can you conclude that the mean balance of such accounts has decreased during this period? Explain your conclusion in words. What if \(\alpha=.025\) ?

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