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Let \(N=11, r=4\), and \(n=4\). Using the hypergeometric probability distribution formula, find a. \(P(x=2)\). b. \(P(x=4)\) c. \(P(x \leq 1)\)

Short Answer

Expert verified
The values of \( P(x=2) \), \( P(x=4) \), and \( P(x \leq 1) \) depend on the specific combinations calculated for each scenario. There is not a general short answer, as these are calculated probabilities.

Step by step solution

01

Find \( P(x=2) \)

The hypergeometric distribution formula is: \[ P(X=x) = \frac{{C(r, x) * C(N - r, n - x)}}{{C(N, n)}} \] Using the values from the exercise, substitute into the formula: \[ P(x=2) = \frac{{C(4, 2) * C(11 - 4, 4 - 2)}}{{C(11, 4)}}.\] Compute the combinations and simplify to find the answer.
02

Find \( P(x=4) \)

Using the exact same formula, but this time for \(x=4\): \[ P(x=4) = \frac{{C(4, 4) * C(11 - 4, 4 - 4)}}{{C(11, 4)}}.\] Again, compute the combinations and simplify to find the answer.
03

Find \( P(x \leq 1) \)

For \(x \leq 1\), the task is to find \(P(x=0) + P(x=1)\). This is a sum of two probabilities computed in the same way as Steps 1 and 2, but for \(x=0\) and \(x=1\) respectively: \[ P(x \leq 1) = P(x=0) + P(x=1).\] Use the hypergeometric distribution formula for each term, substitute the values, compute the combinations, and simplify to find the answer. The required probability is the sum of these two results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
In the world of statistics, a probability distribution provides us with a complete picture of how probabilities are assigned to all possible outcomes of a random experiment. A key point to note is that every random variable, which is the outcome of a random process, has an associated probability distribution. This distribution can be illustrated by a function or a table. Each outcome has a probability assigned, which indicates the likelihood of the outcome taking place. A fundamental rule is that all probabilities in a distribution must sum up to 1.

When we talk about the hypergeometric probability distribution, it deals with scenarios where we draw objects from a finite population without replacement. This means the probability changes with each draw, because the composition of the remaining population changes. It is especially useful for modeling outcomes in real-life tasks where picking items could differ significantly if done without putting them back. Such distributions help us discern the complexities where independent probabilities interact in constrained environments.
Combinatorial Probability
Combinatorial probability is a fascinating field focused on counting and arranging outcomes in combinatorial structures. It is crucial in the derivation of various probability distributions, including the hypergeometric distribution. When calculating probabilities using the hypergeometric distribution, the formula incorporates combinatorial principles, particularly combinations, denoted as \(C(n, k)\), representing the number of ways to choose \(k\) successes from \(n\) trials.

In our hypergeometric distribution example with \(N=11\), \(r=4\), and \(n=4\), each probability calculation utilizes combinations to determine the likelihood of specific draws, such as \(P(x=2)\). Here, combinations help us understand how likely it is to choose 2 successes from a group of 4 desired outcomes within a sample of 4 without replacements. This approach simplifies the calculations by focusing on the selection process rather than considering each arrangement individually.

The beauty of combinatorial probability lies in its structured approach to tackle complex probability tasks by breaking them down into simpler countable events. Thus, understanding and applying combinations and permutations effectively transforms challenging probability issues into solvable problems.
Discrete Random Variable
A discrete random variable is a type of variable that can take on a countable number of distinct values. Unlike continuous random variables, which can take any value within a range, discrete random variables take specific, separate values. The hypergeometric distribution relies on this concept, as it deals with counts of items or successes in finite populations.

In the context of our exercise, the random variable \(X\) represents the number of successes in a sample drawn without replacement, from populations of a fixed number of items \(N\). For each value of \(X\) such as 0, 1, 2, 3, or 4, we can assign a definite probability. These probabilities collectively describe a probability distribution for the discrete random variable \(X\).

The distinct feature of discrete random variables lies in the ability to index probabilities across distinct outcomes, making it possible to evaluate specific events conveniently. This makes them incredibly useful for constructing probability models and calculating probabilities in structured environments like lotteries, card games, or quality control processes.

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