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Let \(N=14, r=6\), and \(n=5 .\) Using the hypergeometric probability distribution formula, find a. \(P(x=4)\) b. \(P(x=5)\) c. \(P(x \leq 1)\)

Short Answer

Expert verified
In order to have the final answers, you need to calculate the binomial coefficients and substitute them into the hypergeometric distribution formula for each part of the problem (a, b, c), resulting in respective probabilities. Make sure to add up the probabilities for \(x = 0\) and \(x = 1\) for the third part (c).

Step by step solution

01

Understand the hypergeometric distribution

The hypergeometric distribution gives the probability of \(x\) successes (random draws for which the object drawn has a specified feature) in \(n\) draws, without replacement, from a finite population of size \(N\) that contains exactly \(r\) objects with that feature. The formula is \[ P(x) = \frac{{C(r, x) \cdot C(N-r, n-x)}}{C(N, n)} \]\n This formula includes binomial coefficients, denoted \(C(a, b)\), which imply choosing \(b\) from \(a\).
02

Calculate \(P(x=4)\)

Substitute \(N=14\), \(r=6\), \(n=5\) and \(x=4\) into the formula:\n \[ P(x=4) = \frac{{C(6, 4) \cdot C(14-6, 5-4)}}{C(14, 5)} = \frac{{C(6, 4) \cdot C(8, 1)}}{C(14, 5)} \]\n Calculate the binomial coefficients and after that the resulting probability.
03

Calculate \(P(x=5)\)

Substitute \(N=14\), \(r=6\), \(n=5\) and \(x=5\) into the formula:\n \[ P(x=5) = \frac{{C(6, 5) \cdot C(14-6, 5-5)}}{C(14, 5)} = \frac{{C(6, 5) \cdot C(8, 0)}}{C(14, 5)} \]\n Calculate the binomial coefficients and after that the resulting probability.
04

Calculate \(P(x \leq 1)\)

We need to add up probabilities for \(P(x=0)\) and \(P(x=1)\). Substitute \(N=14\), \(r=6\), \(n=5\) and \(x=0\), \(x=1\) into the formula:\n \[ P(x = 0) = \frac{{C(6, 0) \cdot C(14-6, 5-0)}}{C(14, 5)} = \frac{{C(6, 0) \cdot C(8, 5)}}{C(14, 5)} \]\n \[ P(x = 1) = \frac{{C(6, 1) \cdot C(14-6, 5-1)}}{C(14, 5)} = \frac{{C(6, 1) \cdot C(8, 4)}}{C(14, 5)} \]\n Calculate the binomial coefficients for both, add up their results to get the total probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
Probability distributions are mathematical functions that provide the probabilities of occurrence of different possible outcomes in an experiment. In the case of a hypergeometric distribution, it specifically models the probability of a given number of successes in a sequence of draws from a finite population. The success here is defined as drawing an item that possesses a particular attribute you are interested in.

For instance, if you want to know the likelihood of drawing exactly 4 specific cards out of a hand of 5 from a deck of 14 cards, in which 6 are of interest—this would follow a hypergeometric distribution.
  • This distribution is applicable when there are no replacements, meaning each draw affects subsequent probabilities.
  • It's handy in scenarios where the population size is relatively small.
Understanding this concept is vital in interpreting the likelihood of various outcomes in constrained environments where the population has defined limits.
Binomial Coefficients
Binomial coefficients are crucial in calculating probabilities within hypergeometric distributions. They represent the number of ways to choose a subset of items from a larger set, without considering the order. Mathematically, it's expressed as \(C(a, b)\), which denotes choosing \(b\) items from \(a\).
  • In hypergeometric distribution, you'll encounter these coefficients multiple times as they define possible outcomes of selected draws.
  • These coefficients are integral to calculating the numerator and denominator in the hypergeometric formula, \( P(x) = \frac{{C(r, x) \cdot C(N-r, n-x)}}{C(N, n)} \).
Let's take an example: to find \( C(6, 4) \), you determine how many ways you can choose 4 items out of 6, giving you parts of the probability of a particular number of successes. Knowing how to compute these ensures you can tackle problems involving combinations effectively.
Finite Population
A finite population in statistical terms refers to a population of a limited size, where every element can be accounted for. In hypergeometric distribution, this concept is integral because the probabilities are built upon drawing from a clearly defined and closed group of items.
  • The total number of items \(N\) is fixed, as seen in the example where \(N = 14\).
  • Having a finite population means that the outcome of one draw impacts what is available the in subsequent ones, reflecting dependency in probabilities.
This contrasts with infinite populations where probabilities remain constant irrespective of prior outcomes.
Within such finite settings, it's possible to exactly calculate probabilities without estimations, since all elements contribute to the final result.
Random Draws
Random draws in the context of a hypergeometric distribution refer to each selection made from the finite population. Each draw is independent in its execution yet affects the subsequent draw due to the finite nature of the population.
  • Once an item is drawn, it affects the probability of subsequent draws since the items aren't replaced.
  • This is pivotal for problems where the understanding of probability is necessary for successive events.
  • For example, in multiple-choice scenarios or card games, understanding each random draw and its impact helps in predicting outcomes accurately.
Considering random draws is essential for assessing real-world scenarios like quality control, where pulling items for testing affects the pool left behind. A strong grasp on this idea allows better planning and accurate prediction of probable outcomes.

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