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The probability that a randomly selected elementary or secondary school teacher from a city is a female is \(.68\), holds a second job is \(.38\), and is a female and holds a second job is \(.29\). Find the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job.

Short Answer

Expert verified
The probability that a randomly selected elementary or secondary school teacher from this city is a female or holds a second job is 0.77.

Step by step solution

01

Define the Given Information

We can represent the given information with the following variables: let F be the event 'is female': \(P(F) = 0.68\). Let J be the event 'holds a second job': \(P(J) = 0.38\), and let F & J be the combined event: 'is a female and holds a second job': \(P(F \cap J) = 0.29\).
02

Apply the Formula

We are looking for the probability that a randomly selected teacher is either a female or holds a second job. This is represented as \(P(F \cup J)\). The formula for the union of two events is \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). Applying this formula to our problem, we get: \(P(F \cup J) = P(F) + P(J) - P(F \cap J)\).
03

Compute the Probability

Substitute the given values into the formula: \(P(F \cup J) = 0.68 + 0.38 - 0.29 = 0.77\). So, the probability that a randomly selected elementary or secondary school teacher from this city is either a female or holds a second job is 0.77.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Events
Understanding the union of events is crucial when dealing with probabilities involving multiple events. In probability theory, the union of two events A and B, represented as \(P(A \cup B)\), refers to the likelihood of either event A occurring, event B occurring, or both events happening simultaneously.
The probability of the union of two events can be calculated using the formula:
  • \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
The principle behind this formula is simple. We begin by adding the probabilities of both events because, in a union, we consider occurrences from both sets. However, since the intersection \(P(A \cap B)\) is counted twice (once in \(P(A)\) and once in \(P(B)\)), it must be subtracted once to avoid overcounting.
For example, if we want to find the probability that a randomly selected teacher is either a female or holds a second job, we utilize the union formula. This way, we accurately account for teachers who are both female and hold a second job.
Intersection of Events
The intersection of events is a fundamental concept for calculating the probability that two events occur simultaneously. This is symbolized as \(P(A \cap B)\), where both event A and event B occur.

To determine this, consider the joint probability: the likelihood that both specified conditions are met.
For instance, in our problem, it refers to the probability \(P(F \cap J)\) of a teacher being both female and holding a second job. In practical terms, this scenario captures overlap where both characteristics co-exist. Such calculations help in accurately understanding complex situations where multiple criteria can be true at once.

Thinking in terms of intersections helps to refine probabilities when noticing shared attributes between events. This ensures no overestimation happens when considering probabilities of combined events.
Elementary Probability Concepts
Elementary probability concepts lay the foundational understanding necessary for handling more complex probability scenarios. At the core, probability is a measure of how likely an event is to occur, represented as a number between 0 (impossible event) and 1 (certain event).

Some basic principles include:
  • The probability of an event \(A\), denoted \(P(A)\), quantifies the chance of occurrence.
  • The sum of probabilities of all possible outcomes always equals 1, ensuring all potential occurrences are considered.
  • If two events cannot happen simultaneously, they are called mutually exclusive, simplifying calculations as \(P(A \cap B) = 0\).
Getting comfortable with these principles is key to tackling more involved probability questions. By understanding basic definitions and relationships like unions and intersections, you can approach probability problems with confidence and clarity.

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Most popular questions from this chapter

Given that \(A\) and \(B\) are two independent events, find their joint probability for the following. a. \(P(A)=.61\) and \(P(B)=.27\) b. \(P(A)=.39\) and \(P(B)=.63\)

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