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In a group of 10 persons, 4 have a type A personality and 6 have a type B personality. If two persons are selected at random from this group, what is the probability that the first of them has a type A personality and the second has a type B personality? Draw a tree diagram for this problem

Short Answer

Expert verified
The probability that the first person selected has a type A personality and the second has a type B personality is 0.267. A tree diagram for this problem would start with a branch representing the type A personality selection (probability 0.4), followed by a branch for the type B personality selection (probability 0.67)

Step by step solution

01

Understanding the problem

Firstly, it's important to visualize the problem. Initially, the group consists of 10 persons: 4 with a type A personality and 6 with a type B personality. A type A personality person is selected first, and then a type B personality person is selected.
02

Calculating the probability of selecting a Type A personality first

The probability of selecting a type A personality person is the number of type A personality persons divided by the total number of persons. So that would be \(\frac{4}{10} = 0.4\).
03

Calculating the probability of selecting a Type B personality second

After the first selection, a type B personality person is selected but the group now has only 9 persons. The probability is now the number of type B personality persons divided by the new total number of persons. So that would be \(\frac{6}{9} = 0.67\).
04

Calculating the overall probability

The overall probability of both these events happening is the product of the individual probabilities. So, the overall probability would be \(0.4 × 0.67 = 0.267.\)
05

Drawing the tree diagram

A tree diagram for this problem would have two levels. The first level represents the type A personality selection with a probability of 0.4, and the second level represents the type B personality selection (after a type A has been selected) with a probability of 0.67.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Tree Diagrams
A tree diagram is a visual tool used in probability theory that helps outline all possible outcomes of an event. This is particularly helpful when dealing with multiple steps or stages in an experiment. For instance, in the context of our problem, we have an initial selection process followed by another independent selection process.

The tree begins with a single node, representing the starting point or the first choice. Branches then extend from this node to represent possible choices or outcomes. As you move further down the tree, each subsequent level of branches represents another step or stage in the experiment.

  • Each path through the tree can be traced from start to finish, defining a complete outcome of the experiment.
  • To find the probability of any complete path (i.e., a series of events happening in sequence), you multiply the probabilities along that path together.
Tree diagrams simplify complex probability problems, making it easier to visualize and calculate probabilities, like finding the probability of picking one person with type A personality followed by one with type B.
Exploring Conditional Probability
Conditional probability is the probability of an event occurring, given that another event has occurred. In the context of our exercise, the selection of the second person depends on the outcome of the first selection.

Here's what makes conditional probability unique:
  • We focus on the probability of the second event, given a specific outcome of the first event.
  • The first event affects the sample space of the second event — in our case, reducing the total number of people being considered.
For example, after selecting a type A personality, the probability landscape changes because now we are choosing from only 9 remaining people. This reduced sample affects how likely we are to pick someone with a type B personality.

By calculating these probabilities step-by-step, we can then multiply them to find the overall probability of both events occurring in sequence.
Diving into Personality Types
Personality types, such as Type A and Type B, are categories used to describe different personality characteristics. Understanding these is useful in psychology and helps in organizing and predicting behaviors in various settings.

Type A personality is often characterized by traits such as:
  • High competitiveness
  • Urgency about time
  • Strong drive and ambition
Meanwhile, Type B personalities are typically seen as:
  • More relaxed and easy-going
  • Less stressed about time pressures
  • Laid-back in their approach
Having a mix of these personality types in a group, like the one in our exercise, provides an interesting social dynamic and we can explore probabilities related to selecting individuals from such a mixed group.

Understanding these personality traits can also provide context when considering interactions between different individuals, which might, for example, affect team performance or life choices.

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Most popular questions from this chapter

In a class of 35 students, 13 are seniors, 9 are juniors, 8 are sophomores, and 5 are freshmen. If one student is selected at random from this class, what is the probability that this student is a. a junior? b. a freshman?

What is meant by the joint probability of two or more events? Give one example.

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A consumer agency randomly selected 1700 flights for two major airlines, \(\mathrm{A}\) and \(\mathrm{B}\). The following table gives the two-way classification of these flights based on airline and arrival time. Note that "less than 30 minutes late" includes flights that arrived early or on time. $$\begin{array}{cccc} \hline & \begin{array}{c} \text { Less Than 30 } \\ \text { Minutes Late } \end{array} & \begin{array}{c} \mathbf{3 0} \text { Minutes to } \\ \text { 1 Hour Late } \end{array} & \begin{array}{c} \text { More Than } \\ \text { 1 Hour Late } \end{array} \\ \hline \text { Airline A } & 429 & 390 & 92 \\ \text { Airline B } & 393 & 316 & 80 \\ \hline \end{array}$$ a. Suppose one flight is selected at random from these 1700 flights. Find the following probabilities. i. \(P(\) more than 1 hour late and airline \(\mathrm{A}\) ) ii. \(P(\) airline \(\mathrm{B}\) and less than 30 minutes late) b. Find the joint probability of events " 30 minutes to 1 hour late" and "more than 1 hour late." Is this probability zero? Explain why or why not.

The probability that a student graduating from Suburban State University has student loans to pay off after graduation is .60. The probability that a student graduating from this university has student loans to pay off after graduation and is a male is \(.24 .\) Find the conditional probability that a randomly selected student from this university is a male given that this student has student loans to pay off after graduation.

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