/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 A company is to hire two new emp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A company is to hire two new employees. They have prepared a final list of eight candidates, all of whom are equally qualified. Of these eight candidates, five are women. If the company decides to select two persons randomly from these eight candidates, what is the probability that both of them are women? Draw a tree diagram for this problem.

Short Answer

Expert verified
The probability that the company will hire two women from the pool of eight candidates (from which five are women) is approximately 0.357 or 35.7%.

Step by step solution

01

Calculate Total Combinations

Calculate the total number of combinations of choosing 2 employees from the pool of 8 candidates. Using the combination formula, it is calculated as \(8C2 = \frac{8!}{2!(8-2)!} = 28\) combinations.
02

Calculate Combinations with Desired Outcome

Now, calculate the combinations with the desired outcome -- that both employees are women. There are 5 women among the 8 candidates. The number of combinations of 2 employees that can be formed from 5 women is calculated similarly as \(5C2 = \frac{5!}{2!(5-2)!} = 10\) combinations.
03

Calculate Probability

Finally, calculate the probability of the desired outcome by dividing the number of combinations with a desired outcome by the total number of combinations. The probability of the company hiring two women is therefore \(P = \frac{5C2}{8C2} = \frac{10}{28} = 0.357143\) to six decimal places.
04

Construct a Tree Diagram

A tree diagram for this problem can be created using the probability calculated. The first branch would be the probability of the first person selected being a woman (5/8), with the corresponding branch being the probability of the first person being a man (3/8). Each branch would then further branch into two parts - one for the probability of the second person being a woman, and one for the probability of the second person being a man. These probabilities would differ slightly from the original probabilities, as the pool has decreased by one. When multiplied together, the branches resulting in two women being selected should total to the calculated probability (0.357143).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There are a total of 160 practicing physicians in a city. Of them, 75 are female and 25 are pediatricians. Of the 75 females, 20 are pediatricians. Are the events "female" and "pediatrician" independent? Are they mutually exclusive? Explain why or why not.

A student is to select three classes for next semester. If this student decides to randomly select one course from each of eight economics classes, six mathematics classes, and five computer classes, how many different outcomes are possible?

Jason and Lisa are planning an outdoor reception following their wedding. They estimate that the probability of bad weather is .25, that of a disruptive incident (a fight breaks out, the limousine is late, etc.) is 15 , and that bad weather and a disruptive incident will occur is .08. Assuming these estimates are correct, find the probability that their reception will suffer bad weather or a disruptive incident.

An insurance company has information that \(93 \%\) of its auto policy holders carry collision coverage or uninsured motorist coverage on their policies. Eighty percent of the policy holders carry collision coverage, and \(60 \%\) have uninsured motorist coverage. a. What percentage of these policy holders carry both collision and uninsured motorist coverage? b. What percentage of these policy holders carry neither collision nor uninsured motorist coverage? c. What percentage of these policy holders carry collision but not uninsured motorist coverage?

Powerball is a game of chance that has generated intense interest because of its large jackpots. To play this game, a player selects five different numbers from 1 through 59 , and then picks a Powerball number from 1 through 39 . The lottery organization randomly draws 5 different white balls from 59 balls numbered 1 through 59 , and then randomly picks a Powerball number from 1 through \(39 .\) Note that it is possible for the Powerball number to be the same as one of the first five numbers. a. If the player's first five numbers match the numbers on the five white balls drawn by the lottery organization and the player's Powerball number matches the Powerball number drawn by the lottery organization, the player wins the jackpot. Find the probability that a player who buys one ticket will win the jackpot. (Note that the order in which the five white balls are drawn is unimportant.) b. If the player's first five numbers match the numbers on the five white balls drawn by the lottery organization, the player wins about \(\$ 200,000\). Find the probability that a player who buys one ticket will win this prize.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.