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Given that \(A\) and \(B\) are two independent events, find their joint probability for the following. a. \(P(A)=.61\) and \(P(B)=.27\) b. \(P(A)=.39\) and \(P(B)=.63\)

Short Answer

Expert verified
a. The joint probability for the first set of values (P(A)=.61 and P(B)=.27) is 0.1647. b. The joint probability for the second set of values (P(A)=.39 and P(B)=.63) is 0.2457.

Step by step solution

01

Understand the concept of independent events

Two events are said to be independent if the occurrence of one event does not affect the occurrence of the other event. The joint probability for the two independent events is the product of their individual probabilities.
02

Find the joint probability for the first set of values

Given that P(A) = 0.61 and P(B) = 0.27. The joint probability, \(P(A \cap B)\), is the product of \(P(A)\) and \(P(B)\) which can be predicted as \(P(A \cap B) = P(A) \cdot P(B) = 0.61 * 0.27 = 0.1647\)
03

Find the joint probability for the second set of values

Given that P(A) = 0.39 and P(B) = 0.63. The joint probability, \(P(A \cap B)\), is the product of \(P(A)\) and \(P(B)\) which can be predicted as \(P(A \cap B) = P(A) \cdot P(B) = 0.39 *0.63 = 0.2457\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joint Probability
Joint probability refers to the likelihood of two events happening at the same time. Consider two events, say, event A and event B. In probability terms, we denote the joint probability of these two events as \(P(A \cap B)\). This notation signifies the probability that both events A and B occur simultaneously.
It's key to remember that when dealing with joint probability, especially when the events are independent, their outcome is calculated by considering both probabilities together in a specific way. But why is it important? Joint probability helps us understand how two scenarios can happen together and is significant in areas like statistics and risk analysis. By grasping joint probability, you're learning to see how different elements in probability might intersect and influence outcomes in various fields.
Product Rule
The product rule is a fundamental principle used widely in probability theory, particularly suited for independent events. When two events are independent, it implies that the occurrence of one event doesn't affect the other. Therefore, one straightforward way to find their joint probability is by using the product rule.
To use the product rule for independent events, simply multiply their individual probabilities. Mathematically, this is expressed as \(P(A \cap B) = P(A) \cdot P(B)\). It's a neat and quick way to calculate the joint probability without complicated calculations, provided the independence assumption holds.
The product rule is powerful because of its simplicity, offering a straightforward method to predict outcomes without heavy computation. For students and professionals alike, it's a handy tool in probability theory.
Probability Theory
Probability theory is a branch of mathematics that deals with the analysis of random phenomena. Within this theory, several core concepts help us to understand and predict the likelihood of various outcomes.
  • Basic probability: This refers to calculating the likelihood of simple events occurring, typically within a range from 0 (impossible) to 1 (certain).
  • Conditional probability: This involves finding the probability of an event occurring given that another event has already occurred. It's about determining how our information changes the likelihood of outcomes.
  • Independent and dependent events: These are two classifications of events. Independent events are those where the occurrence of one doesn't affect the likelihood of another, whereas dependent events do have an influence on each other.
Probability theory serves as a backbone for many real-world applications, including statistics, finance, and science. It equips you with the tools to make informed predictions and decisions based on available data, making it a crucial part of understanding and navigating the uncertain world we live in.

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Most popular questions from this chapter

A thief has stolen Roger's automatic teller machine (ATM) card. The card has a four-digit personal identification number (PIN). The thief knows that the first two digits are 3 and 5 , but he does not know the last two digits. Thus, the PIN could be any number from 3500 to 3599 . To protect the customer, the automatic teller machine will not allow more than three unsuccessful attempts to enter the PIN. After the third wrong PIN, the machine keeps the card and allows no further attempts. a. What is the probability that the thief will find the correct PIN within three tries? (Assume that the thief will not try the same wrong PIN twice.) b. If the thief knew that the first two digits were 3 and 5 and that the third digit was either 1 or 7 , what is the probability of the thief guessing the correct PIN in three attempts?

Given that \(P(A)=.30\) and \(P(A\) and \(B)=.24\), find \(P(B \mid A)\).

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When is the following addition rule used to find the probability of the union of two events \(A\) and \(B\) ? $$P(A \text { or } B)=P(A)+P(B)$$ Give one example where you might use this formula.

Let \(A\) be the event that a number less than 3 is obtained if we roll a die once. What is the probability of \(A ?\) What is the complementary event of \(A\), and what is its probability?

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