/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 For the following pairs, indicat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For the following pairs, indicate which do not comply with the rules for setting up hypotheses, and explain why: a. \(H_{0}: \mu=15, H_{a}: \mu=15\) b. \(H_{0}: p=.4, H_{a}: p>.6\) c. \(H_{0}: \mu=123, H_{a}: \mu<123\) d. \(H_{0}: \mu=123, H_{a}: \mu=125\) e. \(H_{0}: \hat{p}=.1, H_{a}: \hat{p} \neq .1\)

Short Answer

Expert verified
Sets a and d do not comply with the rules of hypothesis testing. In set a, null and alternative hypotheses are equal which is incorrect. In set d, alternative hypothesis is incorrectly specified as it does not cover all possible outcomes.

Step by step solution

01

Analyze Set a

Set a is \(H_{0}: \mu=15, H_{a}: \mu=15\). Null and alternate hypotheses are identical which is not right. The null hypothesis allows for equality but the alternative hypothesis should not equal the null hypothesis.
02

Analyze Set b

Set b is \(H_{0}: p=.4, H_{a}: p>.6\). This set is correctly formed. The null hypothesis includes \( \leq 0.6 \) implying all values up to, and including 0.6. The alternate hypothesis implies all values greater than 0.6, thus the null and alternate hypotheses are mutually exclusive and cover all possible outcomes.
03

Analyze Set c

Set c is \(H_{0}: \mu=123, H_{a}: \mu<123\). This set is correctly formed. The null hypothesis includes \( \mu \geq 123 \) and the alternate hypothesis covers the remaining possibilities.
04

Analyze Set d

Set d is \(H_{0}: \mu=123, H_{a}: \mu=125\). The null hypothesis allows for equality while the alternative hypothesis includes a specific value. Hypotheses must include all possible outcomes and these do not. Alternative hypothesis is incorrectly specified and should be include less than, not equals to, greater than or not equals to.
05

Analyze Set e

Set e is \(H_{0}: \hat{p}=.1, H_{a}: \hat{p} \neq .1\). This set is correctly formed. The null hypothesis covers the possibility of equality, \( =.1 \), while the alternate hypothesis includes all other possibilities \( \neq .1 \).
06

Conclusion

Out of the 5 presented pairs, sets a and d do not comply with the rules for setting up hypotheses. Set a has identical null and alternative hypotheses which is incorrect. Set d does not cover all possible outcomes in its null and alternative hypotheses.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, symbolically represented as \( H_{0} \), is a fundamental concept in hypothesis testing. It's a statement proposing that no significant difference or effect exists in a particular situation or that any observed differences are attributable to random chance. For example, if we are testing a new drug's effectiveness, the null hypothesis might state that the drug has no effect on patients compared to a placebo.

From the exercise, it's clear that the null hypothesis must be set up to allow for equality (\(\bmu = 15\)) or the status quo. It acts as the default or baseline condition and is presumed true until evidence suggests otherwise. The null hypothesis should always be clear, specific, and testable, covering a single possibility around a population parameter - typically involving terms like \( = \), \(\bgeq\), or \(\bleq\). When a null hypothesis is set optimally, it paves the way for the alternative hypothesis to challenge it with contrasting predictions.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_{a} \) or \( H_{1} \), is the counterpart to the null hypothesis in statistical testing. It represents what researchers aim to demonstrate or suspect to be true—namely, that a significant difference or effect does exist.

In the case of \( H_{0}: \bmu=15, H_{a}: \bmu!=15 \) we see an example where the alternative hypothesis is correctly stating what the researcher is trying to confirm or deny - that \( \bmu \) is different from 15. Alternative hypotheses can take on different forms, such as \( > \), \( < \), or \( eq \), and should be mutually exclusive with the null hypothesis, as they represent opposing possibilities that cannot both be true at the same time. Properly stated, the alternative hypothesis gives direction to the research and uses statistical evidence to refute the null hypothesis.
Statistical Hypotheses
Statistical hypotheses are the foundational blocks of hypothesis testing, which is a method used to decide whether to accept or reject a specific statement about a parameter based on sample data. These hypotheses need to be mutually exclusive and collectively exhaustive. This means they won't overlap (\(\bmu=123\) vs. \(\bmu<123\)) and will cover all possible outcomes.

Illustrating with example c from the exercise, \( H_{0}: \bmu=123, H_{a}: \bmu<123 \), it demonstrates a proper setup where the statistical hypotheses are exclusive and encompass every potential scenario. A well-formulated pair of statistical hypotheses will dictate the structure of the test and determine the adequacy of the evidence required to persuade us in favor of one over the other.
Mutually Exclusive Outcomes
In the context of hypothesis testing, mutually exclusive outcomes mean that the scenarios represented by the null and alternative hypotheses cannot happen at the same time. They cover different prospective realities, so if one is true, the other must be false. This principle is crucial for the clarity and validity of the hypothesis testing process.

Example b from the step-by-step solution (\( H_{0}: p=0.4, H_{a}: p>0.6 \)) shows that the set of outcomes covered by the null and alternative hypotheses don't overlap, making them mutually exclusive. The null hypothesis encompasses all proportions \(\bleq 0.6\), while the alternative hypothesis includes those \(\b> 0.6\). Together, they cover all possible values for \(\bp\) ensuring that any outcome will support either \( H_{0} \) or \( H_{a} \) - but not both. This clear demarcation allows for straightforward decision-making: any evidence that falls into the realm of the alternative hypothesis will challenge and potentially reject the null hypothesis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The mean length of long-distance telephone calls placed with a particular phone company was known to be \(7.3\) minutes under an old rate structure. In an attempt to be more competitive with other long-distance carriers, the phone company lowered long-distance rates, thinking that its customers would be encouraged to make longer calls and thus that there would not be a big loss in revenue. Let \(\mu\) denote the mean length of long-distance calls after the rate reduction. What hypotheses should the phone company test to determine whether the mean length of long-distance calls increased with the lower rates?

In a survey of 1005 adult Americans, \(46 \%\) indicated that they were somewhat interested or very interested in having web access in their cars (USA Today. May 1\. 2009). Suppose that the marketing manager of a car manufacturer claims that the \(46 \%\) is based only on a sample and that \(46 \%\) is close to half, so there is no reason to believe that the proportion of all adult Americans who want car web access is less than .50. Is the marketing manager correct in his claim? Provide statistical evidence to support your answer. For purposes of this exercise, assume that the sample can be considered as representative of adult Americans.

Do state laws that allow private citizens to carry concealed weapons result in a reduced crime rate? The author of a study carried out by the Brookings Institu-tion is reported as saying, "The strongest thing I could say is that I don't see any strong evidence that they are reducing crime" (San Luis Obispo Tribune, January \(23 .\) 2003). a. Is this conclusion consistent with testing \(H_{0}:\) concealed weapons laws reduce crime versus \(H_{a}:\) concealed weapons laws do not reduce crime or with testing \(H_{0}:\) concealed weapons laws do not reduce crime versus \(H_{a}:\) concealed weapons laws reduce crime Explain. b. Does the stated conclusion indicate that the null hypothesis was rejected or not rejected? Explain.

The report "Highest Paying Jobs for \(2009-10\) Bachelor's Degree Graduates" (National Association of Colleges and Employers, February 2010 ) states that the mean yearly salary offer for students graduating with a degree in accounting in 2010 is \(\$ 48,722\). Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of \(\$ 49,850\) and a standard deviation of \(\$ 3300\). Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the 2010 national average of \(\$ 48,722\) ? Test the relevant hypotheses using \(\alpha=.05\).

Let \(\mu\) denote the true average lifetime (in hours) for a certain type of battery under controlled laboratory conditions. A test of \(H_{0}: \mu=10\) versus \(H_{a}:\) \(\mu<10\) will be based on a sample of size \(36 .\) Suppose that \(\sigma\) is known to be \(0.6\), from which \(\sigma_{\bar{x}}=.1\). The appropriate test statistic is then $$ z=\frac{\bar{x}-10}{0.1} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.