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To determine whether the pipe welds in a nuclear power plant meet specifications, a random sample of welds is selected and tests are conducted on each weld in the sample. Weld strength is measured as the force required to break the weld. Suppose that the specifications state that the mean strength of welds should exceed \(100 \mathrm{lb} / \mathrm{in}^{2} .\) The inspection team decides to test \(H_{0}: \mu=100\) versus \(H_{a}: \mu>100 .\) Explain why this alternative hypothesis was chosen rather than \(\mu<100\).

Short Answer

Expert verified
The alternative hypothesis of \(H_{a}: \mu>100\) was chosen over \(\mu<100\) because in a sensitive environment like a nuclear power plant, it's safer and more beneficial to confirm if the weld strengths exceed the minimum required standards, rather than falling below it.

Step by step solution

01

Understanding the context

This exercise is set in a nuclear power plant setting. The safety of the plant and the people inside and around it are of utmost importance.In this scenario, the weld strength is inspected to verify if it meets the needed specifications. A robust weld can hold the pipe sections together securely even under extreme conditions, ensuring the integrity of the pipe system. Therefore, a high weld strength is essential.
02

Interpreting the hypotheses

The hypothesis \(H_{0}: \mu=100\) implies that the mean strength of welds is equal to 100 lb/in² - which is the minimum requirement for specifications. The alternative hypothesis \(H_{a}: \mu>100\) suggests that the mean strength exceeds the minimum threshold.
03

Explaining the choice of alternative hypothesis

The choice of \(H_{a}: \mu>100\) over \(\mu<100\) means that inspectors are more interested in verifying if the average weld strength exceeds the safety specifications, rather than falling short of it. This is vital because in an environment like a nuclear power plant where safety is critical, it is far better for welds strength to exceed the required minimum standard.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis, denoted as \( H_0 \), is a statement that assumes there is no effect or no difference in the context of the study. It is essentially the default or baseline condition that the researchers seek to test. For the exercise about pipe welds in a nuclear power plant, the null hypothesis is \( \mu = 100 \), which suggests that the mean strength of the welds is exactly at the cutoff point of 100 lb/in². This value is the minimum specified for safety purposes.

Accepting the null hypothesis would imply that there is no evidence to claim the weld strength exceeds or falls below the set specifications, meaning the current state is acceptable. This hypothesis is crucial in statistically determining whether any observed differences in data sample can be attributed to random chance or if they signify a true effect, particularly in contexts where safety is paramount.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), represents a statement contrary to the null hypothesis. It proposes that there is a real effect or a difference, suggesting deviations from the baseline set by the null hypothesis. In this scenario, the alternative hypothesis \( H_a: \mu > 100 \) suggests that the mean weld strength is greater than 100 lb/in².

This hypothesis is strategically chosen to align with safety goals, as proving \( \mu > 100 \) indicates stronger than necessary welds, which is desirable in a safety-sensitive environment like a nuclear power plant. If the data provides sufficient evidence to reject \( H_0 \), the alternative hypothesis gains support, suggesting improvements or exceptional quality in weld strength. Such a choice reflects a proactive approach to ensure safety rather than merely meeting the minimum standards.
Statistical Analysis
Statistical analysis is a critical process in hypothesis testing that involves collecting, analyzing, and interpreting data to reach conclusions about the null hypothesis. In this context, the analysis primarily focuses on assessing whether the sample data provides enough evidence to reject the null hypothesis \( H_0 \).

The process usually involves:
  • Calculating sample statistics such as the mean and standard deviation.
  • Determining the test statistic that quantifies how far the sample results deviate from what is stated in \( H_0 \).
  • Evaluating the p-value, which helps in deciding whether to reject the null hypothesis in favor of \( H_a \).

Interpreting the results of the statistical analysis is crucial. For instance, if the p-value is below a predetermined significance level (often 0.05), it suggests the observed data is inconsistent with \( H_0 \), leading to its rejection. This analysis ensures that the conclusions drawn about weld strength are statistically valid and reliable.
Sample Testing
Sample testing is a practical approach to hypothesis testing that involves examining a representative subset of welds to infer the strength characteristics for the entire population. It allows for the assessment of weld quality without inspecting every individual weld in the nuclear power plant, which would be resource-intensive and impractical.

The process involves:
  • Selecting a random sample of welds to ensure unbiased and representative results.
  • Measuring the weld strength in terms of the force required to break the weld.
  • Applying statistical tests to determine whether the observed sample mean supports or rejects the null hypothesis.

Careful conduct and analysis of sample testing are vital, as the reliability and validity of inferred conclusions about the population depend on the accuracy and randomness of the sample. Decisions based on these results directly impact safety measures and operational standards in the context they are applied.

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Most popular questions from this chapter

The report "Highest Paying Jobs for \(2009-10\) Bachelor's Degree Graduates" (National Association of Colleges and Employers, February 2010 ) states that the mean yearly salary offer for students graduating with a degree in accounting in 2010 is \(\$ 48,722\). Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of \(\$ 49,850\) and a standard deviation of \(\$ 3300\). Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the 2010 national average of \(\$ 48,722\) ? Test the relevant hypotheses using \(\alpha=.05\).

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Suppose that you are an inspector for the Fish and Game Department and that you are given the task of determining whether to prohibit fishing along part of the Oregon coast. You will close an area to fishing if it is determined that fish in that region have an unacceptably high mercury content. a. Assuming that a mercury concentration of \(5 \mathrm{ppm}\) is considered the maximum safe concentration, which of the following pairs of hypotheses would you test: \(H_{0}: \mu=5\) versus \(H_{a}: \mu>5\) or \(H_{0}: \mu=5\) versus \(H_{a}: \mu<5\) Give the reasons for your choice. b. Would you prefer a significance level of \(.1\) or \(.01\) for your test? Explain.

The article "Poll Finds Most Oppose Return to Draft, Wouldn't Encourage Children to Enlist" (Associated Press, December 18,2005 ) reports that in a random sample of 1000 American adults, 700 indicated that they oppose the reinstatement of a military draft. Is there convincing evidence that the proportion of American adults who oppose reinstatement of the draft is greater than two-thirds? Use a significance level of \(.05\).

"Most Like it Hot" is the title of a press release issued by the Pew Research Center (March 18, 2009 . www.pewsocialtrends.org). The press release states that "by an overwhelming margin, Americans want to live in a sunny place." This statement is based on data from a nationally representative sample of 2260 adult Americans. Of those surveyed, 1288 indicated that they would prefer to live in a hot climate rather than a cold climate. Do the sample data provide convincing evidence that a majority of all adult Americans prefer a hot climate over a cold climate? Use the nine-step hypothesis testing process with \(\alpha=.01\) to answer this question.

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