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Let \(\mu\) denote the true average lifetime (in hours) for a certain type of battery under controlled laboratory conditions. A test of \(H_{0}: \mu=10\) versus \(H_{a}:\) \(\mu<10\) will be based on a sample of size \(36 .\) Suppose that \(\sigma\) is known to be \(0.6\), from which \(\sigma_{\bar{x}}=.1\). The appropriate test statistic is then $$ z=\frac{\bar{x}-10}{0.1} $$

Short Answer

Expert verified
The z-test statistic for this hypothesis test is \( z = \frac {\bar{x} - 10}{0.1} \). This statistic will help determine whether or not to reject the null hypothesis, \(H_0: \mu=10\), depending on its comparison to the z-critical-value, which is determined by the significance level of the test.

Step by step solution

01

Understanding the Problem

The problem involves a hypothesis test with established null and alternative hypotheses. The null hypothesis (\(H_0: \mu=10\)) indicates the assumed average lifespan of the battery, while the alternative hypothesis (\(H_a: \mu<10\)) represents the other possibility being tested. A sample size of 36 is considered for this test and standard deviation is known to be 0.6. However, for a sample of this size, the standard deviation of the sample mean (\(\sigma_{\bar{x}}\)) is calculated to be 0.1.
02

Formulating the Test Statistic

For a z-test, the test statistic is calculated as: \( z= \frac{\bar{x}-10}{0.1} \) where \(\bar{x}\) denotes the sample mean. This z-score gives us the distance between the sample mean and assumed population mean in terms of standard deviations. The denominator, \(0.1\), is the standard error which represents variation in the sampling distribution of the sample mean and it takes the value of standard deviation divided by square root of the sample size.
03

Using the Test Statistic

The defined z-score formula will be used in hypothesis testing. For a given sample mean, the formula will produce the z-score which can then be compared to the z-critical-value determined by the significance level of the test. If the calculated z-score is less than the z-critical-value, we reject the null hypothesis, suggesting that the average lifespan of the battery is less than 10 hours. Otherwise, if the z-score is greater than or equal to the z-critical-value, we fail to reject the null hypothesis, implying that we don't have enough evidence to claim that the average lifespan isn't 10 hours.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-test
A Z-test is a statistical method used to determine if there is a significant difference between the sample mean and a known population mean, under the assumption that the sample is normally distributed. It's particularly useful when we have a large sample size (generally over 30) and the population standard deviation is known. In this scenario, the Z-test helps us examine if the average lifetime of the battery differs from the supposed 10 hours.

To perform a Z-test, you first calculate the test statistic, which is a Z-score. The Z-score tells you how many standard deviations the sample mean is away from the population mean. If the sample mean significantly differs from what is assumed under the null hypothesis, the Z-score will indicate whether you need to reject or fail to reject the null hypothesis.
  • If the Z-score is extreme (negatively or positively) based on a pre-determined critical value (depending on the significance level like 0.05 or 0.01), it suggests evidence against the null hypothesis.
  • If the Z-score falls within the range of confidence, it suggests that there's not enough evidence to reject the null hypothesis.
Standard Deviation
Standard deviation is a statistical measurement of the dispersion or spread in a set of data. It quantifies how much the individual data points differ from the mean of the data set. A lower standard deviation indicates that data points are close to the mean, while a higher standard deviation shows that data are more spread out.

In the context of hypothesis testing like our battery example, understanding the standard deviation is crucial. It is used to calculate the standard error, which is needed to compute the Z-score. The standard deviation of the original data set is 0.6, showing how much the lifetimes of batteries generally deviate from their average. The standard deviation of the sample mean (0.1) then gives a sense of how much the sample means are expected to vary due to random sampling variation.
  • A known standard deviation allows for the Z-test to be performed accurately.
  • The standard deviation of the sample mean helps in understanding the reliability and accuracy of a sample mean as an estimate of the population mean.
Null Hypothesis
The null hypothesis is a fundamental part of hypothesis testing. It is a statement that there is no effect or no difference and, in statistical testing, it suggests that any observed difference is due to random chance. In the battery life example, the null hypothesis (\(H_0: \mu=10\)) proposes that the true average lifetime of the battery is 10 hours.

Testing the null hypothesis involves determining whether there is strong enough statistical evidence to reject it in favor of the alternative hypothesis (which suggests a change or difference). During such testing:
  • If the evidence from the sample is strong enough (e.g., the Z-score is significant), we reject the null hypothesis.
  • If the evidence isn't strong, we fail to reject the null hypothesis, meaning we do not have enough evidence to say the average battery life is different from 10 hours.
This process ensures that claims are only made when they are supported by statistical evidence.
Sample Mean
A sample mean, denoted by \(\bar{x}\), is the average of observations taken from a sample. It serves as an estimate of the population mean, which in our example, is the average battery life. The sample mean is calculated by totaling all the individual data points in the sample and dividing by the number of observations.

In hypothesis testing, like our battery example, the sample mean acts as a critical component in computing the test statistic for the Z-test. It forms the numerator in our Z-test formula:\(\frac{\bar{x}-10}{0.1}\), which measures how far \(\bar{x}\) deviates from the hypothesized population mean relative to the standard error.
  • Understanding the sample mean helps deduce how well the sample represents the population.
  • The reliability of inferences about the population mean often depends on the value of the sample mean.
With a sound understanding of the sample mean, we further gain insights into the variability and reliability of our hypothesis test results.

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Most popular questions from this chapter

The paper "Playing Active Video Games Increases Energy Expenditure in Children" (Pediatrics [2009]: 534-539) describes an interesting investigation of the possible cardiovascular benefits of active video games. Mean heart rate for healthy boys age 10 to 13 after walking on a treadmill at \(2.6 \mathrm{~km} /\) hour for 6 minutes is 98 beats per minute (bpm). For each of 14 boys, heart rate was measured after 15 minutes of playing Wii Bowling. The resulting sample mean and standard deviation were \(101 \mathrm{bpm}\) and \(15 \mathrm{bpm}\), respectively. For purposes of this exercise, assume that it is reasonable to regard the sample of boys as representative of boys age 10 to 13 and that the distribution of heart rates after 15 minutes of Wii Bowling is approximately normal. a. Does the sample provide convincing evidence that the mean heart rate after 15 minutes of Wii Bowling is different from the known mean heart rate after 6 minutes walking on the treadmill? Carry out a hypothesis test using \(\alpha=.01\). b. The known resting mean heart rate for boys in this age group is \(66 \mathrm{bpm}\). Is there convincing evidence that the mean heart rate after Wii Bowling for 15 minutes is higher than the known mean resting heart rate for boys of this age? Use \(\alpha=.01\).

Assuming a random sample from a large population, for which of the following null hypotheses and sample sizes \(n\) is the large-sample \(z\) test appropriate: a. \(H_{0}: p=.2, n=25\) b. \(H_{0}: p=.6, n=210\) c. \(H_{0}: p=.9, n=100\) d. \(H_{0}: p=.05, n=75\)

In a representative sample of 1000 adult Americans, only 430 could name at least one justice who is currently serving on the U.S. Supreme Court (Ipsos, January 10, 2006 ). Using a significance level of .01, carry out a hypothesis test to determine if there is convincing evidence to support the claim that fewer than half of adult Americans can name at least one justice currently serving on the Supreme Court.

For which of the following \(P\) -values will the null hypothesis be rejected when performing a test with a significance level of .05: a. \(.001\) d. \(.047\) b. \(.021\) e. \(.148\) c. \(.078\)

Past experience has indicated that the true response rate is \(40 \%\) when individuals are approached with a request to fill out and return a particular questionnaire in a stamped and addressed envelope. An investigator believes that if the person distributing the questionnaire is stigmatized in some obvious way, potential respondents would feel sorry for the distributor and thus tend to respond at a rate higher than \(40 \%\). To investigate this theory, a distributor is fitted with an eye patch. Of the 200 questionnaires distributed by this individual, 109 were returned. Does this strongly suggest that the re-sponse rate in this situation exceeds the rate in the past? State and test the appropriate hypotheses at significance level .05.

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