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Many older homes have electrical systems that use fuses rather than circuit breakers. A manufacturer of 40 -amp fuses wants to make sure that the mean amperage at which its fuses burn out is in fact \(40 .\) If the mean amperage is lower than 40 , customers will complain because the fuses require replacement too often. If the mean amperage is higher than 40, the manufacturer might be liable for damage to an electrical system as a result of fuse malfunction. To verify the mean amperage of the fuses, a sample of fuses is selected and tested. If a hypothesis test is performed using the resulting data, what null and alternative hypotheses would be of interest to the manufacturer?

Short Answer

Expert verified
The null hypothesis, H0, is that the mean amperage of the fuses is 40 (H0: µ = 40). The alternative hypothesis, H1, is that the mean amperage of the fuses is not 40 (Ha: µ ≠ 40).

Step by step solution

01

Understanding Null and Alternative Hypotheses

In hypothesis testing, the null hypothesis (often denoted by H0) is a statement about the population that will be assumed to be true unless sufficient contradictory evidence is found. The alternative hypothesis (often denoted by Ha or H1) is the opposite of the null hypothesis and it is what we conclude is the case if the null hypothesis is rejected.
02

Formulating the Null Hypothesis

The null hypothesis, H0, in this case would be that the mean amperage of the fuses is exactly 40 amps. Using mathematical notation, this can be written as: H0: µ = 40.
03

Formulating the Alternative Hypothesis

The alternative hypothesis, H1, would be that the mean amperage of the fuses is not equal to 40 amps. In other words, it could either be less than or greater than 40. This can be mathematically written as: Ha: µ ≠ 40.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
In the realm of statistics, particularly when performing hypothesis testing, understanding the null and alternative hypotheses is crucial. The null hypothesis (ull hypothesis - typically denoted as ull hypothesis ) serves as a starting assumption. It is a declaration about a population parameter (in this case, mean amperage) which suggests that there is no effect or no difference; it represents the status quo. For the fuse manufacturer, the null hypothesis claims that the mean amperage at which fuses burn out is exactly 40 amps, mathematically noted as ull hypothesis : ull hypothesis = 40.

The alternative hypothesis (ull hypothesis - sometimes denoted as ull hypothesis 1 or ull hypothesis ) is posited as a contrast to the null hypothesis. It suggests that there is an effect or a difference. In hypothesis testing, if evidence against the null hypothesis is strong enough, the null hypothesis is rejected in favor of the alternative hypothesis. For our fuse manufacturer scenario, the alternative hypothesis is concerned with mean amperage being different (either less or more) than 40 amps, expressed as ull hypothesis : ull hypothesis ≠ 40. This encompasses both possibilities that concern the manufacturer: a mean amperage lower than 40 causing customer complaints, or higher than 40 potentially leading to liability issues due to fuse malfunction.
Mean Amperage
Mean amperage is the average electrical current, measured in amperes, that causes a fuse to burn out. As with any average, it is determined by summing the amperages at which individual fuses burn out and dividing by the total number of fuses tested. In the context of our manufacturer, ensuring that the mean amperage aligns with the 40-amp specification is critical for customer satisfaction and safety.

Calculating Mean Amperage

The calculation of mean amperage is straightforward: sum all the observed amperages from the sample of fuses and divide by the number of fuses. This mean represents an estimate of the population parameter—from the sample, we infer about the whole lot of fuses. If the calculated mean significantly deviates from 40, it may trigger a need for manufacturing adjustments.
Population Parameter
The term 'population parameter' refers to a specific characteristic of a population that can be measured or quantified. In statistics, populations are not always people, but can be a collection of objects or occurrences, such as all the fuses produced by the manufacturer. The parameter of interest in the given exercise is the mean amperage at which the fuses burn out.

Understanding that a sample is a subset of the population is pivotal. We use the sample's mean amperage to estimate the true mean amperage for the entire population of fuses. Since it is impractical to test every single fuse, a sample provides a practical approach to infer the population parameter. The precision of this estimation depends on the sample size and variability within the sample.
Statistical Significance
Statistical significance is a determination about whether any observed differences or relationships in data occur by chance or are reflective of true differences in the population. In hypothesis testing, it is used to decide whether to reject the null hypothesis or not.

In the scenario of the fuse manufacturer, if the sample mean amperage is found to be significantly different from 40 amps according to statistical testing, it would be deemed statistically significant. This implies that the observed deviation is unlikely to have occurred by random chance alone. A common threshold for determining statistical significance is a p-value of 0.05 or 5%, which means there's a 5% chance that the results are due to random variation rather than a true effect. If the p-value is less than the chosen significance level, the null hypothesis is rejected, indicating that the mean amperage is not 40 amps, prompting further investigation or changes in the manufacturing process.

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Most popular questions from this chapter

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For the following pairs, indicate which do not comply with the rules for setting up hypotheses, and explain why: a. \(H_{0}: \mu=15, H_{a}: \mu=15\) b. \(H_{0}: p=.4, H_{a}: p>.6\) c. \(H_{0}: \mu=123, H_{a}: \mu<123\) d. \(H_{0}: \mu=123, H_{a}: \mu=125\) e. \(H_{0}: \hat{p}=.1, H_{a}: \hat{p} \neq .1\)

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