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Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. In a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California), a random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

Short Answer

Expert verified
After calculating the test statistic and finding the p-value, if the p-value is less than or equal to \(\alpha = .01\), then we can conclude that the majority of local residents oppose hunting on the Morro Bay. If the p-value is greater than \(\alpha = .01\), we cannot make this conclusion.

Step by step solution

01

Defining the Hypotheses

Firstly, we need to define the null hypothesis \(H_0\) and the alternative hypothesis \(H_1\). Here, \(H_0\) is 'The majority of local residents do not oppose hunting on the Morro Bay', which means the ratio of opposition is less than or equal to 0.5 (because the majority is defined as more than 50%). Hence, \(H_0: p \leq 0.5\). The alternative hypothesis \(H_1\) is 'The majority of local residents oppose hunting on the Morro Bay', implying the ratio of opposition is greater than 0.5. Therefore, \(H_1: p > 0.5\).
02

Calculate Test Statistic

Once we have defined the hypothesis, the next step is to calculate the test statistic. We calculate it as follows: The sample proportion \(p̂\) is calculated as the number of successes (people who oppose hunting) divided by the total number of observations, we get \(p̂ = 560/750 = 0.747\). For a one-sample z-test, the test statistic \(z\) is given by the formula \(z = (p̂ - p_0) / \sqrt{(p̂(1-p̂)/n)}\), where \(p_0\) is the proportion assumed in the null hypothesis. Based on our null hypothesis the value of \(p_0\) is 0.5. Therefore, the test statistic \(z\) here becomes \(z = (0.747 - 0.5) / \sqrt{(0.747×0.253)/750}\).
03

Find P-value

The p-value is the probability of obtaining a result as extreme as the observed results, under the null hypothesis. To get the p-value, we look at our calculated \(z\) score in the z-table (or use a statistical software or calculator) to find the probability. We subtract this probability from 1 (since we are looking at the probability of being greater) to get the p-value.
04

Decision

We now compare the p-value with alpha value \(\alpha = .01\). If the p-value is less than or equal \(\alpha\), we reject the null hypothesis. If the p-value is greater than \(\alpha\), we fail to reject the null hypothesis. In our case, if p-value \(\leq .01\), we reject \(H_0\) and this means the majority of local residents oppose hunting on the Morro Bay.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
Understanding the purpose of null and alternative hypotheses is essential for anyone delving into hypothesis testing in statistics. These hypotheses represent two mutually exclusive statements about a population parameter. The null hypothesis (\(H_0\)) typically suggests that there is no effect or difference, and it serves as the statement we attempt to challenge. In our example concerning Morro Bay duck hunting, we define \(H_0\): \(p \[leq\] 0.5 \), indicating that less than or equal to half of the local residents oppose hunting.

The alternative hypothesis (\(H_1\) or \(H_a\)), on the other hand, is the assertion we hope to provide evidence for. In our case, \(H_1\): \(p \[gt\] 0.5\), implying a belief that more than half of the locals are against hunting. This setup prepares us for the next steps in our testing procedure—calculating the test statistic and interpreting the results.
Test Statistic Calculation
The test statistic is a standardized value that helps us make a decision regarding our hypotheses. It's calculated from sample data and is used to assess the plausibility of the null hypothesis. For our one-sample z-test scenario, we compute the test statistic using the formula \(z = (\hat{p} - p_0) \ \sqrt{(\hat{p}(1-\hat{p})/n)} \), where \(\hat{p}\) is the sample proportion, \(p_0\) is the population proportion under the null hypothesis, and \(n\) is the sample size.

In the Morro Bay example, by plugging the observed sample proportion and the assumed population proportion into the formula, we calculate the z-value that helps us to understand how far the sample proportion is from the null hypothesis proportion, when measured in standard deviations.
P-Value Interpretation
The p-value is a critical concept for interpreting test results. It represents the probability of observing sample results as extreme as those obtained, assuming the null hypothesis is true. A small p-value indicates that such extreme data would be very unlikely under the null hypothesis and thus provides evidence against \(H_0\).

Specifically, if the p-value is less than our significance level (\(\alpha\))—which is \(.01\) in the Morro Bay case—we have strong grounds for rejecting the null hypothesis. This result would mean it is highly likely that a greater proportion of the population opposes duck hunting than our null hypothesis stated. A p-value greater than \(\alpha\), however, would mean we do not have enough evidence to dismiss \(H_0\), and we would say that we 'fail to reject' it.
One-Sample Z-Test
A one-sample z-test is a type of statistical test used when comparing the sample mean to a known population mean (\(p_0\)) when the population standard deviation is known. In the context of the Morro Bay survey, we're comparing the sample proportion of residents opposing duck hunting to an expected population proportion under the null hypothesis. After calculating the z-test statistic from the sample data, we refer to a standard normal distribution table—or use statistical software—to find the probability associated with the z-value.

In this case, we conclude the test by deciding whether to reject or not reject \(H_0\) based on whether the computed p-value is lower than our predetermined significance level (\(\alpha = .01\)). If we do reject \(H_0\), we're saying that the evidence suggests a majority of the residents oppose duck hunting, which could have implications for future regulations and policy-making in Morro Bay.

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Most popular questions from this chapter

An automobile manufacturer is considering using robots for part of its assembly process. Converting to robots is an expensive process, so it will be undertaken only if there is strong evidence that the proportion of defective installations is lower for the robots than for human assemblers. Let \(p\) denote the proportion of defective installations for the robots. It is known that human assemblers have a defect proportion of \(.02\). a. Which of the following pairs of hypotheses should the manufacturer test: \(H_{0}: p=.02\) versus \(H_{a}: p<.02\) or \(H_{0}: p=.02\) versus \(H_{a}: p>.02\) Explain your answer. b. In the context of this exercise, describe Type I and Type II errors. c. Would you prefer a test with \(\alpha=.01\) or \(\alpha=.1\) ? Explain your reasoning.

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Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most \(150^{\circ} \mathrm{F}\), there will be no negative effects on the river's ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above \(150^{\circ} \mathrm{F}\), researchers will take 50 water samples at randomly selected times and record the temperature of each sample. The resulting data will be used to test the hypotheses \(H_{0}: \mu=150^{\circ} \mathrm{F}\) versus \(\left.H_{a}: \mu\right\rangle\) \(150^{\circ} \mathrm{F}\). In the context of this example, describe Type I and Type II errors. Which type of error would you consider more serious? Explain.

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