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The article "The Sorority Rush Process: SelfSelection, Acceptance Criteria, and the Effect of Rejection" (Journal of College Student Development [1994]: \(346-353\) ) reported on a study of factors associated with the decision to rush a sorority. Fifty-four women who rushed a sorority and 51 women who did not were asked how often they drank alcoholic beverages. For the sorority rush group, the mean was \(2.72\) drinks per week and the standard deviation .86. For the group who did not rush, the mean was \(2.11\) and the standard deviation \(1.02 .\) Is there evidence to support the claim that those who rush a sorority drink more than those who do not rush? Test the relevant hypotheses using \(\alpha=.01\). What assumptions are required in order for the two-sample \(t\) test to be appropriate?

Short Answer

Expert verified
After running the two-sample t-test and interpreting the results, a decision about the claim that women who rush a sorority drink more than women who do not can be made. The assumptions needed for a two-sample t-test are that the samples are independent, from normally distributed populations, and the variances of these populations are assumed to be equal.

Step by step solution

01

Identify the Data and Hypotheses

Firstly, identify two groups of women: Group 1 - women who rush a sorority with mean=2.72 and standard deviation=0.86; Group 2 - women who do not rush with mean=2.11 and standard deviation=1.02. The null hypothesis \(H_0\) is: there's no difference in the weekly alcohol consumption between the two groups. Therefore, \(H_0: \mu_1 - \mu_2 = 0\). The alternative hypothesis \(H_1\) is: women who rush a sorority consume more alcohol than those who do not rush. Therefore, \(H_1: \mu_1 - \mu_2 > 0\).
02

Calculate the Test Statistic

Assuming that the variances from the two populations are equal, we calculate the pooled standard deviation \(s_p\) and then the t-score. The formula for the pooled standard deviation is: \(s_p = \sqrt{{((n1-1)*s1^2 + (n2-1)*s2^2)}/{(n1+n2-2)}}\). The t-score calculation is \((x̄1 - x̄2)/ s_p * \sqrt{(1/n1) + (1/n2)}\). Here, \(x̄1\) and \(x̄2\) are the sample means, \(s1\) and \(s2\) are the respective sample standard deviations, \(n1\) and \(n2\) are the sizes of the two samples.
03

Find the P-Value

The p-value can be obtained by looking up the t-score in the t-distribution table, taking into account the degrees of freedom (df), which in this case is \(df = n1 + n2 - 2\). A p-value less than \(\alpha = .01\) would lead to rejection of the null hypothesis.
04

Making Decision

Compare the calculated p-value with the significance level, α=.01. If p-value < α, the null hypothesis is rejected and it can be concluded that women who rush a sorority drink significantly more than women who do not.
05

Check Assumptions

For a two-sample t-test to be appropriate, certain assumptions need to be met: 1. The samples are independent of each other. 2. Each sample is from a normally distributed population. 3. The population variances are equal which is the case when the ratio of the larger sample variance to the smaller sample variance is less than 2:1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis testing
Hypothesis testing is a fundamental statistical technique used to make inferences or informed decisions about a population based on sample data. In the context of the two-sample t-test, like the one used in this exercise, the primary goal is to compare the means of two independent groups.
A hypothesis test starts with formulating null and alternative hypotheses. The null hypothesis (\(H_0\)) in this exercise asserts that there is no difference in alcohol consumption between women who rush a sorority and those who do not. This is expressed as \(H_0: \mu_1 - \mu_2 = 0\).
Conversely, the alternative hypothesis (\(H_1\)) suggests a difference exists, specifically that women who rush consume more alcohol, written as \(H_1: \mu_1 - \mu_2 > 0\).
The test proceeds by calculating a test statistic, which helps determine the likelihood that the observed data would occur under the null hypothesis. If the probability (the p-value) is sufficiently low, we reject the null hypothesis, indicating that the sample provides enough evidence to support the alternative hypothesis.
Pooled variance
Pooled variance is a method used to estimate the variance of two populations when performing a two-sample t-test. This technique is employed when the assumption of equal variances holds true.
In this exercise, we calculated the pooled variance using the formula: \[s_p = \sqrt{{((n1-1)s1^2 + (n2-1)s2^2)}/{(n1+n2-2)}}\] where \(s1\) and \(s2\) represent the standard deviations of the two samples, and \(n1\) and \(n2\) are their respective sample sizes.
The pooled variance provides a single estimate of the variance by combining the variances of the two groups in a weighted fashion, taking into account their sample sizes. Together with the difference in sample means, it allows the calculation of the t-statistic needed for hypothesis testing. In all applications, ensuring that the assumption of equal variances holds is key, affecting the validity of the pooled variance estimation and subsequent t-test results.
P-value
The p-value plays a crucial role in hypothesis testing by quantifying the evidence against the null hypothesis. It represents the probability that the observed or more extreme differences occurred just by random chance if the null hypothesis were true.
In the exercise undertaken, after computing the t-statistic, the p-value is derived by comparing this statistic to a t-distribution, considering the degrees of freedom (\(df = n1 + n2 - 2\)).
The rule of thumb is: the smaller the p-value, the stronger the evidence against the null hypothesis. If the p-value is less than the significance level \(\alpha = 0.01\) in this instance, the null hypothesis is rejected. This implies there's substantial evidence to assert that women who rush a sorority drink more than those who don't. Always ensure the significance level is set before testing to maintain unbiased decisions.
Assumptions of t-test
For the two-sample t-test to provide reliable results, several key assumptions must be verified:
  • **Independence**: The samples must be independent of each other, meaning the selection or outcome in one sample does not influence the other.
  • **Normality**: Each group should come from a normally distributed population, especially important with small sample sizes.
  • **Homogeneity of Variance**: Both populations should have equal variances. This assumption is checked by ensuring the ratio of the larger to the smaller sample variance is less than 2:1.
In practice, if these assumptions are not met, the results of the t-test may not be valid. This could lead to incorrect conclusions about the data. Hence, before computing the test, it's essential to validate these assumptions, possibly transforming data or using alternative methods if needed.

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