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The article "Workaholism in Organizations: Gender Differences" (Sex Roles [1999]: \(333-346\) ) gave the following data on 1996 income (in Canadian dollars) for random samples of male and female MBA graduates from a particular Canadian business school: \begin{tabular}{lccc} & \(\boldsymbol{n}\) & \(\boldsymbol{x}\) & \(\boldsymbol{s}\) \\ \hline Males & 258 & \(\$ 133,442\) & \(\$ 131,090\) \\ Females & 233 & \(\$ 105,156\) & \(\$ 98,525\) \\ \hline \end{tabular} a. For what significance levels would you conclude that the mean salary of female MBA graduates of this business school is above \(\$ 100,000\) ? b. Is there convincing evidence that the mean salary for female MBA graduates of this business school is lower than the mean salary for the male graduates?

Short Answer

Expert verified
The solutions to these questions depend on the computed p-values, which may be found using a standard distribution table or statistical software. For a, any significance level greater than this p-value would lead us to conclude that the mean salary of female MBA graduates is above $100,000. On part b, if the p-value is less than the significance level, there is convincing evidence that the mean salary of female MBA graduates of this business school is less than the mean salary of male MBA graduates.

Step by step solution

01

Formulate the Hypothesis for Part a

The null hypothesis (\(H_0\)) can be formulated as: The mean salary of female MBA graduates of this business school is equal to $100,000. The alternative hypothesis (\(H_1\)) is: The mean salary of female MBA graduates of this business school is above $100,000. Mathematically, \(H_0: \mu = \$100,000\) and \(H_1: \mu > \$100,000\).
02

Statistical Calculation for Part a

Compute the test statistic (z) using the formula: \[z = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}}\] We plug the values from the exercise into this equation, where \(\bar{x} = \$105,156\), \(\mu_0 = \$100,000\), \(s = \$98,525\), and \(n = 233\). Calculate the z-score and find the corresponding p-value from the standard normal distribution table or via computation.
03

Decision for Part a

Using the p-value, compare it with the standard significance level (usually 0.05). If the p-value is less than 0.05, we reject the null hypothesis in favor of the alternative hypothesis. Otherwise, we fail to reject the null hypothesis. The significance levels at which we would conclude that the mean salary of female MBA graduates is above $100,000 are those greater than the computed p-value.
04

Formulate the Hypothesis for Part b

The null hypothesis (\(H_0\)) is that the mean salary for female MBA graduates is equal to that of the male graduates. The alternative hypothesis (\(H_1\)) is that the mean salary for female MBA graduates is lower than that of the male graduates. In mathematical notation, \(H_0: \mu_F = \mu_M\) and \(H_1: \mu_F < \mu_M\).
05

Statistical Calculation for Part b

Compute the test statistic using the formula for the hypothesis test of difference between two means (since the standard deviations are known, we will use z-test): \[z = \frac{\bar{x}_F - \bar{x}_M} {\sqrt{\frac{s_F^2}{n_F} + \frac{s_M^2}{n_M}}}\] where \(\bar{x}_F = \$105,156\), \(\bar{x}_M = \$133,442\), \(s_F = \$98,525\), \(s_M = \$131,090\), \(n_F = 233\), and \(n_M = 258\). After finding the z-score, compute the p-value.
06

Decision for Part b

Using the p-value, compare it with the standard significance level (usually 0.05). If the p-value is less than the level of significance, we reject the null hypothesis in favor of the alternative hypothesis. If the p-value is larger than the level of significance, we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Significance Level
When conducting hypothesis tests, the significance level is crucial. It helps researchers decide the threshold for determining if a result is statistically significant. The significance level, denoted by \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true. A common \( \alpha \) value used in testing is 0.05. This implies a 5% risk of concluding that a difference exists when there is no actual difference.

Choosing the right significance level depends on the context of the study. For high-stakes testing, like pharmaceuticals, a lower \( \alpha \) level, such as 0.01, might be preferable to reduce the risk of false positives. Conversely, for initial exploratory studies, a higher \( \alpha \) might be used to detect potential effects that warrant further investigation.

Understanding the implication of the significance level assists in interpreting the results. If the computed p-value from the test is less than \( \alpha \), the result is deemed statistically significant, leading to the rejection of the null hypothesis in favor of the alternative. This aligns with one of the key tasks in the original exercise: determining the significance levels for conclusions on MBA graduates' salaries.
z-test
The z-test is a statistical test used to determine whether there is a significant difference between sample and population means, or between two sample means, when the variance is known.

For a single sample mean, the z-test formula looks like this:
  • \[ z = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]
Here, \(\bar{x}\) is the sample mean, \(\mu_0\) is the population mean under the null hypothesis, \(s\) is the sample standard deviation, and \(n\) is the sample size.

A z-test assumes that the sample size is sufficiently large or that the underlying distribution is normal. It's commonly used in situations like those in the original exercise, to compare MBA graduates' salaries where large sample sizes make the test robust.

For comparing two sample means, the z-test formula adjusts to account for the sample sizes and standard deviations of both groups, which helps in establishing confidence in the differences observed between groups, such as differences in male and female graduate salaries.
p-value
The p-value is a vital aspect of hypothesis testing that quantifies how much the data support the null hypothesis. It is the probability of observing a sample statistic as extreme as the test statistic, under the assumption that the null hypothesis is true.

When you perform a hypothesis test, you calculate the p-value based on the test statistic, such as the z-score from a z-test. If the p-value is smaller than the chosen significance level \( \alpha \), the evidence is strong enough to reject the null hypothesis. For instance, if \( \alpha \) is set at 0.05 and your p-value is 0.03, you reject the null hypothesis because 0.03 is less than 0.05.

The interpretation of the p-value helps determine the strength of the results, as in the exercise problem where the p-value helped decide whether to conclude variations in salaries among MBA graduates. Thus, even a small p-value, in conjunction with a chosen \( \alpha \), may indicate statistically significant results warranting more in-depth exploration or policy implications.

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