/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 City crime records show that \(2... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

City crime records show that \(20 \%\) of all crimes are violent and \(80 \%\) are nonviolent, involving theft, forgery, and so on. Ninety percent of violent crimes are reported versus \(70 \%\) of nonviolent crimes. a. What is the overall reporting rate for crimes in the city? b. If a crime in progress is reported to the police, what is the probability that the crime is violent? What is the probability that it is nonviolent? c. Refer to part b. If a crime in progress is reported to the police, why is it more likely that it is a nonviolent crime? Wouldn't violent crimes be more likely to be reported? Can you explain these results?

Short Answer

Expert verified
Answer: The overall reporting rate for crimes in the city is 74%. Given a crime is reported, the probability of it being violent is approximately 24.32%, and the probability of it being nonviolent is approximately 75.68%.

Step by step solution

01

a. Calculating the overall reporting rate

To find the overall reporting rate for crimes in the city, we can use the given probabilities to calculate the total probability of a crime being reported. Let P(V) be the probability of a crime being violent, and P(NV) be the probability of a crime being nonviolent. Similarly, let P(R|V) and P(R|NV) denote the probabilities of reporting a crime given it is violent and nonviolent, respectively. We are given the following probabilities: P(V) = 0.2 P(NV) = 0.8 P(R|V) = 0.9 P(R|NV) = 0.7 We want to find P(R), the overall probability that a crime is reported. We can use the law of total probability: P(R) = P(R|V)P(V) + P(R|NV)P(NV). Calculating the overall reporting rate: P(R) = (0.9)(0.2) + (0.7)(0.8) = 0.18 + 0.56 = 0.74 Thus, the overall reporting rate for crimes in the city is \(74 \%\).
02

b. Calculating probabilities for violent and nonviolent crimes given a crime is reported

To find the probabilities of a crime being violent or nonviolent given it is reported, we will apply Bayes' theorem. Bayes' theorem states: P(A|B) = (P(B|A) * P(A)) / P(B) We will calculate P(V|R) and P(NV|R) using the given probabilities and the overall reporting rate we calculated in part a. P(V|R) = (P(R|V) * P(V)) / P(R) = (0.9 * 0.2) / 0.74 = 0.18 / 0.74 = 0.2432 P(NV|R) = (P(R|NV) * P(NV)) / P(R) = (0.7 * 0.8) / 0.74 = 0.56 / 0.74 = 0.7568 The probability of a reported crime being violent is approximately \(24.32 \%\), and the probability of it being nonviolent is approximately \(75.68 \%\).
03

c. Interpreting the results and providing explanations

Given a crime is reported, the probability of it being violent is lower than the probability of it being nonviolent (24.32% vs 75.68%). At first glance, this may seem counterintuitive because violent crimes are more likely to be reported (90% reporting rate vs 70% for nonviolent crimes). However, we must consider the initial probability distribution of crimes: only 20% of crimes are violent and 80% are nonviolent. Even though violent crimes have a higher reporting rate, nonviolent crimes still make up the majority of total crimes. Therefore, when a crime is reported, it is more likely to be a nonviolent crime simply because nonviolent crimes are more common.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that \(P(A)=.4\) and \(P(A \cap B)=.12\). a. Find \(P(B \mid A)\). b. Are events \(A\) and \(B\) mutually exclusive? c. If \(P(B)=.3,\) are events \(A\) and \(B\) independent?

A food company plans to conduct an experiment to compare its brand of tea with that of two competitors. A single person is hired to taste and rank each of three brands of tea, which are unmarked except for identifying symbols \(A\), \(B\), and \(C\). a. Define the experiment. b. List the simple events in \(S\). c. If the taster has no ability to distinguish a difference in taste among teas, what is the probability that the taster will rank tea type \(A\) as the most desirable? As the least desirable?

You have two groups of distinctly different items, 10 in the first group and 8 in the second. If you select one item from each group, how many different pairs can you form?

Player \(A\) has entered a golf tournament but it is not certain whether player \(B\) will enter. Player \(A\) has probability \(1 / 6\) of winning the tournament if player \(B\) enters and probability \(3 / 4\) of winning if player \(B\) does not enter the tournament. If the probability that player \(B\) enters is \(1 / 3,\) find the probability that player \(A\) wins the tournament.

Who is the king of late night TV? An Internet survey estimates that, when given a choice between David Letterman and Jay Leno, \(52 \%\) of the population prefers to watch Jay Leno. Suppose that you randomly select three late night TV watchers and ask them which of the two talk show hosts they prefer. a. Find the probability distribution for \(x\), the number of people in the sample of three who would prefer Jay Leno. b. Construct the probability histogram for \(p(x)\). c. What is the probability that exactly one of the three would prefer Jay Leno? d. What are the population mean and standard deviation for the random variable \(x ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.