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Player \(A\) has entered a golf tournament but it is not certain whether player \(B\) will enter. Player \(A\) has probability \(1 / 6\) of winning the tournament if player \(B\) enters and probability \(3 / 4\) of winning if player \(B\) does not enter the tournament. If the probability that player \(B\) enters is \(1 / 3,\) find the probability that player \(A\) wins the tournament.

Short Answer

Expert verified
Answer: The probability that player A wins the tournament is 5/9.

Step by step solution

01

Identify the given probabilities

We are given the following: - Probability that player A wins if player B enters, denoted as P(A wins | B enters) = 1 / 6 - Probability that player A wins if player B does not enter, denoted as P(A wins | B does not enter) = 3 / 4 - Probability that player B enters, denoted as P(B enters) = 1 / 3
02

Calculate the probability that player B does not enter the tournament

Since there are only two possibilities (player B enters or does not enter), we can calculate the probability that player B does not enter as: P(B does not enter) = 1 - P(B enters) = 1 - (1 / 3) = 2 / 3
03

Use the Law of Total Probability

To find the overall probability of player A winning the tournament, we can use the Law of Total Probability. This law states that the probability of an event occurring (in this case, player A winning) can be found by summing the probabilities of that event, given all possible scenarios (in this case, player B entering or not entering the tournament). Mathematically, this is represented as: P(A wins) = P(A wins | B enters) * P(B enters) + P(A wins | B does not enter) * P(B does not enter)
04

Calculate the probability that player A wins the tournament

Substitute the given probabilities into the expression: P(A wins) = (1 / 6) * (1 / 3) + (3 / 4) * (2 / 3) P(A wins) = (1 / 18) + (6 / 12) P(A wins) = (1 / 18) + (1 / 2) Find a common denominator (in this case, 18) to add these fractions: P(A wins) = (1 + 9) / 18 P(A wins) = 10 / 18
05

Simplify the probability

Simplify the fraction by dividing both the numerator and denominator by their greatest common divisor (in this case, 2): P(A wins) = (10 / 2) / (18 / 2) P(A wins) = 5 / 9 So, the probability that player A wins the tournament is 5/9.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Understanding conditional probability is crucial when dealing with scenarios that depend on a certain condition. For instance, player A's chance of winning the golf tournament is different depending on whether player B participates or not. This shows the outcome is conditioned on another event.

Simply put, conditional probability answers the question: 'What is the probability of event A happening given that event B has already occurred?' In our example, we look at two scenarios: the probability of A winning if B enters, and the probability of A winning if B does not enter. Mathematically, this is expressed as P(A wins | B enters) and P(A wins | B does not enter), where the '|' symbol is read as 'given'.

When teaching conditional probability, it's important to emphasize the dependency of one event on another. This concept extends to a variety of applications such as medical diagnosis, risk assessment, and even sports strategies, making it a foundational concept in probability theory.
Law of Total Probability
The law of total probability is a fundamental rule that relates marginal probability to conditional probabilities. It states that the probability of a particular event can be calculated by considering all possible scenarios that could lead to that event.

In the context of our exercise, we use the law of total probability to find out player A's overall chance of winning the tournament. We break the event 'A wins' into two mutually exclusive scenarios: 'B enters the tournament' and 'B does not enter the tournament'. Then, we calculate the probability for each scenario and add them up to get the total probability of A winning.

Here's the formula based on our scenario: \

\( P(A \text{ wins}) = P(A \text{ wins} | B \text{ enters}) \times P(B \text{ enters}) + P(A \text{ wins} | B \text{ does not enter}) \times P(B \text{ does not enter}) \).

Students should grasp that this law helps manage complex problems by breaking them into simpler, conditional parts. Notably, its use is not limited to two scenarios; it applies to any number of partitions that cover all possible outcomes.
Probability Calculation
Probability calculation involves mathematical operations used to determine the likelihood of an event. In our exercise, we carried out different calculations such as finding complements, multiplying probabilities, and adding fractions.

Firstly, to calculate the complement we used the fact that the probability of an event and its complement sum up to one. For example, we calculated P(B does not enter) as 1 minus P(B enters).

Next, we applied the multiplication principle of probability to the conditional probabilities and their respective scenarios. Lastly, we added these products to get the total probability. When adding fractions, we found a common denominator before summing them up. It's essential to walk students through these steps, as fluency in basic arithmetic operations is key for accurate probability calculation.

If students find difficulty in these steps, it may help to visualize the problem using probability trees or Venn diagrams. These visual aids reinforce the understanding of how different probability rules interplay to arrive at a solution.

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