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91Ó°ÊÓ

A study is to be conducted in a hospital to determine the attitudes of nurses toward various administrative procedures. If a sample of 10 nurses is to be selected from a total of \(90,\) how many different samples can be selected?

Short Answer

Expert verified
Answer: 43,758,678 different samples can be selected.

Step by step solution

01

Identify the given values

n, the total number of nurses, is 90 and r, the number of nurses to be selected, is 10.
02

Use the combination formula

We need to find the number of different samples of selecting 10 nurses (r) from the total of 90 nurses (n). This can be found using the combination formula: \(C(n,r) = \frac{n!}{r!(n-r)!}\).
03

Calculate factorials

First, compute the factorials needed for the formula: - n! = 90! - r! = 10! - (n-r)! = (90-10)! = 80!
04

Compute the combination

Now, plug these values into the combination formula: \(C(90,10) = \frac{90!}{10!(90-10)!} = \frac{90!}{10! \cdot 80!}\).
05

Simplify and calculate the result

Simplify the expression and compute the result: \(C(90,10) = \frac{90!}{10! \cdot 80!} = \frac{90 \times 89 \times 88 \times \cdots \times 81}{10 \times 9 \times 8 \times \cdots \times 1} = 43,758,678\). There are 43,758,678 different samples of 10 nurses that can be selected from a total of 90 nurses.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Formula
Combinatorics is a branch of mathematics that deals with counting combinations and permutations. The combination formula is a fundamental concept within this field. It helps us determine the number of ways to select a group of items from a larger set, where the order of selection doesn't matter.

In our exercise, we want to determine how many ways we can choose 10 nurses from a group of 90. The combination formula is represented as:\[C(n, r) = \frac{n!}{r!(n-r)!}\]
  • \(n\) is the total number of items to choose from.
  • \(r\) is the number of items we want to select.
The exclamation mark \(!\) denotes a factorial, a concept we'll explore next.

The beauty of the combination formula is that it simplifies the process of counting large sets efficiently without having to list out every possible combination manually. It's a powerful tool in probabilistic scenarios and can be applied in various fields like statistics, gambling, and computer science.
Factorials
Factorials are quite a handy mathematical concept, particularly when dealing with combinations and permutations. A factorial, denoted by the symbol \(!\), is the product of all positive integers up to a given number.

For instance:
  • The factorial of 5, written as \(5!\), is \(5 \times 4 \times 3 \times 2 \times 1 = 120\).
  • \(0!\) is defined as 1, which is a key point to remember.
In our nurse selection example, we needed to compute a few factorials: \(90!\), \(10!\), and \(80!\).

Factorials grow very fast, which can make the computation tricky without the help of calculators or software. However, for combination calculations, many terms cancel out, simplifying our work often to manageable numbers. Understanding factorials is essential for using the combination formula correctly and interpreting the implications of large numbers.
Sample Selection
Sample selection, as derived through the combination process, is about choosing items, like nurses, in contexts where the order does not matter. This is opposed to permutations, where order is crucial.

When selecting samples using the combination formula, our focus shifts solely to the choice of items irrespective of sequence. This approach suits our exercise perfectly where 10 nurses are to be chosen out of 90 without caring about the order in which they are picked.

The purpose of selecting samples varies based on field or scenario. For example:
  • In healthcare studies, like ours, samples help in determining trends or outcomes by studying a smaller, manageable group.
  • In surveys, samples reflect a larger population's opinions or conditions without needing input from everyone.
Thus, understanding how to select samples properly and use combinations enables us to ensure appropriate and effective data collection and representation.

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Most popular questions from this chapter

A fire-detection device uses three temperature-sensitive cells acting independently of one another in such a manner that any one or more can activate the alarm. Each cell has a probability \(p=.8\) of activating the alarm when the temperature reaches \(100^{\circ} \mathrm{F}\) or higher. Let \(x\) equal the number of cells activating the alarm when the temperature reaches \(100^{\circ} \mathrm{F}\). a. Find the probability distribution of \(x\). b. Find the probability that the alarm will function when the temperature reaches \(100^{\circ} \mathrm{F}\). c. Find the expected value and the variance for the random variable \(x\).

Let \(x\) equal the number observed on the throw of a single balanced die. a. Find and graph the probability distribution for \(x\). b. What is the average or expected value of \(x ?\) c. What is the standard deviation of \(x\) ? d. Locate the interval \(\mu \pm 2 \sigma\) on the \(x\) -axis of the graph in part a. What proportion of all the measurements would fall into this range?

You have two groups of distinctly different items, 10 in the first group and 8 in the second. If you select one item from each group, how many different pairs can you form?

Suppose that \(P(A)=.3\) and \(P(B)=.5\). If events \(A\) and \(B\) are mutually exclusive, find these probabilities: a. \(P(A \cap B)\) b. \(P(A \cup B)\)

A sample space \(S\) consists of five simple events with these probabilities: $$\begin{array}{c}P\left(E_{1}\right)=P\left(E_{2}\right)=.15 \quad P\left(E_{3}\right)=.4\\\P\left(E_{4}\right)=2 P\left(E_{5}\right)\end{array}$$ a. Find the probabilities for simple events \(E_{4}\) and \(E_{5}\). b. Find the probabilities for these two events: $$A=\left\\{E_{1}, E_{3}, E_{4}\right\\}$$ $$B=\left\\{E_{2}, E_{3}\right\\}$$ c. List the simple events that are either in event \(A\) or event \(B\) or both. d. List the simple events that are in both event \(A\) and event \(B\).

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