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The two stars of the Miami Heat professional basketball team are very different when it comes to making free throws. ESPN.com reports that Jason Williams makes about \(80 \%\) of his free throws, while Shaquille O'Neal makes only \(53 \%\) of his free throws. \({ }^{4}\) Assume that the free throws are independent, and that each player takes two free throws during a particular game. a. What is the probability that Jason makes both of his free throws? b. What is the probability that Shaq makes exactly one of his two free throws? c. What is the probability that Shaq makes both of his free throws and Jason makes neither of his?

Short Answer

Expert verified
Answer: a) The probability of Jason making both of his free throws is 0.64 or 64%. b) The probability of Shaquille making exactly one of his two free throws is 0.4982 or 49.82%. c) The probability of Shaquille making both of his free throws and Jason missing both of his free throws is 0.011236 or 1.12%.

Step by step solution

01

a. Probability that Jason makes both of his free throws

Since the free throws are independent, we can find the probability of both free throws by simply multiplying the probabilities of each free throw. Jason makes about \({80\%}\) of his free throws, so we have: P(Jason makes both) = P(Jason makes first) * P(Jason makes second) = \({0.8 * 0.8 = 0.64}\)
02

b. Probability that Shaq makes exactly one of his two free throws

Shaq makes about \({53\%}\) of his free throws. For Shaq to make exactly one of his two free throws, there are two possibilities: either Shaq makes the first and misses the second, or he misses the first and makes the second. We have to calculate the probability of both possibilities and add them together. P(Shaq makes exactly one) = P(Shaq makes first, misses second) + P(Shaq misses first, makes second) = \({0.53 * 0.47 + 0.47 * 0.53 = 0.4982}\)
03

c. Probability that Shaq makes both of his free throws and Jason misses both of his

For this scenario, we have two independent events - Shaq making both of his free throws and Jason missing both of his free throws. First, we'll find the probabilities for each player and then multiply them. P(Shaq makes both) = P(Shaq makes first) * P(Shaq makes second) = \({0.53 * 0.53 = 0.2809}\) P(Jason misses both) = P(Jason misses first) * P(Jason misses second) = \({0.2 * 0.2 = 0.04}\) Now, we multiply these probabilities to find the probability of both events happening. P(Shaq makes both, Jason misses both) = P(Shaq makes both) * P(Jason misses both) = \({0.2809 * 0.04 = 0.011236}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events Probability
Independent events in probability are scenarios where the outcome of one event does not influence the outcome of another. When dealing with independent events, the key principle is that the probability of both events occurring is the product of their individual probabilities. This concept is essential in many real-life applications, such as calculating the likelihood of multiple outcomes in games of chance or sports, like basketball free throws.
In our case, Jason Williams and Shaquille O'Neal's free throws are independent events. Their success or failure on each throw does not affect their next throw or each other's performance. To calculate the combined probability of independent events, we multiply the probability of each event occurring separately. Understanding this concept is important because it simplifies complex probability problems into more manageable calculations.
Probability Calculations
Probability calculations involve determining the likelihood of a particular outcome. The probability of an event is always between 0 and 1, where 0 represents impossibility and 1 represents certainty. In basketball, calculating probabilities can help us understand a player's consistency and expectations during a game.
For instance, to find the probability that Jason makes both free throws, we calculated \(0.8 \times 0.8\), since he has a \(80\%\) free throw success rate. On the other hand, we used a slightly more complex calculation for Shaq, considering the different outcomes where he could make exactly one free throw. The probabilities of these separate outcomes were added together, following the rules of combinatorial probability. Clarifying and practicing these calculations can boost a student's confidence in solving probability problems.
Free Throw Probability
Free throw probability is a practical application of probability in sports analytics. It sheds light on a player's skill level and what can be expected in specific game situations. A player with a higher free throw probability, like Jason Williams with an \(80\%\) success rate, is considered more reliable in scoring free throws than a player with a lower probability, such as Shaquille O'Neal's \(53\%\).
To improve understanding, it's helpful to visualize free throw attempts as independent trials, where each throw's outcome does not affect the next. This perspective helps in grasping why we multiply probabilities for successive throws for the same player and also why we treat the performances of Jason and Shaq independently, even if they are playing in the same game. Comparing different players' free throw probabilities also aids in team strategy and player development.

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