/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 You enter a chess tournament whe... [FREE SOLUTION] | 91Ó°ÊÓ

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You enter a chess tournament where your probability of winning a game is 0.3 against half the players (novices), 0.4 against a quarter of the players (experienced) and 0.5 against the remaining quarter of the players (masters). You play a game against a randomly chosen opponent. a) What is the probability of winning? b) Given that you won, what is the probability that the game was against a master?

Short Answer

Expert verified
a) 0.375; b) \( \frac{1}{3} \).

Step by step solution

01

Understanding the Problem

We are tasked with finding the probability of winning a game against a randomly selected player from a tournament where opponents have different levels of skills. Additionally, we need to find the probability that the opponent was a master given that you won.
02

Setting Up the Probabilities

You have a 30% chance (0.3) of winning against novices, 40% (0.4) against experienced players, and 50% (0.5) against masters. The fraction of players who are novices, experienced, and masters are 1/2, 1/4, and 1/4 respectively.
03

Finding the Total Probability of Winning (a)

Use the law of total probability: \[P(\text{Winning}) = P(\text{Win | Novice}) \times P(\text{Novice}) + P(\text{Win | Experienced}) \times P(\text{Experienced}) + P(\text{Win | Master}) \times P(\text{Master})\]Substituting the values:\[= (0.3 \times 0.5) + (0.4 \times 0.25) + (0.5 \times 0.25)\]\[= 0.15 + 0.1 + 0.125 = 0.375\]
04

Conditional Probability Setup for Part (b)

We need to find out \( P(\text{Master | Winning}) \). Use Bayes' theorem:\[P(\text{Master | Winning}) = \frac{P(\text{Winning | Master}) \times P(\text{Master})}{P(\text{Winning})}\]
05

Calculate the Probability in Part (b)

Using the values:\[P(\text{Winning | Master}) = 0.5\]\[P(\text{Master}) = 0.25\]\[P(\text{Winning}) = 0.375\]So:\[P(\text{Master | Winning}) = \frac{0.5 \times 0.25}{0.375} = \frac{0.125}{0.375} = \frac{1}{3}\]
06

Conclusion of Solution

The overall probability of winning a match is 0.375, and given that you won, the probability that you were playing against a master is \( \frac{1}{3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics looking at the likelihood of occurrence of different events. It provides a mathematical framework to quantify uncertain phenomena and is widely used in various fields such as science, engineering, and finance. In the chess tournament example, probability helps us evaluate the chance of winning against different types of opponents.

When we talk about probability, we often refer to events, which are specific outcomes we are interested in. The probabilities are expressed as numbers between 0 (impossible event) and 1 (certain event). Here, your chances of winning against novices, experienced players, and masters are 0.3, 0.4, and 0.5, respectively. These numbers reflect your relative likelihood of winning each game.

In practical use, probability theory helps us predict future outcomes based on existing data or conditions. For the tournament, combined probabilities provide a total probability, helping us assess broader questions like the overall winning probability when participants are chosen randomly.
Bayes' Theorem
Bayes' theorem is a cornerstone of conditional probability, allowing us to update our predictions or beliefs about an event based on new evidence. Named after the Reverend Thomas Bayes, this theorem translates our intuitive understanding of conditional scenarios into a mathematical approach.

For the chess example, Bayes' theorem helps answer: What is the likelihood that your opponent was a master given that you won the game? We use the formula:\[P(\text{B | A}) = \frac{P(\text{A | B}) \times P(\text{B})}{P(\text{A})}\]
  • \(P(\text{A | B})\) is the probability of winning given the opponent is a master, which is 0.5.
  • \(P(\text{B})\) is the prior probability of facing a master, 0.25.
  • \(P(\text{A})\) is the overall probability of winning, 0.375, obtained from the law of total probability.
Using these values, we calculate \(P(\text{Master | Winning})\), which results in \(\frac{1}{3}\) or approximately 0.333. This tells us that if you win, there is a 33.3% chance that the opponent was a master.
Law of Total Probability
The law of total probability allows us to calculate the probability of an event by considering all the possible ways it can happen, especially when dealing with partitioned events. It's vital when outcomes depend on different underlying conditions.

In the chess tournament scenario, calculating the overall probability of winning involves considering the sections of player types—novices, experienced players, and masters. Each group involves:
  • A condition: the probability of winning against that specific type.
  • A relative frequency: the fraction of the player group, which specifies their proportion.
The formula within this context is expressed as:\[P(\text{Winning}) = P(\text{Win | Novice}) \times P(\text{Novice}) + P(\text{Win | Experienced}) \times P(\text{Experienced}) + P(\text{Win | Master}) \times P(\text{Master})\]
Substituting known values provides a combined probability, 0.375, representing the chance of winning against any randomly selected player in the tournament. Using the law of total probability, we effectively integrate information across differing probabilities and conditions, allowing for a comprehensive understanding of various possible outcomes.

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