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People with O-negative blood type are universal donors, i.e. they can donate blood to individuals with any blood type. Only \(8 \%\) of people have O-negative. a) One person randomly appears to give blood. What is the probability that hel she does not have O-negative? b) Two people appear independently to give blood. What is the probability that (i) both have O-negative? (ii) at least one of them has O-negative? (iii) only one of them has O-negative? c) Eight people appear randomly to give blood. What is the probability that at least one of them has O-negative?

Short Answer

Expert verified
a) 0.92; b) i) 0.0064, ii) 0.1536, iii) 0.1472; c) 0.4868

Step by step solution

01

Understanding Probability Basics

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. If the probability of having O-negative blood type is \(8\%\), then \(P(O-) = 0.08\). To find the probability of not having O-negative blood type, we compute \(P( ext{not } O-) = 1 - P(O-)\).
02

Solving Part a

To find the probability that a random person does not have O-negative blood, we'll use the complement rule. Since \(P(O-) = 0.08\), then \(P( ext{not } O-) = 1 - 0.08 = 0.92\). So, the probability is \(0.92\).
03

Solving Part b(i)

For both individuals to have O-negative blood, we use the multiplication rule as the events are independent. Thus, \(P( ext{both } O-) = P(O-) \times P(O-) = 0.08 \times 0.08 = 0.0064\).
04

Solving Part b(ii)

The probability that at least one has O-negative is found by subtracting the probability that none have it from 1. The probability that neither has O-negative is \((1 - 0.08) \times (1 - 0.08) = 0.92 \times 0.92 = 0.8464\). Thus, \(P( ext{at least one } O-) = 1 - 0.8464 = 0.1536\).
05

Solving Part b(iii)

To find the probability that only one of two people has O-negative, we consider two mutually exclusive scenarios: either the first person has it and the second does not, or vice versa. Thus, \(P( ext{only one } O-) = (0.08 \times 0.92) + (0.92 \times 0.08) = 0.1472\).
06

Solving Part c

For eight people, the probability that at least one has O-negative is found by subtracting the probability that none have it from 1. If the probability that none of the eight have O-negative is \((0.92)^8\), then \((0.92)^8 = 0.5132\). Hence, \(P( ext{at least one } O-) = 1 - 0.5132 = 0.4868\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Universal Donor
A universal donor is someone whose blood can be used in transfusions to individuals with any blood type. This is particularly important in medical emergencies when there is no time to match the donor's blood type to the recipient's.

People with O-negative blood type are universal donors. This is because their blood lacks A, B, and Rh antigens, which are the primary triggers for immune reactions in blood transfusions. As a result, O-negative blood is considered compatible with any other type. However, only about 8% of the population has O-negative blood, why they are especially valued as donors.

Understanding who is a universal donor can be crucial in various medical contexts. It ensures anyone, regardless of blood type, can receive life-saving blood transfusions when needed.
Independent Events
In probability, independent events are events where the occurrence of one event does not affect the probability of the other.

For instance, when considering the probability of two people giving blood, each person's blood type is independent of the other. If each person has a 0.08 probability of having O-negative blood, we compute the probability for two people by multiplying these individual probabilities.
  • For both individuals to have O-negative blood, the probability is calculated as follows: \(0.08 \times 0.08 = 0.0064\).
  • Similarly, the probability that neither has O-negative blood is \((1 - 0.08) \times (1 - 0.08) = 0.92 \times 0.92 = 0.8464\).

These calculations demonstrate how outcomes are multiplied when events are independent, offering insights into more complex probability scenarios.
Complement Rule
The complement rule is a fundamental principle in probability. It helps to calculate the probability of an event occurring by using the probability of its complement, or opposite.

Simply put, the probability of an event not happening is equal to one minus the probability of it happening. For instance, if the probability of a person having O-negative blood is 0.08, then the probability of not having it is \(1 - 0.08 = 0.92\).

This rule is beneficial for quickly determining non-occurrence probabilities. For example, to find the probability that at least one person in a group of people has a specific characteristic, we can subtract the probability that no members have that characteristic from one. In parts b(ii) and c of the exercise, this rule allows for efficient calculation of complex scenarios.
Probability Calculation
Probability calculations are pivotal to predicting the likelihood of events. They rely on understanding basic principles such as multiplication rules and complements.

To solve various parts of the problem, we use these principles:
  • For b(i), the probability of both independently appearing individuals having O-negative is a simple multiply: \(0.08 \times 0.08 = 0.0064\).
  • For b(ii), the probability of at least one having O-negative is \(1 - 0.8464\), calculated using the complement of neither having it, giving \(0.1536\).
  • For b(iii), calculations for only one having O-negative involves addition of probabilities from two scenarios yielding \(0.1472\).
  • For c, involving eight individuals, we extend the complement approach: \(1 - (0.92)^8 = 0.4868\).

These calculations emphasize the practical use of probability rules in tackling problems involving multiple scenarios and highlight the incremental changes as more variables are introduced.

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