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Events \(A\) and \(B\) are given such that \(P(A)=\frac{7}{10} P(A \cup B)=\frac{9}{10}\) and \(P(A \cap B)=\frac{3}{10}\) Find a) \(P(B)\) b) \(P\left(B^{\prime} \cap A\right)\) c) \(P\left(B \cap A^{\prime}\right)\) d) \(P\left(B^{\prime} \cap A^{\prime}\right)\) e) \(P\left(B | A^{\prime}\right)\)

Short Answer

Expert verified
a) \( \frac{1}{2} \), b) \( \frac{2}{5} \), c) \( \frac{1}{5} \), d) \( \frac{1}{10} \), e) \( \frac{2}{3} \)

Step by step solution

01

Find Probability of B

We start by using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]Given values are \( P(A) = \frac{7}{10} \), \( P(A \cup B) = \frac{9}{10} \), and \( P(A \cap B) = \frac{3}{10} \). Plug these values into the equation:\[ \frac{9}{10} = \frac{7}{10} + P(B) - \frac{3}{10} \]Simplify the expression:\[ P(B) = \frac{9}{10} - \frac{7}{10} + \frac{3}{10} = \frac{5}{10} = \frac{1}{2} \]
02

Find Probability of B' intersection A

The event \( B' \cap A \) represents the probability that event \( A \) happens but not event \( B \). Use the formula:\[ P(B' \cap A) = P(A) - P(A \cap B) \]Substitute the known values:\[ P(B' \cap A) = \frac{7}{10} - \frac{3}{10} = \frac{4}{10} = \frac{2}{5} \]
03

Find Probability of B intersection A'

The event \( B \cap A' \) represents the probability that event \( B \) happens but not event \( A \). Use the formula:\[ P(B \cap A') = P(B) - P(A \cap B) \]Substitute the known values:\[ P(B \cap A') = \frac{1}{2} - \frac{3}{10} = \frac{5}{10} - \frac{3}{10} = \frac{2}{10} = \frac{1}{5} \]
04

Find Probability of B' intersection A'

The event \( B' \cap A' \) represents the probability that neither event \( A \) nor \( B \) happens. Use the complement formula:\[ P(B' \cap A') = 1 - P(A \cup B) \]Substitute the given value:\[ P(B' \cap A') = 1 - \frac{9}{10} = \frac{1}{10} \]
05

Find Conditional Probability B given A'

The conditional probability \( P(B | A') \) is the probability of \( B \) occurring given that \( A' \) has occurred, found with:\[ P(B | A') = \frac{P(B \cap A')}{P(A')} \]First find \( P(A') = 1 - P(A) = 1 - \frac{7}{10} = \frac{3}{10} \).Then substitute into the conditional probability formula:\[ P(B | A') = \frac{\frac{1}{5}}{\frac{3}{10}} = \frac{\frac{2}{10}}{\frac{3}{10}} = \frac{2}{3} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a key concept in probability that helps us determine the likelihood of an event occurring given that another event has already happened. This is represented mathematically by the formula: \[ P(B | A') = \frac{P(B \cap A')}{P(A')} \]Conditional probability is extremely useful in scenarios where outcomes are influenced by prior events. In this exercise, we calculated the probability of event \( B \) occurring given that \( A' \) (the complement of \( A \)) has occurred. Here's what each part of our calculation involved:- **Finding \( P(A') \):** We started by determining the complement of event \( A \). This is calculated as: \[ P(A') = 1 - P(A) \]- **Plugging into the formula:** Once we have \( P(A') \), we use it to find the conditional probability by dividing \( P(B \cap A') \) by \( P(A') \). This gives us the probability of \( B \) given \( A' \). Understanding how conditional probabilities work is essential for solving problems where events depend on each other. By knowing how to calculate these probabilities, you can unravel complex probability scenarios with ease.
Intersection of Events
The intersection of events is an important concept that explains how two or more events can overlap. In probability, the intersection of events \( A \) and \( B \) is represented as \( A \cap B \), and it denotes the probability that both \( A \) and \( B \) happen simultaneously.For this problem, we were explicitly given the value of \( P(A \cap B) = \frac{3}{10} \). However, understanding the calculation process can deepen your comprehension:- The probability of the intersection tells us how likely it is for both events to occur at the same time.- This is computed directly if provided, or by manipulating other given probabilities.Grasping intersection probabilities is fundamental for solving complex situations where multiple conditions should be met together. Thus, having a solid understanding of intersections helps you easily navigate through multi-event probability problems.
Complementary Probability
Complementary probability focuses on the chance of an event not happening. This is often overlooked but is crucial for a well-rounded understanding of probability. The complement of an event \( A \) is denoted as \( A' \), and it is calculated as:\[ P(A') = 1 - P(A) \]In our exercise, we found the probability of \( B' \cap A \), which means \( A \) happens and \( B \) does not. It utilizes the difference in probabilities of event \( A \) and their intersection, \( A \cap B \):\[ P(B' \cap A) = P(A) - P(A \cap B) \]Complementary probabilities are vital when you need to determine the chances of an event avoiding a certain outcome or when calculating the leftovers after considering an event occurrence. Consequently, mastering the use of complements allows for a more comprehensive analysis of any probabilistic scenario.
Union of Events
The union of events is one of the core concepts which deals with the probability that at least one of several events occurs. Symbolically, the union of events \( A \) and \( B \) is noted as \( A \cup B \), which can be interpreted as "\( A \) or \( B \) or both" happening.To find the probability of the union of two events, we use:\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]In our problem, this formula was pivotal in finding \( P(B) \), showcasing how the union involves both adding the occurrences of \( A \) and \( B \) and subtracting their intersection, to avoid overcounting the overlap.The concept of union is essential as it allows us to integrate and assess multiple events, determining the probability that at least one among them happens. This is particularly significant in scenarios where multiple events have varying impact forces, and understanding their union facilitates strategic decision making.

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Most popular questions from this chapter

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