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We throw a coin and a standard six-sided die and we record the number and the face that appear. Find a) the probability of having a number larger than 3 b) the probability that we receive a head and a 6

Short Answer

Expert verified
a) \( \frac{1}{2} \), b) \( \frac{1}{12} \)

Step by step solution

01

Understanding the Sample Space

When we throw a coin and a die, the outcomes can be represented as ordered pairs (coin, die). The coin has two possible outcomes: heads (H) and tails (T). The die has six possible outcomes: 1, 2, 3, 4, 5, and 6. Thus, our sample space consists of 2 (coin outcomes) x 6 (die outcomes) = 12 possible outcomes: (H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6).
02

Calculating Probability for a Number Larger Than 3

We need to find the probability that the die shows a number larger than 3. The numbers on the die that are larger than 3 are 4, 5, and 6. For each of these numbers, there are 2 associated outcomes (H and T), so there are 6 possible outcomes: (H, 4), (H, 5), (H, 6), (T, 4), (T, 5), (T, 6). To find this probability, divide the number of favorable outcomes (6) by the total number of outcomes (12): \[ P( ext{Number > 3}) = \frac{6}{12} = \frac{1}{2} \]
03

Calculating Probability for a Head and a 6

Next, we find the probability of getting a head and the die showing a 6. This is represented by the single outcome (H, 6). To find this probability, divide the number of favorable outcomes (1) by the total number of possible outcomes (12): \[ P( ext{Head and 6}) = \frac{1}{12} \]
04

Conclusion

By understanding and calculating these probabilities from our sample space, we find the required outcomes in each case. We have determined the specific events as fractions over the total possible outcomes. P(number > 3) is \( \frac{1}{2} \) and P(head and 6) is \( \frac{1}{12} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
When dealing with probability, understanding the sample space is fundamental. The sample space is the set of all possible outcomes of a given experiment. In the scenario where we throw a coin and roll a six-sided die, we can think of the outcomes as combinations or pairs.
The pairs are formed from the results of each separate event, in this case, the coin toss and the die roll.
Here's how to think about it:- The coin has two outcomes: heads \( (H) \) or tails \( (T) \).
- The die has six possible outcomes: 1 through 6.
Combining these, the sample space includes every possible combination of these results. Mathematically, this is 2 coin outcomes multiplied by 6 die outcomes, resulting in 12 total possibilities. List the sample space like: (H, 1), (H, 2), ..., (T, 6). By clearly laying out the sample space, we make it easier to identify the desirable outcomes for various events.
Favorable Outcomes
Once you understand the sample space, determining the favorable outcomes becomes straightforward. Favorable outcomes are the specific outcomes that meet the criteria of an event we're interested in.
Let's explore the examples given: 1. **A number larger than 3:**
The numbers that satisfy the condition (larger than 3) on a die are 4, 5, and 6. Since each number can be paired with either heads or tails, favorable outcomes are: (H, 4), (H, 5), (H, 6), (T, 4), (T, 5), and (T, 6). That's a total of 6 favorable combinations.
This set of favorable outcomes helps calculate probabilities by focusing only on the events that interest us. 2. **Receiving a head and a 6:**
This is a more specific event. Here, we only want the exact pair: (H, 6). Thus, we have just 1 favorable outcome.
By identifying the favorable outcomes, you translate a real-world scenario into mathematical terms that allow you to calculate probability. It is about narrowing down the wide range of possibilities to only those which satisfy the condition or event.
Events
In probability, an event is a specific outcome or a set of outcomes from the sample space. When considering events, you often focus on what you are trying to determine the probability of.
Let's look at the events in our example. 1. **Event of a number larger than 3:**
We are actually talking about a defined set of outcomes from the sample space where the die shows 4, 5, or 6, regardless of the coin result.
This event is significant as it adjusts our view from all possible outcomes (sample space) to relevant ones for our purpose. 2. **Event of getting a head and a 6:**
This event is much narrower. It involves only one outcome from the sample space
— when both the coin shows heads and the die shows a 6.
When analyzing probabilities, defining the events properly is crucial. It allows keeping track of only the outcomes you need, linking between the abstract world of numbers and the real-world situations being modeled. This method of thinking about events is central to all probability problems and helps organize the information clearly, making complex problems easier to solve.

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Most popular questions from this chapter

An urn contains six red balls and two blue ones. We make two draws and each time we put the ball back after marking its colour. a) What is the probability that at least one of the balls is red? b) Given that at least one is red, what is the probability that the second one is red? c) Given that at least one is red, what is the probability that the second one is blue?

Coloured balls are placed in three boxes as follows: $$\begin{array}{|l|c|c|c|}\hline &&\text { Box } \\\\\hline & 1 & 2 & 3 \\\\\hline \text { Green } & 4 & 8 & 6 \\\\\hline \text { Red } & 6 & 2 & 8 \\\\\hline \text { Blue } & 10 & 6 & 6 \\\\\hline\end{array}$$ A box is selected at random from which a ball is randomly drawn. a) What is the probability that the ball is green? b) Given that the ball is green, what is the probability that it was drawn from box \(2 ?\)

We throw a coin and a standard six-sided die and we record the number and the face that appear in that order. For example, \((5, h)\) represents a 5 on the die and a head on the coin. Find the sample space.

Car insurance companies categorize drivers as high risk, medium risk and low risk. (For your information only: Teens and seniors are considered high risk!) \(20 \%\) of the drivers insured by 'First Insurance'are high risk, and \(50 \%\) are medium risk driver. The company's actuaries estimate the chance that each class of driver will have at least one accident in the coming 12 months as follows: High risk \(6 \%\) medium \(3 \%\) and low \(1 \%\) a) Find the probability that a randomly chosen driver is a high-risk driver that will have an accident in a 12 -month period. b) Find the probability that a randomly chosen driver insured by this company will have an accident in the next 12 months. c) A customer has a claim for an accident. What is the probability that he/she is a high-risk driver?

Cars leaving the highway can take a right turn (R), left turn \((L),\) or go straight \((S)\) You are collecting data on traffic patterns at this intersection and you group your observations by taking four cars at a time every 5 minutes. a) List a few outcomes in your sample space U. How many are there? b) List the outcomes in the event that all cars go in the same direction. c) List the outcomes that only two cars turn right. d) List the outcomes that only two cars go in the same direction.

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