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An urn contains six red balls and two blue ones. We make two draws and each time we put the ball back after marking its colour. a) What is the probability that at least one of the balls is red? b) Given that at least one is red, what is the probability that the second one is red? c) Given that at least one is red, what is the probability that the second one is blue?

Short Answer

Expert verified
a) \( \frac{15}{16} \) b) \( \frac{3}{5} \) c) \( \frac{2}{5} \)

Step by step solution

01

Define Probability Events

Let the event of drawing a red ball be \( R \) and a blue ball be \( B \). Since balls are replaced, each draw is independent.
02

Calculate Probability of At Least One Red Ball

Calculate the probability of not drawing any red balls in both draws: \( P(BB) = \left( \frac{2}{8} \right) \times \left( \frac{2}{8} \right) = \frac{1}{16} \). Therefore, the probability of at least one red ball, \( P(RR, RB, BR) = 1 - \frac{1}{16} = \frac{15}{16} \).
03

Calculate the Probability of Drawing Red Second Given At Least One Red

Given at least one red, consider outcomes \( RR, RB, BR \). Probabilities are: \( P(RR) = \left( \frac{6}{8} \right) \times \left( \frac{6}{8} \right) = \frac{9}{16} \), \( P(RB) = \left( \frac{6}{8} \right) \times \left( \frac{2}{8} \right) = \frac{3}{16} \), \( P(BR) = \left( \frac{2}{8} \right) \times \left( \frac{6}{8} \right) = \frac{3}{16} \). The conditional probability that the second is red is \( P(R_2 | R_1) = \frac{P(RR)}{P(RR, RB, BR)} = \frac{9/16}{15/16} = \frac{3}{5} \).
04

Calculate the Probability of Drawing Blue Second Given at Least One Red

Similarly, the probability that the second ball is blue given at least one red is \( P(B_2 | R_1) = \frac{P(RB + BR)}{P(RR, RB, BR)} = \frac{(3/16 + 3/16)}{15/16} = \frac{2}{5} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability helps us understand the likelihood of an event happening based on another event that has already occurred. This concept is crucial in many real-life situations, including determining outcomes in games or predicting future occurrences from a certain point of view.
For example, let's consider part b of our problem: Given that at least one of the balls is red, we want to find the probability that the second ball is red. This kind of situation is a typical scenario for conditional probability.
To compute conditional probability, we use the formula:
  • \( P(A | B) = \frac{P(A \cap B)}{P(B)} \)
where:
  • \( P(A | B) \) is the probability of event A occurring given that B is true.
  • \( P(A \cap B) \) is the probability of both A and B occurring.
  • \( P(B) \) is the probability that event B occurs.
In our problem, event A is drawing a red ball on the second draw, and event B is at least one red ball has been drawn. By focusing on these probabilities, we can determine outcomes more precisely
Independent Events
If events are independent, the occurrence of one does not affect the other. This understanding is significant, especially in complex systems where multiple factors could influence results.
In our problem, we consider each draw from the urn to be independent since the ball is replaced after each draw. This replacement ensures that each draw is unaffected by previous draws. Therefore, the probability of drawing a red or blue ball remains constant for each draw.
When calculating probabilities involving independent events, we can multiply their individual probabilities. For instance, the probability of drawing a blue ball in both draws is calculated as:
  • \( P(BB) = P(B) \times P(B) \)
  • \( = \left( \frac{2}{8} \right) \times \left( \frac{2}{8} \right) = \frac{1}{16} \)
This reinforces the idea that independent events hold constant probabilities, highlighting the impact of independence in probability theory.
Probability Theory
Probability theory is the mathematical framework for analyzing random events. It's about quantifying uncertainty and making informed predictions based on empirical data and theoretical models. This field finds use in various disciplines including finance, science, and everyday decision-making.
In the given exercise, probability theory guides us in calculating various outcomes of drawing balls from an urn. The calculations involve determining possible outcomes and their probabilities.
Here are a few key components of probability theory reflected in the exercise:
  • Sample Space: This is the set of all possible outcomes, such as drawing combinations of red and blue balls from the urn.
  • Event: Any subset of the sample space, like drawing a red ball.
  • Probability: Measures how likely an event is to occur, such as the chances of drawing at least one red ball.
By applying these core ideas, probability theory provides a structured approach to evaluate and interpret real-world scenarios involving chance.

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Most popular questions from this chapter

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