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Nigel is a student at Wigley College and lives in the dorms. To avoid coming late to his morning classes he usually sets his alarm clock. \(85 \%\) of the time he manages to remember and set his alarm. When the alarm goes off he manages to go to his morning classes \(90 \%\) of the time. If the alarm is not set, he still manages to get up and go to class on \(60 \%\) of the days. a) What percentage of the days does he manage to get to his morning classes? b) He made it to class one day. What is the chance that he did that without having set the alarm?

Short Answer

Expert verified
Nigel gets to classes on 85.5% of the days. There's a 10.5% chance he made it without setting the alarm.

Step by step solution

01

Define Events and Probabilities

Let event \(A\) represent Nigel setting the alarm, and \(B\) represent him getting to class. We know that \(P(A) = 0.85\) and \(P(eg A) = 0.15\) (not setting the alarm). Given that the alarm is set and goes off, \(P(B|A) = 0.90\); if the alarm is not set, \(P(B|eg A) = 0.60\). Our task is to find the total probability of him getting to class, \(P(B)\).
02

Use the Law of Total Probability

We use the law of total probability to calculate \(P(B)\): \[ P(B) = P(B|A)P(A) + P(B|eg A)P(eg A) \]Substitute the known probabilities: \[ P(B) = (0.90)(0.85) + (0.60)(0.15) \]
03

Calculate \(P(B)\)

Calculate each term:\(0.90 \times 0.85 = 0.765\)\(0.60 \times 0.15 = 0.09\)Add the results to find \(P(B)\):\[ P(B) = 0.765 + 0.09 = 0.855 \]
04

Interpret Result for Part (a)

Nigel manages to get to his morning classes on \(85.5\%\) of the days.
05

Use Bayes' Theorem for Part (b)

To find the probability he made it to class without setting the alarm \(P(eg A|B)\), use Bayes' theorem:\[ P(eg A|B) = \frac{P(B|eg A)P(eg A)}{P(B)} \]Substitute the known values:\[ P(eg A|B) = \frac{0.60 \times 0.15}{0.855} \]
06

Calculate \(P(\neg A|B)\)

Calculate the numerator first:\(0.60 \times 0.15 = 0.09\)Calculate the division:\[ P(eg A|B) = \frac{0.09}{0.855} \approx 0.105 \]
07

Interpret Result for Part (b)

The probability that Nigel made it to class without setting the alarm is approximately \(10.5\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Total Probability
The Law of Total Probability is a fundamental concept used to determine the overall likelihood of an event by considering all possible ways that event can occur. We do this by breaking down the event into scenarios, then weighing each scenario by its probability. This method gives a comprehensive view of the event's total probability.
In Nigel's case, the event in question is whether he manages to get to his morning classes. Since this can happen in two ways—either by setting his alarm or not setting it—the Law of Total Probability helps integrate these possibilities. Here's how:
  • If the alarm is set, Nigel has a 90% chance of getting to class.
  • If the alarm is not set, he has a 60% chance of still making it.
With these probabilities and knowing that the alarm is set 85% of the time, we apply the law:
\[ P(B) = P(B|A)P(A) + P(B| eg A)P( eg A) \]
By substituting the values we've:
  • \(0.90 imes 0.85 = 0.765\) for when the alarm is set
  • \(0.60 imes 0.15 = 0.09\) for when the alarm is not set
Adding these gives us 0.855, or 85.5%. This means Nigel gets to class on 85.5% of the days, combining both scenarios.
Bayes' Theorem
Bayes' Theorem is a powerful rule for determining the likelihood of an underlying cause when given the outcome. Essentially, it's about revising the probability of a condition based on new evidence. Think of it as flipping the conditional probability around. It’s especially useful for situations like Nigel’s, where we want to know the reverse probability of an event based on the result.
In part b of Nigel's situation, we know he made it to class and we seek to understand the likelihood he didn't set his alarm. Here’s how Bayes' Theorem fits in:
  • We want \( P( eg A | B) \), the probability he didn't set the alarm given he arrived in class.
  • We use Bayes' Theorem to calculate it: \[ P( eg A | B) = \frac{P(B | eg A)P( eg A)}{P(B)} \]
By inserting known values:
  • \( P(B | eg A) = 0.60 \)
  • \( P( eg A) = 0.15 \)
  • \( P(B) = 0.855 \)
The resulting calculation shows that, after solving, the chance Nigel made it to class without setting the alarm is approximately 10.5%. Bayes' theorem provided a methodical way to understand this probability based on outcomes.
Conditional Probability
Conditional probability is all about figuring out the chance of an event happening, given that another event has already occurred. It's like saying, "Under these circumstances, how likely is this to happen?" This is a straightforward but deeply insightful part of probability theory.
In our scenario with Nigel, conditional probability helps us determine the chances of him going to class based on whether or not he sets his alarm. We use terms like \( P(B|A) \) and \( P(B| eg A) \), which stand for the probability of him getting to class given the alarm is set, and not set, respectively.
  • If the alarm is set, then this probability is 90%. This means, knowing he's set the alarm, there's a high chance he makes it to class.
  • If the alarm is not set, then this probability is 60%. This lowers since waking up without the alarm is more challenging.
These probabilities are conditional because they depend on the occurrence of a certain precursor event—setting the alarm or not. This framework helps detail the situation and calculate more sophisticated outcomes using the Law of Total Probability or Bayes' Theorem, making it foundational in grasping more complex probability concepts.

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