/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 When Olympic athletes are tested... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When Olympic athletes are tested for illegal drug use (doping), the results of a single test are used to ban the athlete from competition. In an experiment on 1000 athletes, 100 were using the testosterone drug. During the medical examination, the available test would positively identify \(50 \%\) of the users. It would also falsely identify \(9 \%\) of the non-users as users. If an athlete tests positive, what is the probability that he/she is really doping?

Short Answer

Expert verified
The probability is approximately 38.17%.

Step by step solution

01

Understand the Problem

We have three main groups of athletes: real dopers, non-dopers who test positive, and those who test negative. We need to calculate the probability that an athlete is actually doping when their test result is positive.
02

Identify the Relevant Numbers

From the problem, we have a total of 1000 athletes. 100 athletes are dopers (users), 900 are non-dopers. The test identifies 50% of dopers as positive, and 9% of non-dopers as positive.
03

Calculate True Positives

We apply the test detection rate (50%) to the dopers. Out of 100 dopers, the test correctly identifies 50 athletes as doping: \(50\% \times 100 = 50\) true positives.
04

Calculate False Positives

Now, apply the false positive rate (9%) to the non-dopers. Out of 900 non-dopers, the test falsely identifies 81 athletes as doping: \(9\% \times 900 = 81\) false positives.
05

Find Total Positives

Combine true positives with false positives to get the total number of athletes who tested positive: \(50 + 81 = 131\) athletes.
06

Calculate the Probability

Use Bayes' theorem formula to calculate the probability of actual doping when a test is positive. This is the number of true positives divided by the total number of positive results: \( \frac{50}{131} \approx 0.3817 \).
07

Present the Final Answer

The probability that an athlete who tests positive is actually doping is approximately 38.17%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a mathematical concept that helps us quantify the likelihood of certain events happening. It ranges from 0 to 1, with 0 meaning the event is impossible and 1 meaning it is certain. In real-life scenarios, such as medical tests or sports doping tests, probability is used to assess risks and outcomes.
For instance, in the scenario of doping tests, probability helps us understand how likely it is that a positive test result truly means an athlete is doping. We use Bayes' theorem, which involves conditional probabilities, to calculate this. Bayes' theorem allows us to reverse or update initial probabilities with new evidence. In this task, it helped calculate the probability of actual doping given a positive test result.
False Positive
A false positive is an error that occurs when a test incorrectly indicates the presence of a condition, such as doping, when it is not present. In our doping test example, 9% of non-dopers are falsely identified as users.
This happens in many types of tests, and it is important to acknowledge because it can lead to incorrect conclusions. Consider the consequence of falsely accusing a non-doper with this error. False positives reduce the accuracy of a test and can have serious implications.
To determine the effect of false positives, we calculate the number of non-dopers falsely identified as users. With 900 non-dopers, the device yields 81 false positives: \(9\% \times 900 = 81\). Understanding this concept is crucial for evaluating and improving any testing process.
True Positive
True positives occur when a test correctly identifies a condition, like doping, in individuals who actually have it. They demonstrate the effectiveness of a test.
In the context of our doping test, true positives refer to dopers correctly identified by the test. The test identifies 50% of dopers, which means for 100 dopers, it has a true positive occurrence for 50 athletes: \(50\% \times 100 = 50\).
Knowing the true positive rate helps in evaluating the sensitivity of the test, which is its ability to correctly detect those with the condition. The higher the true positive rate, the more reliable the test is for positively identifying a condition. This metric is essential while making decisions based on test results.
Doping Tests
Doping tests are used to detect the presence of banned substances in athletes. Their goal is to ensure fairness and integrity in sports. However, like all tests, they are subject to errors.
In the test described, multiple outcomes are possible: true positives, false positives, true negatives, and false negatives. Each of these affects the overall reliability and accuracy of the test.
Understanding the underlying probabilities involved in a doping test, including both true and false positives, is crucial. It helps authorities make informed decisions about whether a positive result genuinely indicates substance use. Additionally, improving the test's accuracy can reduce errors, thereby increasing the confidence in test results and ensuring fair play.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At a small airport, if an aircraft is present at \(10 \mathrm{km}\) distance from the runway, radar detects it and generates an alarm signal \(99 \%\) of the time. If an aircraft is not present, the radar generates a (false) alarm, with probability 0.10. We assume that an aircraft is present with probability 0.05. a) What is the probability that the radar gives an alarm signal? b) Given that there is no alarm signal, what is the probability that an aircraft is there?

A construction company is bidding on three projects: \(B_{1}, B_{2}\) and \(B_{3}\). From previous experience they have the following probabilities of winning the bids: \(P\left(B_{1}\right)=0.22, P\left(B_{2}\right)=0.25\) and \(P\left(B_{3}\right)=0.28 .\) Winning the bids is not independent one from another. The joint probabilities are given below. $$\begin{array}{|c|c|c|c|} \hline & B_{1} & B_{2} & B_{3} \\ \hline B_{1} & & 0.11 & 0.05 \\ \hline B_{2} & 0.11 & & 0.07 \\ \hline B_{3} & 0.05 & 0.07 & \\ \hline \end{array}$$ Also, \(P\left(B_{1} \cap B_{2} \cap B_{3}\right)=0.01 .\) Find the following probabilities: a) \(P\left(B_{1} \cup B_{2}\right)\) b) \(P\left(B^{\prime}_{1} \cap B_{2}^{\prime}\right)\) c) \(P\left(B^{\prime}, \cap B_{2}^{\prime}\right) \cup B_{3}\) d) \(P\left(B^{\prime}_{1} \cap B_{2}^{\prime} \cap B_{3}\right)\) e) \(P\left(B_{2} \cap B_{3} | B_{1}\right)\) \(f) P\left(B_{2} \cup B_{3} | B_{1}\right)\)

Driving tests in a certain city are relatively easy to pass the first time you take them. After going through training, the percentage of new drivers passing the test the first time is \(80 \% .\) If a driver fails the first test, there is chance of passing it on a second harder test, two weeks later. \(50 \%\) of the second-chance drivers pass the test. If the second test is unsuccessful, a third attempt, a week later, is given and \(30 \%\) of the participants pass it. Otherwise, the driver has to retrain and take the test after 1 year. a) Find the probability that a randomly chosen new driver will pass the test without having to wait one year. b) Find the probability that a randomly chosen new driver that passed the test did so on the second attempt.

In Vienna, conventional wisdom has it that in February days are snowy or fine. \(80 \%\) of the time a fine day follows a fine day. \(40 \%\) of the time a snowy day is followed by a fine day. The forecast for the first of February to be a fine day is 0.75 a) Find the probability that 2 nd February is fine. b) Given that 2 nd February turns out to be snowy, what is the probability that the 1 st of February was a fine day?

You are given two fair dice to roll in an experiment. a) Your first task is to report the numbers you observe. (i) What is the sample space of your experiment? (ii) What is the probability that the two numbers are the same? (iii) What is the probability that the two numbers differ by \(2 ?\) (iv) What is the probability that the two numbers are not the same? b) In a second stage, your task is to report the sum of the numbers that appear. (i) What is the probability that the sum is \(1 ?\) (ii) What is the probability that the sum is \(9 ?\) (iii) What is the probability that the sum is \(8 ?\) \(13 ?\) (iv) What is the probability that the sum is

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.