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In Problems 1-20, determine the Laplace transform of the given function using Table 7.1 on page 356 and the properties of the transform given in Table 7.2. [Hint: In Problems 12-20, use an appropriate trigonometric identity.]

e-tcos3t+e6t-1.

Short Answer

Expert verified

The Laplace transform for the given equation iss+1(s+1)2+9+1s-6-1sfors>6.

Step by step solution

01

Definition of Laplace transform

  • The integral transform of a given derivative function with real variable t into a complex function with variable s is known as the Laplace transform.
  • Let f(t) be supplied for t(0), and assume that the function meets certain constraints that will be presented subsequently.
  • The Laplace transform formula defines the Laplace transform of f(t), which is indicated by Lftor F(s).
02

Determine the Laplace transform for the given equation

Given that e-tcos3t+e6t-1.

Find the Laplace transform of the given function e-tcos3t+e6t-1using the Laplace formula

Laf1+bf2=aLf1+bLf2, Leatcosbt=s-a(s-a)2+b2, L{1}=1s, Ltn=n!sn+1and Leat=1s-aas follows:

Le-tcos3t+e6t-1=Le-tcos3t+Le6t-L{1}=s-(-1)(s-(-1))2+32+1s-6-1s=s+1(s+1)2+9+1s-6-1sfors>6

Therefore, the Laplace transform for the given equation is

s+1(s+1)2+9+1s-6-1sfors>6

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