/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7.3 - 4E In Problems 1-20, determine the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 1-20, determine the Laplace transform of the given function using Table 7.1 on page 356 and the properties of the transform given in Table 7.2. [Hint: In Problems 12-20, use an appropriate trigonometric identity.]


3t4-2t2+1

Short Answer

Expert verified

The Laplace transform for the given equation is72s5-4s3+1sfors>0.

Step by step solution

01

Definition of Laplace transform

  • The integral transform of a given derivative function with real variable t into a complex function with variable s is known as the Laplace transform.
  • Let f(t) be supplied for t(0), and assume that the function meets certain constraints that will be presented subsequently.
  • The Laplace transform formula defines the Laplace transform of f(t), which is indicated by Lftor F(s).
02

Determine the Laplace transform for the given equation

Given that,3t4-2t2+1

Find the Laplace transform of the given function 3t4-2t2+1using the Laplace formula

localid="1662716857805" Laf1+bf2=aLf1+bLf2, Ltn=n!sn+1and L1=1sas follows:

L3t4-2t2+1=3Lt4-2Lt2+L{1}=3×4!s4+1-2×2!s2+1+1s=3×24s5-2×2s3+1s=72s5-4s3+1sfors>0

Therefore, the Laplace transform for the given equation is72s5-4s3+1sfors>0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.