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Find the Laplace transform off(t)=∫0t(t−v)e3vdv

Short Answer

Expert verified

Laplace transformation of∫0tevsin(t−v)dv is 1s2(s−3).

Step by step solution

01

Assuming g(t) and h(t).

Let

g(t)=th(t)=e3t

02

Getting the values of G(s) and H(s).

Now,

G(s)=L{g(t)}(s)=1s2

H(s)=L{h(t)}(s)=1s−3

03

Step 3: Now, On applying the Convolution Theorem

We get,

L{f(t)}(s)=L{∫0t(t−v)e3vdv}(s)=L{∫0tg(t−v)h(v)dv}

L{f(t)}(s)=L{g(t)∗h(t)}(s)=G(s)⋅H(s)=1s2(s−3)

Therefore,

L{f(t)}(s)=1s2(s−3)

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