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In Problems 11–20, determine the partial fraction expansion for the given rational function.−2s2−3s−2s(s+1)2

Short Answer

Expert verified

The partial fraction expansion for the given ration function is 1(s+1)2−2s.

Step by step solution

01

Definition of partial fraction expansion

  • The partial fraction expansion of a rational fraction (that is, a fraction with both a polynomial numerator and a polynomial denominator) is an algebraic procedure that involves expressing the fraction as a sum of a polynomial plus one or more fractions with a simpler denominator.
  • The partial fraction decomposition is important because it gives methods for a variety of rational function computations, such as explicit antiderivative computations, Taylor series expansions, inverse Z-transforms, and inverse Laplace transforms.
02

Determine the partial fraction expansion for the given rational function

The given rational function is −2s2−3s−2s(s+1)2.

Rewrite −2s2−3s−2s(s+1)2 as a sum of partial fractions as:

−2s2−3s−2s(s+1)2=As+B(s+1)+C(s+1)2

Multiply both sides by the LCD (s+1)(s−2)as follows:

−2s2−3s−2=As+12+Bs(s+1)+Cs−2s2−3s−2=As2+2As+A+Bs2+Bs+Cs

Group like terms and factor as:

−2s2−3s−2=(As2+Bs2)+(2As+Bs+Cs)+A−2s2−3s−2=(A+B)s2+(2A+B+C)s+A

Compare coefficients of s2, s and constant term as follows:

A+B=−22A+B+C=−3A=−2

Find the constants as:

A=−2,B=0,C=1

Substitute the value of constants into −2s2−3s−2s(s+1)2=As+B(s+1)+C(s+1)2 as:

−2s2−3s−2s(s+1)2=−2s+0(s+1)+1(s+1)2−2s2−3s−2s(s+1)2=1(s+1)2−2s

Therefore, the partial fraction expansion for the given ration function is 1(s+1)2−2s.

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