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Question: In Problems 15-24, solve for Ys, the Laplace transform of the solution yt to the given initial value problem.

y''+6y=t2-1;y0=0,y'0=-1

Short Answer

Expert verified

The Initial value for y''+6y=t2-1isY=-s3-s2+2s3s2+6

Step by step solution

01

The Laplace Transform

  • The Laplace transform is a strong integral transform used in mathematics to convert a function from the time domain to the s-domain.
  • In some circumstances, the Laplace transform can be utilized to solve linear differential equations with given beginning conditions.
  • Fs=∫0∞f(t)e-stt'
02

Determine the Laplace transform

Define Lys=Ys

Using the properties listed below, take the Laplace transform of the equation.

Ly''s=s2Lys-sy0-y'0Ltns=n!sn+1

L1s=1sLy''+6Ly=Lt2-L1

Substitute the properties into the equation

s2Y-sy0-y'0+6Y=2!s3-1s

Substitute the initial conditions

y0=0andy'0=-1

s2Y+1+6Y=2s3-1s

Isolate the Y variable as:

Ys2+6=2s3-1s-1=-s3-s2+2s3

Y=-s3-s2+2s3s2+6

Therefore, the initial value fory''+6y=t2-1 isY=-s3-s2+2s3s2+6

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