/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 15E In Problems 15-24, solve for Ys ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 15-24, solve for Ys , the Laplace transform of the solution ytto the given initial value problem.

y''-3y'+2y=cost;y0=0,y'0=-1

Short Answer

Expert verified

The Initial value fory''-3y'+2y=costisY(s)=-s2+s-1s2+1s-1s-2

Step by step solution

01

Determine the Laplace Transform

  • The Laplace transform is a strong integral transform used in mathematics to convert a function from the time domain to the s-domain.
  • In some circumstances, the Laplace transform can be utilized to solve linear differential equations with given beginning conditions.
  • Fs=∫0∞f(t)e-stt'
02

Determine the Laplace transform

Applying the Laplace transform and using its linearity as follows:

Ly''-3y'+2y=LcostLy''-3Ly'+2Ly=ss2+1

Solve for the transfer function as:

s2Ys-sy0-y'0-3sYs-y0+2Ys=ss2+1s2Ys+1-3sYs+2Ys=ss2+1s2-3s+2Ys=ss2+1-1Ys=-s2+s-1s2-3s+2s2+1

Since s2-3s+2=(s-1)(s-2)

Y(s)=-s2+s-1s2+1(s-1)(s-2)

Therefore, the Initial value fory''-3y'+2y=costisY(s)=-s2+s-1s2+1s-1s-2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.